Circuit analysis: What is the reason for the dimming of the electric light, and the power is reduced

According to your tips; The "dimming of the bulb" must be caused by a voltage drop. Because the bulb does not change, only a drop in voltage can cause the bulb to dim.

Electrical power is obtained from voltage x current. Because the voltage drops, the power becomes smaller.

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We often use a lot of electrical appliances in our lives, such as mobile phone chargers and so on, and many of them are low-power electrical appliancesThis is not much pressure on the circuit, but when we use high-power appliances, the lamp will suddenly dim, in fact, the current given is insufficient, resulting in a decrease in the brightness of the bulb, let's take a look at the analysis.

Mainly because of the high-power electrical appliances it needs a lot of current, but the actual given is very small, ** insufficient, so the lights will be dimmed, in life high-power electrical appliances are somewhat dangerous, use with caution.

When using high-power electrical appliances, the current suddenly increases, causing the voltage to drop, and the lamp will suddenly dim.

That's because when using high-power appliances, the voltage of the lamp does not reach its rated voltage, so it will be dimmed.

1. If the light is dimmed when the voltage you give is the same, then the current in the lamp becomes smaller.

2. If you change the voltage at both ends of the lamp to dim the lamp, it means that the voltage at both ends of the lamp becomes smaller.

3. If you change a light bulb and this bulb is darker than the previous bulb, it means that the power of this bulb is less than the previous one.

4. In the first case, there must be a problem with the bulb, which causes the internal resistance to increase and its working current to decrease.

5. Whether the voltage becomes smaller, the current becomes smaller, or the bulb is changed, the power of the bulb becomes smaller, power = voltage * current, so if you want the bulb to be brighter, you must choose a bulb with higher power.

The lights are on and off because of the current:

Turn on the lights at peak power consumption, due to the increase in load, the total resistance decreases back, according to Ohm's law, the transmission line answers.

The current on the power line increases, the electric energy lost on the transmission line becomes larger, then the voltage at both ends of the home circuit is relatively low, and the actual power of the bulb is small, so it is darker and late at night, the user who uses electricity is less, the current on the trunk road is small, and the electric energy lost on the line is smaller, then the voltage at both ends of the home circuit is large relative to the voltage at the peak of electricity consumption, and the actual power of the bulb is large, so it is relatively bright.

Another reason is that the ballast is aging or poor quality, which is greatly affected by weather humidity.

How it works Electric light:

An electric light is a device that converts electrical energy into light energy to provide illumination.

Its working principle is: when the current passes through the filament (tungsten filament, the melting point reaches more than 3000 degrees Celsius), the spiral filament continuously gathers the heat, so that the temperature of the filament reaches more than 2000 degrees Celsius, and the filament emits light when it is in an incandescent state, like a red-hot iron can shine. The higher the temperature of the filament, the brighter the light emitted.

Therefore, it is called incandescent lamp.

From the perspective of energy conversion, when the lamp emits light, a large amount of electrical energy will be converted into heat energy, and only a very small part can be converted into useful light energy.

The light emitted by electric lamps is panchromatic light, but the proportion of each color is determined by the luminescent substance (tungsten) and temperature. The imbalance in proportions leads to a color shift in the color of the light, so the color of the object is not realistic under the electric light.

It is related to the actual power: the more work done by the current in 1 second, the brighter the bulb will be.

The higher the electrical power, the brighter the bulb, and it seems that the brightness of the bubble is related to the electrical power.

However, the relationship between current, voltage and electric power is p=ui, comparing two bulbs, when their voltage is the same, the electric power of the bulb with a large current is also large, and the bulb is also brighter, indicating that the brightness of the bulb is also related to the current. And if the current flowing through the bulb is the same, and the voltage at both ends of the bulb is different, then the bulb with a large voltage at both ends is brighter, and it seems that the brightness and darkness of the bulb are also related to the voltageConclusion: because there is a relationship between voltage, current, and electric power P=UI, when U is constant, P is proportional to I, and the increase of P is the increase of I.

Similarly, when i is constant, an increase in p is an increase in u. Therefore, voltage, current, and electrical power all affect the brightness and darkness of the bulb.

Power i.e. is positively correlated with the product of the UI.

1. Since the filament is made of tungsten, a small amount of tungsten filament will vaporize in the incandescent state for a long time, and the tungsten vapor formed will condense on the glass wall of the bulb, and over time, the glass wall will not be transparent.

2. The filament of the incandescent lamp that has been used for a long time will become thinner, that is, the resistance of the filament will become larger.

In the case of constant voltage, the power of the square of the voltage resistance. So the power becomes smaller, so it becomes darker.

These are the two reasons

The greater the resistance, the smaller the current, and the darker the bulb--- which is the case when connected in parallel, and the parallel connection is characterized by the same voltage, p=u r.

In a series circuit, the greater the resistance, the brighter the small bulb--- which is the case when connected in series, and the characteristic of series connection is that the current is the same, p=i *r

Therefore, the above problems must have a precondition, that is, when the current is constant, the greater the resistance of the filament, there is p i2r to know, when the current is constant. The current through the filament is determined by the voltage at both ends of the filament and the resistance of the filament, the greater the actual power, the brighter the bulb, the brightness of the bulb is determined by the actual power of the bulb, when the bulb emits light, it can be regarded as a pure resistance circuit.

The light bulb suddenly brightens in the circuit.

Cause: Increased voltage.

The current rises. Ammeter.

and the voltmeter's indication is larger.

The bulb suddenly dims in the circuit.

Cause: Voltage drop.

The current is reduced. Both the ammeter and voltmeter are shown smaller.

Note: p=u*i u square r i square r

where p is the power.

u is the voltage. i is the current.

r is the resistance. Brightening or darkening is a change in power or a decrease in power. r is invariant, and it is easy to know the answer according to the formula.