Math application questions, find the steps answer urgent !

Two possibilities. 10 rooms for people.

11 rooms for people.

Set up x rooms. Y people.

4x+19=y 6x=y+1...x=10 y=564x+19=y 6x=y+3...x=11 y=63

The number of people is x, and the number of dormitories is y. From the inscription, we know that 19 + 4y = x, and 0< x-6(y-1)<6, the final answer is obtained from the above equation and inequality, and

Set the number of occupants x people, dormitory y room (x, y is a positive integer), get:

4y+19=x （1）

1≤x-6（y-1）≤5 （2）

Substituting (1) into (2) yields: 1 -2y+25 524 -2y-20

10≤y≤12

And y is a positive integer, so y=10, or y=11, or y=12i)y=10, then x=59

ii) y=11, then x=63

iii) y=12, then x=67

All three answers are fine, and in the end, to sum up, it is enough to write a conclusion.

Solution: Set: There are x rooms.

There are students (4x+19) people.

The inequality group is set by "If there are 6 people in each dormitory, there is a dormitory that is neither empty nor satisfied".

4x+19-6（x-1)<6

4x+19-6(x-1)>0

In fact, there are 6x-(4x+19)>0

If the number of people in the dormitory is x and the dormitory has y rooms, there is an implicit known condition in this question that x and y are whole numbers, that is, the number of people and the number of rooms cannot be half of the room.

Since there is a dormitory that is not empty and dissatisfied, the number of people in the dormitory is 1 to 5, and the inequalities and equations are listed.

1<=x-6*（y-1）<=5

4y+19=x

10<=y<=12, so the value of y is 10 or 11 or 12

When y=10, the number of people is 4*10+19=59, when y=11, the number of people is 4*11+19=63, and when y=12, the number of people is 4*12+19=67.

Solution: Let A assign x people and B assign y people.

x+y=18

31+x=2(20+y)

Solve the equation x 15 y 3

Good luck with your studies!

First give A 20*2-31 = 9 people, then 9 people left, and B 9 (2+1)=3 people.

Then A will punish 18-3=15 people, and B will punish 3 people.

If x people are transferred to A, then 18-x people will be transferred to B.

31+x=2*(20+(18-x))

x=15, so 15 people should be assigned to A.

3 people each in place B.

31+x=2（20+y） -31+x=40+2y ->x=9+2yx+y=18

x=15 y=3

15 people are assigned to Division A and 3 persons are allocated to Division B.

If A allocates x people, then B allocates 18-x people.

31+x=2（20+18-x）

x=15

Now the total number of A and B is: 31 + 20 + 18 = 69 (people) and now B has: 69 (2 + 1) = 23 (people).

Now A has: 23*2=46 (person).

A distribution: 46-31 = 15 (person).

B allocation: 18-15 = 3 (person).

A allocates 15....B assigns 3....

Same as the same steps.

I don't know what grade you are in, have you ever studied equations?

The question is simple.

Untie; Let the distance be y, and the original planned exercise time is x

45(x+1/2)=y

50(x-1/2))=y

The solution equation is x=y=450

The distance is 450 km. Time hours.

Same as the same steps.

The profit and loss problem can be solved.

45 30 60 = kilometers ......If you travel according to the original time, you will travel less distance.

50 30 60 = 25 km ......If you travel according to the original time, you will travel more distances.

Hours ......Original time.

50 ( 450 km ......The distance between the two places.

Set the original planned travel time to x

distance = (x+

The solution: x= distance is: (

Solution: If the distance between the two places is x, and the travel is 45 kilometers per hour, the time required is x 45 hours.

According to 60 km hours, the time required is x 60 hours, according to the title.

x solution, x = 180

Answer: The distance between A and B is 180 kilometers, and the original planned travel time is hours.

Let the distance between A and B be x, and the original planned travel time is yx 45-y= y-x 50=

First, the addition of the two equations becomes x 45-x 50=1, and then the general score: 50x-45x=45*50 5x=45*50

x=9*50 x=450 and then x=450 is brought into the first formula: 10-y= y=

So the distance between A and B is 450 The original planned travel time is.

Let the sides of the cube be x long

The length of the box is x+4 and the width is x-2

x^2=(x+4)(x-2)

x^2=x^2+2x-8

2x=8x=4cm

The length of the original rectangle is 4+4=8cm, and the width is 4-2=2cm

Solution: If the side length of the square is x, then the length of the rectangle is x+4 and the width is x-2.

Yes: x squared = (x+4)(x-2).

If the solution is x=4, then the length of the rectangle = x+4=8, and the width is x-2=2.

Let the length and width of the original rectangle be x,y

then xy=(x-4)(y+2).

x-4=y+2

then x=8y=2

There are x boys and y girls. Rule.

x+y=47

y=x/2+2

Solve the system of equations.

x+x/2+2=47

3x/2=47-2=45

x=45*2/3=30

So y=47-30=17

So there are 30 boys and 17 girls.

There are x girls and y boys.

x+y=47

x-2)*2=y

x=17 y=30

There are 30 boys. There are 17 girls. The answer from the guy upstairs was right.

The answer is the most beautiful.

LZ is pitiful. There are no answers to summer vacation assignments.

Xie upstairs. We only know the answer. I haven't written the steps yet.

If there are x boys, then there are 1 2x+2 girls.

x+1/2x+2=47

Then x=30

A: There are 30 boys and 17 girls in the class.

50 students, the average score is 60, the total score is 50 * 60 = 3000, and the number of passing students is x, which can be listed:

70x+45(50-x)=3000, x=30

Hope mine can help you.

The number of students who passed was 30. Find the steps.

The difference between the average passing score and the average score of the class is 70-60=10 points.

The difference between the average failing score and the average score of the class is 60-45=15 points.

The ratio of the two differences is 10:15=2:3

The ratio of the two numbers is 3:2

The number of qualified candidates is 50 3 (3+2)=30.

Solution: If the number of passers is x, then, 70x + 45*(50-x)=60*50

Solution x=30

Answer...

The answer is A6m s; B 4m s

It can be solved like this.

Let A run xm per second and B run ym per second

So get the equation.

5（x-y)=10...Time (5s) multiplied by the velocity difference (x-y) equals the distance difference (10m).

4(x-y)=2y...Time (4s) multiplied by the difference in velocity equals the difference in distance (2y).

The solution is x=6, y=4

So it's ready to come out.

A 6 meters. B 4 meters.

Same as the same steps.

The velocity ratio of A and B is (4+2): 4=3:2

A ran 10 (3-2) in 5 seconds 3=30 meters.

Then A runs 30 5 = 6 meters per second.

B runs 6 3 2 = 4 meters per second.

Let A run x meters per second, and B run y meters per second.

Then: 10 5y 5x

2＋4）y＝4x

Solve the system of equations.

x＝6y＝4