Then ask the master to solve a question in detail, and ask the master to answer a question

Absolute fault on the C upstairs.

In a, the addition of inert gas at constant temperature and pressure is equivalent to increasing the volume and decreasing the concentration, and the equilibrium moves in the direction of the direction of the concentration growth, that is, the right shift is wrong.

In B, it was originally 3:1:3 Now add 2mol each, that is, 8:4:8 is 3::3 that is, increase the concentration of B, so the balance shifts to the left and moves in the opposite direction.

In C, it was originally 3:1:3 and now subtract 1mol each, that is, 5:1:5 is 3::3 that is, reduce the amount of B, so the balance is shifted to the right, which will increase the percentage content of C.

I'm having a hard time typing, and if the answer is correct, I hope you can.

By the way, I will tell you a knowledge point.

The effect of pressure on the equilibrium movement of the gaseous equilibrium system is essentially the effect on the concentration of reactants, so as long as the concentration of reactants does not change, even if the pressure changes, the equilibrium of the reaction will not move. At constant temperature and volume, the addition of inert gas to the gaseous equilibrium system does not change its concentration, so its chemical equilibrium is not affected.

The opposite problem is that at a constant temperature and pressure, an inert gas is added to the gaseous equilibrium system, which reduces the concentration of reactants, so that the equilibrium shifts.

Choosing B constant temperature and constant pressure to add HE is equivalent to increasing the volume, and the equilibrium moves in the direction of volume reduction, so A is wrong. If Isamu 3:1:

3 is charged a, b, c then the balance does not move, so each filled with 2 moles of the percentage of the three gases b increases the balance and shifts b to the left. Similarly, the percentage of C in option C should be reduced. Because the equilibrium is constant temperature and pressure, the addition of A after equilibrium does not move, and the content of C remains unchanged.

a Correct. b c is added to the same amount of abc respectively, and the reaction is to the left, and the reaction is reduced to the right, and the content of c is less.

The amount of d c does not change, because the pressure does not change, and the new A will continue to decompose into BC, but the overall volume will expand.

Four polygons are added, so that the area of each polygon is 36 divided by 4 equals 9

Therefore, the surface area of the cuboid is 9x2 + 9x3x4 = 126

The area of the square has been increased by a total of 4 squares.

The area of the square is 36 4 = 9 square centimeters.

Square flute length = 3 square centimeters.

The length of the cuboid is 3x3 = 9 square centimeters.

Box surface area = 3x3x2 + 3x9x4 = 126 square centimeters.

It is said that there are three small cubes, with an additional base of four squares.

Then the area of the four bases is 36 square centimeters, then the area of a square is 9 cm2, and the side length of the square is 3 cm

The original cuboid is 3 times as tall and 9 cm long at the base

So the surface area is 3*3*2+9*3*4=126cm2

126 has 4 more square faces, that is, each side is 36 4 9 square centimeters, that is, the side is 3mm, so the length of the cuboid is 9, the width and height are 3, so, count it and you can see that there are 12 + 2 14 square faces, that is, 14 * 9 126

1. Let's calculate the cost price first: the profit is a*(1-20%)=the loss is a (1-20%)=

So the total cost is:

2. The turnover is a+a=2a

The result was obtained, and the loss was made.

See the picture cover Hui file messy manuscript.

The detailed answer is as follows: Blind Diagram of Early Source:

1 This question mainly examines the auxiliary line practice of constructing similar triangles. Looking at the graph, we can easily make an auxiliary line: the point B is an extension of the BE parallel to the AC intersection AD to E.

2 For this kind of problem that requires the addition of auxiliary lines to construct similar triangles in land and air, the most common construction rule is to "make parallel lines", or use equal angles or proportional line segments. In this problem, we can pass the point b as an extension of the be parallel to the ac intersection ad at e, so as to obtain the new condition ab ac+1=ae ad. Using these new conditions to cooperate with the known, we can obtain the conclusion to be proven: 1 ad=1 ab+1 ac.

3. Under normal circumstances, the construction of the lead line is similar, which can play a role of "twice the result with half the effort" for the demonstration and solution of the problem.

4 The elf reminds you: "The evidence is similar, larger than the line segment, and it is a habit to add parallel lines." "As the saying goes: often say that the mouth is smooth, and often do not be stupid. Hope to practice more!

Reference: The parallel lines of AC at point D intersect AB at point E, the parallel lines of AC at point D intersection AC at point F, the triangle AED and the triangle AED are equilateral triangles, be ab=ed ac ab-ad ab=ad ac, CF ac=df ab ac-ad ac=ad ab (ab-ad ab )*ac-ad ac)=(ad ac ) ad ab )

Get (ab-ad)*(ac-ad)=ad*ad so 1 ad=1 ab+1 ac.

Look at the first rock map of the person Miga Qiao.

<> such as the family model code calendar map Zhaochang.

Lost 111 dollars.

It turned out that 46 is now 35, a loss of 11, and later a loss of 100, a total of 111

The bottom surface is a square with an area of 30 30 = 900, fold the four sides, and the height is 5, so the whole volume is 900 5 = 4500 ml.