Senior 1 Chemistry 10 Questions All Ask for Explanations I wrote the answers I calculated at the bac

1) Solution 1: Let the quantities of FeO and Fe2O3 be xmol and ymol respectively. According to the ratio of the amount of iron to oxygen in the amount of matter, it is 4:5

Yes: (x+2y):(x+3y)=4:5 x=2y, the ratio of the quantities of FeO and Fe2O3 is 2:1, then the ratio of the quantities of Fe2+ to Fe3+ is 1:1

Solution 2: The ratio of the amount of iron to oxygen is 4:5, which can be written as Fe4O5, and the average valency of Fe is +5 2, according to the cross method, the ratio of the amount of Fe2+ and Fe3+ can be calculated as 1:1.

2) Solution: Let the quantities of FeO and Fe2O3 be xmol and ymol respectively. According to the ratio of the amount of Fe2+ to Fe3+ substance is 1:

2, then there is x:2y=1:2, x=y, and the mass fraction of iron is:

n(fe2o3)=m/m=480g÷160g/mol=3mol。The amount of iron is 6mol, and according to the ratio of Fe2+ to Fe3+ is 1:2, then Fe2+ in the catalyst is 2mol and Fe3+ is 4mol.

2Fe2O3 + C = High Temperature = 4FeO + CO2

1mol 4mol

n= 2mol

m(c)=nm=

1) Yes, the ratio of FeO to Fe2O3 is 2:1.

2) The ratio of FeO to Fe2O3 is 1:1

3）6g.The ratio of Fe2O3 to FeO coefficient in the reaction is 2:1, and the ratio of the amount of the two substances that need to be obtained is 1. 1. The raw material Fe2O3 is 3mol, so it needs to consume 1molSo the need for c is.

Question 1: Chlorine gas is reduced in A, so only a reducing agent can be added to achieve conversion, and the BC option is oxidized (the valency of the element increases) D does not involve redox reactions.

Question 2: Comparison, only the chlorine valence in chlorine gas is increased and decreased in the reactants, only b is not.

Question 3: A, water as a reducing agent B, water as an oxidant C, water as an oxidant D is not Sodium peroxide is both an oxidant and a reducing agent.

Question 4: The nitrogen element in ammonia is 4 and the nitrogen element in ammonia is reduced to 6, and the ratio is 2:3 d

1) The reaction that requires the addition of a reducing agent refers to the reduction reaction carried out by the reaction, and the substance is an oxidizing agent in the reaction.

2) The disproportionation reaction refers to the reaction that the oxidant and the reducing agent are the same substance and the same element.

3) Na+H2O==NaOH+H2 (the valency of hydrogen element changes, and there is hydrogen element in the water, so it is not possible).

Na2O2+H2O==NaOH+O2 (the change in the valency of oxygen refers to the oxygen of Na2O2, so it works).

There is no answer to this question.

4) 6NO(N:+2)+4NH3 (N:-3)=5N2+6H2O6NO(N:+2---0) The valency decreases, and the reduction reaction occurs, and it is oxidized.

The valency of 4NH3 (n:-3) is increased, oxidation occurs, and it is reduced.

1. Only the valency of Cl in A is reduced, the valency of the elements in B, C and D is increased, and the reactants are reduced by the reducing agent, and the valency is reduced.

2. Disproportionation reaction means that the reaction occurs on the same element of the same substance, and some of this element undergoes oxidation reaction, and the valency increases, and some of it undergoes reduction reaction, and the valency decreases. In other words, an element itself undergoes a redox reaction, while the valency of the rest of the substances does not change. The answer is B

3. The O in the water in a is oxidized, and the water is the reducing agent; H in water in b is reduced, and water is an oxidizing agent; Part of the hydrogen in the water in C becomes H2 and is reduced, and the water is the oxidizing agent; D reaction to produce O2, is the disproportionation reaction of Na2O2 itself, water has no change in valency, so it is neither an oxidant nor a reducing agent, the answer is D

4. The n in the product is 0 valence, and the n in no is +2, which is an oxidant in the reaction, and itself is reduced to 0 valence; N in NH3 is -3 and is a reducing agent in the reaction and itself is oxidized to a 0 valence state. So oxidized n:reduced n=4:

6=2:3, answer D

I'll tell you that your questions are all about the rise and fall of the valence The first question is to add a reducing agent, the reactant should be oxidized, and the valency is increased, and there is only a The second question is the disproportionation reaction, which is an element of the reactant, and the valency is both increased and decreased. The third question is neither oxidized nor reduced That is, the valency of the two elements of water has not changed Question 4 The oxidized valency increases and the reduced valency decreases Tell you a smooth slip of the way Up and down The loss of oxygen is also down The rise and fall is the valency The gain and loss is the electron Redox reduction You can take a look at it again I have something to do If you don't understand, you can find me q554344882

In the first question, the valency of b zn is increased, and an oxidation reaction occurs, so an oxidant needs to be added, so b is incorrect.

The first question, if you want to add a reducing agent, that is, it shows oxidation, then choose A!

A is CO2 + SO2 + NO2, NO2 has strong oxidation and can undergo redox reaction to form SO42

In B, CO2+SO2+NO, SO2+NOs do not react, SO42- cannot be generated, and do not react with barium chloride solution.

C is CO2 + SO2 + Cl2, in the solution Cl2 can oxidize SO2 into SO42 D is CO2 + SO2 + NH3, in the solution NH3 (alkaline gas) and SO2 + CO2 can react to form the corresponding (NH4) 2SO3, (NH4) 2CO3 two salts, and react with barium chloride solution to form BASO3 BACO3, these two precipitates.

There is no such thing as HN3) The mass ratio is n(NH3)*17 : N(CH4)*16

Hydrocarbons consume an O for 2 H and 2 O's for a CIn the case of equal mass, the greater the proportion of H, the more oxygen is consumed, so A is selected.

Sodium metal reacts quickly with acetic acid, ethanol slowly, and benzene does not.

Bromine water is soluble in ethanol and benzene and therefore cannot be distinguished.

Sodium carbonate reacts with acetic acid, ethanol is miscible with it, and benzene is immiscible and stratified.

Litmus turns red when exposed to acetic acid, ethanol is miscible, benzene is immiscible and stratified.

1, Methane, 2, Benzene, ethylene (addition reaction), 3, Ethanol, acetic acid (containing active hydrogen) 4, Acetic acid (acid-base neutralization reaction).

3.Methane.

Ethylene, ethanol, acetic acid, acetic acid.

1.According to the chemical equation: CH4 2 O2 16G 2molC2H6 7 2 O2 30G 7 2molC2H4 3 O2 28G 3molC6H6 15 2 O2 78g 15 2molAssuming that the mass is 1G, then the corresponding CH4 needs 1 8mol oxygen, C2H6 requires 7 60mol oxygen, C2H4 requires 3 28mol oxygen, and C6H6 requires 15 156mol oxygen, then it can be seen that the same mass of C6H6 requires the least oxygen.

Acids can react with alkali and carbonic acid, and can test litmus to change color; Benzene extraction.

3.The main component of natural gas is: methane.

Under certain conditions, ethylene can react with hydrogen (addition reaction) and acetic acid can react with sodium metal to form hydrogen.

The salt that can react with sodium hydroxide solution is: acetic acid.