Simple math unary equation problems. It will come. Good plus points

1.The circular track is 400m long in circumference, and you can run 3000m as many times as you run along the runway

Solution: If you run along the runway for x weeks, you can run 400x m

Based on the equation of 400x=3000 columns, we get x=

2.A pencil per branch, B pencil per pencil, 9 yuan to buy two kinds of pencils a total of 20 branches, how many two pencils each bought.

Solution: If A buys x branches, then B pencils buy 20-x branches.

According to the column equation, we get x= 10

3.The upper bottom of a trapezoidal shape is 2cm more than the lower bottom, the height is 5cm, and the area is 40 square centimeters.

Solution: If the upper bottom of the trapezoid is xcm, then the bottom is x-2 cm

Based on the equation of (x+x-2)*5 2=40 columns, we get x=9

4.Someone had a balance of 4,800 yuan last year, this year's income increased by 19% compared with last year, and the expenditure was 10% less than last year, and the result was a balance of 7,800 yuan this year.

Solution: If this person's income is $x this year, then last year's income is $x, and the expenditure is x

Yuan. According to the x-column equation, we get x=14280

Or if the person's income last year is x yuan, then this year's income is ——— yuan and the expenditure is ——— yuan.

According to the column equation, get

5.Write a one-dimensional equation with a solution of -10 as ———

6.The 1,400 yuan scholarship was awarded to 22 students according to two awards, including 200 yuan for each of the first prize and 50 yuan for the second prize.

Solution: If there are x students who have won the first prize, there will be ——- students who have won the second prize.

According to the column equation, get

7.Plant a batch of saplings, if 10 per person. There are 6 saplings left unplanted, and if each person plants 12 lessons, 6 saplings are missing. How many people plant trees?

Solution: If x number of people participate in the tree planting, the sapling tree can be expressed as ——- or ——-.

According to the two equations are the same, the column equation is ———

Sister Jing, give it to me.

We're all our own people.

1.Run(400x)m according to not need to write 400x=3000 3(20-x) gives curly braces x + (x + 2) multiplied by 5 divided by 2 = 40

Don't encourage these children to do their own homework and run out of the wrong style, these questions are too simple, uncles don't solve them for him.

I'm too lazy to forget it, it's too simple, you better study hard, it's better to teach people to fish than to teach them to fish

Solution: Let the first granary have x tons of grain, then.

x+3x+1+

x = 40 first grain silo: 40 tons.

The second granary: 40 * 3 + 1 = 121 tons.

The third granary: 40* tons.

Set: the first granary stores x tons of grain, then the second granary stores 3x 1 ton, and the third granary stores grain (1 2) x 1 ton, then there is:

x＋(3x＋1)＋[1/2)x－1]=180

Solution: x=40, then the first granary stores 40 tons of grain, the second granary stores 3x 1=121 tons, and the third granary stores grain (1 2) x 1=19 tons.

The first position is x, the second is 3x+1, the third is 1 2x-1, and the equation is x+3x+1+1 2x-1=180

i.e. 9 2x = 180

x = 40 The first bin is 40 tons, the second is 129 tons, and the third bin is 19 tons.

The first granary has x tons, the second has 3x+1 tons, and the third has x 2-1 tons, because the 3 granaries have a total of 180 tons of grain.

x + 3 x + 1 + x 2-1 = 180

Solution x = 40 tons.

The first silo has 40 tons, the second has 121 tons, and the third has 19 tons.

Let the first granary be x tons.

The second granary is 3x 1 ton.

The third grain silo is x 1 ton.

x＋3x＋1＋½x－1＝180

Solution x=40

The three granaries each held 40,121,19 tons.

There is a question that I don't understand: I don't know why the questioner thinks it's super easy, or how many people are dumber than you when they think it's super easy?

x + 3x+1) +1 2x-1) = 180 9 2x = 180 x = 40 tons, so the first silo is 40 tons, the second silo is 121 tons, and the third silo is 19 tons.

The third granary: 180 (1+2+3 2)-1=19 (tons).

The first granary: 20 2 = 40 (tons).

The first granary: 40 3 + 1 = 121 (tons).

If the first granary is stored x, then the second granary has 3x+1 and the third granary has it.

Then there is: x+3x+1+

Find x to find the grain in three warehouses.

Let the first granary be x, then the second granary is 3x+1, and the third granary is 1 2x-1, for a total of x+3x+1+1 2x-1=180

x=40, the first granary is 40, then the second granary is 121, and the third granary is 19

The first: 40 tons. The second: 121 tons. The third: 39 tons.

40 121 19 Let the first one be x, and the column equation: 180 = 3x + 1 + 1 2x-1 + x

Solution x=40

That is, the first is: 40, the second: 121, and the third: 19

Let the first one be x, and the column equation: (3x+1)+[1 2)x-1]+x=180, and solve: x=40

Set up the first granary with x tons of grain. 3x＋1＋1／2x－i﹢x＝180

1 Solution: Let the speed of A be x kilometers per hour, so the speed of B is 3 2x kilometers according to the title

So x=1

Answer: A's velocity is 1km h B's velocity is.

2 Solution: Set the distance to x kilometers.

Since the effect of the back and forth currents on the speed of the boat cancels each other out, so: 2x 14 5 so: x 35

A: The water distance between the two piers is 35 km.

3 Solution: When the flight speed of the aircraft is x kilometers, the distance between the two places is y kilometers.

According to the question: (x+26)*8 3=(x-26)*19 6=ySo:x=910 3 y=6656 9Answer:

When the flight speed of the aircraft is 910 3 km, the distance between the two places is 6656 9 km4 Solution: Let the train length be x meters.

According to the title: x=350*6 20=105

A: The length of the train is 105 meters.

5 Solution: If the speed of the bicycle is x kilometers, then the speed of the motorcycle is 3x kilometers, according to the question: 3x*2+x*3=135

So: x=15

A: If you have any questions about a bicycle at a speed of 15 km/h and a motorcycle at a speed of 45 km/h, you can send an email.

1.Solution: Set the price to x yuan, and establish the equation according to the meaning of the problem.

x=300A: The price of this product is 300 yuan.

2.Solution: Let the constant x, then there is a plan to plant 5x trees in class A, and 4x trees in class B, and establish an equation according to the meaning of the problem.

5x*(1+20%)+4x*(1+15%)=2126x+

x = 20 actual tree planting in class A 5 * 20 * (1 + 20%) = 120 (trees) and the actual tree planting in class B 212-120 = 92 (trees).

3.Solution: Let the original time take x hours, and establish the equation 30x = (30 * (1 + 30%) + 1) * (2 x 3 + 30 60) 30 x = 80x 3 + 20 according to the problem

90x=80x+60

10x=60

x=6, so the distance between the two places is 30*6=180 km4Solution: Set the predetermined time to x hours, and establish the equation 5x=5*(x 3)+20*(2x 3-2)15x=5x+40x-120 according to the problem

120=30x

x = 4 schools are 5 * 4 = 20 km.

Good topic, wait for me to figure it out, send it to you right away, and don't copy me downstairs.

1 The set price is x yuan according to the equation of cost equality x=300

2 If Plan A plants x trees, then Plan B plants a total of 212 trees.

x=100 A planted a tree B planted a tree.

3 Set the original time to be x hours. According to the distance equal, 30x=(30*x=6 The distance between ab is 30*6=180 km.

4 Let his house be x km from the school x 5-2=(1 3x) 5+(2 3x) 20 and find x=20 km.

1.If the set price is x yuan, the cost price should be yuan).

Therefore, the solution is x=300 (yuan).

2.If Class A plans to plant 5x trees, and Class B plans to plant 4x trees, Class A actually planted 5x (1+20%) trees, and Class B actually planted 4x (1+15%) trees.

So 5x(1+20%)+4x(1+15%)=212 gives x=20

So Class A actually planted 5x (1+20%) = 120 trees, and Class B actually planted 4x (1+15%) = 92 trees.

3. Let the distance between AB and the two places be x kilometers.

If it does not accelerate, the time spent is 30

After acceleration, the speed is 30*(1+30%)+1=40, so x [30*(1+30%)+1]=(x 30)*(2 3)+30 60

The solution is x=180 (km).

4. Set his home to be X kilometers away from the school.

x 3) 5+(2x 3) 20+2=x 5 to get x=20 (km).

1) Set the price to m

then (get m=300 yuan.)

2) Set the number of trees planted in class A x, then B is 4 5*x

x*(1+20%)+4 5*x*(1+15%)=212 x = 100 trees B is 4 5*100 = 80 trees, 3) Let the distance between the two places be s

s/30）*（2/3）+

Gets s=180km

4) The distance is s

s 5 = 2 + (1 3) * (s 5) + (s 20) gives s = 24km

1.A certain commodity is ready to be discounted due to the change of seasons**, if it is priced at a 75% discount**, it will lose 25 yuan, and if it is priced at a 95% discount**, it will earn 20 yuan, ask how much is the pricing of this commodity?

Solution: Let this commodity be priced at x

Solution x = 300 yuan.

2.Two classes A and B participated in the tree planting activity, according to the plan The ratio of the number of trees planted in the two classes is 5:4, and the result is that A planted 20 more than the plan, B planted 15 more than the plan, and the two classes planted a total of 212 trees.

Solution: Set up class A to plan to plant x trees, and class B plans to plant y trees.

then there is a system of equations x y=5 4; x+

From the system of equations, we can get x=100 trees, y=80 trees.

3.If A travels from A to B at a speed of 30 kilometers per hour, and if the increased speed per hour is 30 kilometers more than the original speed, then A takes two-thirds of the original time and 30 minutes to reach B, then how many kilometers is the distance between A and B?

Solution: Let the distance between a and b be x kilometers.

2/3*(x/30)+1/2=x/（30+

The solution is x=180 (km).

4.A student who travels at a speed of 5 kilometers per hour can return home in time, and he has walked a third of the way, and he catches a car with a speed of 20 kilometers per hour, so he arrives home 2 hours earlier than the scheduled time, and asks how many kilometers is his home from the school?

Solution: Let's set his house is x kilometers away from the school.

x/5=(x/3)÷5＋(2x/3)÷20+2

The solution is x = 20 km.

2.Set the plan 5x(1+20%)+4x(1+15%)=212, then find 5x(1+20%), 4x(1+15%)

3.Let the time be 30x=40*(2 3 x+, and then find 30x4.). x/5-2=x/15+2x/60

, set class A as x, class B as 212-x; ：43、x/(

4、x/5=(x/5)*(1/3)+(x/20)*(2/3)+2

(1) If the speed of the electric train is V, then the speed of the maglev train is 5V+20, then it is known by the inscription (V+5V+20)*

3V+10=298,V=288 3=96km h, the speed of the maglev train is 5*96+20=500km h.

2) 150*12+150*x=240*x, x=150*12 90=20 (days).

3)200*3+200t=250t,t=12,s=250t=3000(m)

4)2s=30*t,s=15t.Calculated at average speed, (30+2+30-2)=60 2=30

5)①(40+50)*t=150,t=5/3h

40+50)* t=150-50*,t=25/18h

40+50)*t=150-60,t=4/3h