Come in and solve math problems math problem solving, quick, thanks

An algebraic formula is a sub-formula, not an equation.

Which year's questions, which year's question is how much, this is the thinking of the questioner, I have done a lot of competition questions in 2006, 2007, 2006 have 2006; 2007 and 2007, if you encounter such a question this year, you know how many you answer, hehe.

m+n=opq=1

The square of a = 4 and then substitute for the value of 2005

It's not an equation or an algebra, what value do you shout! Flip through the book and see it clearly before it comes out! Left 0 Right 2005 How to wait? This is a good type of question.

Is this a problem for you in elementary school? I'm only in 6th grade! I thought you were in elementary school!

Yes! It's not an algebraic equation, it's an equation, and it's a false equation.

Suspect that the "=" in your question should be "+" or "-".

You go back and look at the question.

Algebraic equations are not equations, what you give is already equations, how do you find them?

Ask the teacher or classmates again.,Did you copy the wrong question+。。

1、 840 ÷（1+5%）

800 (sheets).

A: The school used 800 sheets of blank paper in April.

72000 (yuan).

72000 7% = 5040 (yuan).

72000 + 5040 = 77040 (yuan).

A: This hotel should pay 77,040 yuan in taxes every year.

1.Set up x sheets of white paper for April.

Then there is: (1+5%)x=840

x = 800 * 5% (1 + 7%) = 10,000 yuan).

The month is used in paper as a unit.

2. (12 5% + 12 5% 7%) 12 = 10,000 yuan = 77,040 yuan.

1. Paper used in April = 840 (1 + 5%) = 800 (sheets) 2, business tax 120000 * 12 * 5% = 72000 urban maintenance and construction tax 72000 * 7% = 5040

Total = 72000 + 5040 = 77040

Zhang Yuan: Didn't the two people in front of me pay attention to the monthly income and ask for the annual tax, shouldn't they be multiplied by 12 in the monthly results?

÷（1+5%）=800

2. Business tax = 12 5% = 10,000 yuan) Urban maintenance and construction tax = 10,000 yuan) So this hotel should pay 10,000 yuan in taxes every year.

Question 1 (1): The length of this section of the road is: 90 (1 5 + 1 4) = 90 (9 20) = 90 20 9 = 200 meters.

2): The length of this section of the road is: 20 (1 4-1 5) = 20 (1 20) = 20 20 = 400 meters.

3): The length of this section of the road is: 55 (1-1 5-1 4)=55 (11 20)=55 20 11=5 20=100 meters.

Question 2: The distance between Fuzhou and Xiamen: 35 (3 5-1 2)=35 (1 10)=35 10=350 km.

1.90 (1 5 + 1 4) = 200 meters This section of the road is 200 meters long.

2.20 (1 4-1 5) = 400 m This section of the road is 400 m long.

m This section of the road is 100 meters long.

35 (3 5-1 2) = 350 m Fuzhou and Xiamen are 350 km apart.

1.One-fifth plus one-quarter is nine-tenths of twenty and 90 divided by nine-tenths equals 200

Dividing by one-fifth minus a quarter equals 400

3.One-fifth plus one-quarter equals 9/20 1-9/20 = 11/20 20 divided by 11/20 = 200

Three-fifths minus one-half = one-tenth 35 divided by one-tenth = 350 is so tiring.

90 (1 5 + 1 4) = 90 (4 20 + 5 20) = 90 * 20 9 = 200 meters, this section of the road is 200 meters long.

(1 4-1 5) = 20 (5 20-4 20) = 20 * 20 = 400 meters, this section of the road is 400 meters long.

(1-1 5-1 4)=55 (1-9 20)=55 11 20=55*20 11=100 metersThis section of the road is 100 meters long.

Divided into Z groups, each group of x boys, each group of girls Y.

x*z=32

y*z=24

z is the greatest common divisor of 32 and 24, which is 8

x=32/z=32/8=4

y=24/z=24/8=3

x+y=4+3=7

It can be divided into up to 8 groups of 7 people.

Up to 8 groups, 4 males and 3 females in each group.

(x+y)²-3(x+y)=(x+y)[(x+y)-3]

x+y)(x+y-3)

Have fun! I hope it can help you, if you don't understand, please ask, I wish you progress! o(∩_o

Paomeng and Meiyu tease the pride and pose the curtain.