Please ask two math application questions, I am anxious to drop, thank you

Solution: (1) If the mixed doubles is played x games, the men's and women's doubles will be played x+4 games, and the men's and women's singles will be played x+8 games. It is known from the meaning of the title.

x+2(x+4)+2(x+8)=64

x=82) x + 8 = 16 matches for men's and women's singles.

The number of matches is 2 2 16 = 64 people.

Men's and women's doubles are played separately x +4 = 12 matches.

Number of matches: 2 4 12 = 96 people.

Mixed doubles is played in 8 matches.

The number of matches is 4 8 = 32 people.

All athletes participating in the competition = 64 + 96 + 32 = 192 people.

A: Eight mixed doubles matches were played with a total of 192 athletes participating in all competitions.

Solution 2: If you buy x copies for the first time, you will buy 200-x copies for the second time. by the title.

10x+10x×10%+

Solution x=70

So the second purchase 200-70 = 130 copies.

A: The first purchase is 70 copies, and the second purchase is 130 copies.

...Do you have a cell phone, I tell you. I'm also 98, trust me.

1.Solution: Set Men's A and Female B, Men's Singles A, Women's Singles B, Men's Doubles AA, Women's Doubles BB, and Mixed Doubles AB (field).

a+b+aa+bb+ab=64

aa=bb=ab+4

a=b=aa+4=bb+4

Lianli solution. a=b=16

aa=bb=12

ab=81) played 8 matches in mixed doubles.

2) It is related to the registration rules of the competition, for example, some people only participate in mixed doubles, and some people participate in both men's singles and men's doubles.

2.Solution: Let's buy X copies for the first time.

10*x*(1+10%)+10*(200-x)*solution x=70

That is: the first purchase of 70 copies, the second purchase of 200-70 = 130 copies.

Question 1: Let singles be A, doubles be B, and mixed play be C

2a+2b+c=64 a-b=4 b-c=4a=16 b=12 c= 8

8 matches of mixed doubles.

112 athletes.

Question 2: Set the first purchase of A and the second purchase of B.

then a<100

a+b=200

10*a*110%+10*b*85%=1875 to get a=70 b=130

Do the task, ask for one, thank you!!

1. (1) The number of mixed doubles matches is x

Then Men's Doubles is x+4, Women's Doubles is x+4, Men's Singles is x+4+4, and Women's Singles is x+4+4, and the cumulative sum is 64 5x+6*4=64

x=8 A: The number of mixed doubles matches is 8, 12 for men's and women's doubles, and 16 for men's and women's singles.

2) Person-time 8 * 4 + 12 * 4 * 2 + 16 * 2 * 2 = 1922, set the first purchase of x copies.

There is 10x(1+10%)+

Solution x=70 then the second purchase is 200-70=130 A: .

1. (1) 8 matches of mixed doubles;

Mixed doubles was played x times, 64=2(x+4)+x+2(x+4+4)x=82) A total of 96 athletes participated in all competitions;

2. The first and second purchases were made;

Let's say I bought x copies for the first time and y copies for the second time.

x+y=200

10x+(10×10%)x+(10×85%)y=1875；

x=70，y=130；

Let the unit price of football be x, basketball be y, and the equation is:

50xx9%+40yx11%=298

50x+40y=3000

The solution is x=32

y=35 can also be thought of in this way, if it is all football profit 3000x9%=270, less profit 298-270=28 yuan, and basketball is 11%-9%=2% more than football

28 2% = 1400 is the total amount of basketball money, and then divide by the number of 40 is also 35 yuan each, I hope to help you, and learn.

This problem is very easy, football is 42 yuan, basketball is yuan, the specific calculation is the column equation: let x is the ** of football, y is the ** of basketball, 50x+40y=3000, 50x+40y=3000+298, solution, x=42, y=

Let soccer ball ** be a and blue ball ** be b; Then the equation 50a+40b=3000, 50 9%a+40 11%b=298 can be solved to obtain a=32, b=35, and the input price of football and blue ball is 32 yuan and 35 yuan respectively.

Set the input price of football to be X yuan, and the purchase price of basketball to be Y yuan

50x9%x+40x11%y=298

50x+40y=3000

Simultaneous 2 equations, x=32, y=35

That is, the price of football is 32 yuan, and the price of basketball is 35 yuan.

Grass grows. And the example you gave does not grow.

Let the thickness of the grassland be a, the daily growth rate is b, and so on.

5*（a+10b）=11*10

6*(a+14b)=12*14

To obtain ab, bring in, 8*(a+xb)=19*xx can be found.

Question 1:

The unit prices of the three combinations are:

A = 2 * 2 + yuan;

B = 2 * 3 + yuan;

C = 2 * 2 + yuan;

The number of sets of three combinations of fruits sold is: X, Y, and Z.

Then: 4x+6y+4z=116

Multiply by two formulas to get:

Subtract the previous formula from one formula to get :

Therefore: y+z=15, that is, the two combinations of B and C have sold a total of 15 sets.

Since the C fruit in the two sets of combinations B and C is 1 kg, so. c Fruit sold 15 kg.

Question 2: The number of people who grow three kinds of vegetables is x, y, and z. Then:

x+y+z=20

2x+3y+4z=50

Multiply by 2 to get 2x+2y+2z=40

Subtract the previous formula from the second formula: y+2z=10, and introduce y=10-2z into a formula: x+10-2z+z=20, and launch:

x=z+10 In order to make the total crop output value the highest, it is known from the table given that there should be as many vegetables as possible, followed by wheat and tobacco leaves. Therefore, it is necessary to make x the largest, z second, and y the smallest as much as possible.

From y=10-2z, x=z+10 and x+y+z=20, the minimum z is 0 and the maximum is 5; x is 15 at maximum and 10 at minimum; The maximum y is 10 and the minimum is 0;

So the possible values of x, y, z are:

When x=10, y=10, z=0

When x=11, y=8, z=1;

When x=12, y=6, z=2;

When x=13, y=4, z=3;

When x=14, y=2, z=4;

When x=15, y=0, z=5;

Therefore, in order to achieve the highest total value, choose the last planting plan, that is, 15 people grow vegetables and 5 people grow wheat; The total output value can reach 15 * 2 * 1 + 5 * 4 * 10,000 yuan.

The least common multiple of 46 is 12

1 is the first one, no need to pull it out, hehe).

So it's 9

The common factor of 4 and 6 is 12, that is, there is no 12 meters, and there is a flag that does not need to be pulled out. 96 12 = 8, i.e. there are a total of 8 flags that do not need to be drawn.

8 sides, only the common multiple of 4 and 6 do not need to be pulled: 12 24 36 48 60 72 84 96

The flag that is not pulled out is the flag within 96, the common multiple of 4 and 6.

The least common multiple of 4 and 6 is 12, and the common multiple of 4 and 6 is a multiple of 12.

96 12 = 8 (surface).

There is also the first side that does not pull out, a total of 8 + 1 = 9 (face).

Solution: 300 30 = 10

A: It takes 10 days for Team B to complete it alone.

There is no way to type the mathematical symbol: * represents multiplication and division represents division.