Solving Primary Mathematics Application Problems Urgent !!!!

Solution: Set the car x hours to catch up with the bus.

x=19/5

A: The sedan 19 to 5 hours can catch up with the bus.

How many x hours can a sedan catch up with a bus.

25x=95x=

Set up a sedan x hours to catch up with a bus.

The column equation is solved to x=19 5= (hour).

How many x hours can a sedan catch up with a bus.

25x=95

x = A: The car can catch up with the passenger car in hours.

Multiply by 2 = 95 =

x = 95 divided by.

x is approximately equal to.

Hope it works for you.

According to the formula of the chase problem: chase and catch up program = speed difference * time to calculate the chase time. Set up a sedan x hours to catch up with a bus. x=

Solution: Set the car x hours to catch up with the bus.

x = this is an approximation).

A: The sedan can catch up with the passenger car in hours.

Solution: Set up a car to catch up with the bus in T hours;

t = * 2 + t

Solution t = (hour).

A: The sedan can catch up with the passenger car in hours.

If the speed of the passenger ship is x Ziliang h, the ship departing from port A has gone 4+12=16 hours when it meets, and the ship departing from port B has gone for 12 hours

15*16+12*x=480

Solution x=20

The title of this encounter is listed according to the total distance and the side.

The actual distance of the train is 1500 + 300 = 1800m, the time is 3 minutes, and the rest is calculated by yourself.

Enumeration:

Width 1m, length 18m Area: 18 square meters.

It is 2m wide and 16m long, and the area is 32 square meters.

It is 3m wide and 11m long, with an area of 33 square meters.

It is 4m wide and 12m long, with an area of 48 square meters.

It is 5m wide and 10m long, and the area is 50 square meters.

Equations are also possible.

Solution: Let the length of BC be x meters.

s=x(20-x)/2

(x-10)^2/2+100

So when x = 10 meters, the area is the largest.

The enumeration method is easy for elementary school students to understand.

Width 1m, length 18m Area: 18 square meters.

It is 2m wide and 16m long, and the area is 32 square meters.

It is 3m wide and 11m long, with an area of 33 square meters.

It is 4m wide and 12m long, with an area of 48 square meters.

It is 5m wide and 10m long, and the area is 50 square meters.

As long as the length of the rectangle is twice as wide as it is the largest, the length is 10 meters, the width is 5 meters, this type of question is like this...

Did you learn about quadratic equations in elementary school?