Senior Chemistry! How to judge this question hooked by the red pen?

Sulfate is a strong electrolyte, so NH4 and Al are all electrolyzed, originally NH4 is a weak electrolyte will form NH3H2O, and because Al and it rob the hydroxide in the solution, so NH4 does not have too much hydroxide to bind with it, so the concentration is the highest;

Chloride ion strong electrolyte, NH4 is all electrolyzed out and partially combined with hydroxide back, because no one grabs it, so the concentration ratio is lower;

Ammonia is ionized and balanced, with NH4 ions, which is less than the above;

Ammonium acetate is a strong electrolyte, because acetate needs H+, ammonium needs OH-, so each takes what they need, and finally acetic acid and ammonia live together and can be stable, so NH4+ is less!!

Got it?

nh4+ +h2o〈=〉nh3·h2o + h+ ①

nh3+h2o<===>nh3·h2o<===>(nh4+) oh-)

Comparing the concentration of ammonium ions in the solution, in the first 3 substances, the degree of hydrolysis of ammonium ions is compared, the more hydrolysis, the lower the concentration of ammonium ions.

According to this equilibrium reaction, it can be seen that in order to inhibit its hydrolysis, it is necessary to provide H+, that is, the more H+ is provided in it, the more completely the reaction moves to the left, and the greater the concentration of ammonium ions.

Let's take a look at the first one, ammonium aluminium sulfate double salt, aluminum ion hydrolysis Al3++3H2O<==>Al(OH)3+3H+ can provide H+

Ammonium chloride, chloride ions are completely ionized and not hydrolyzed.

Ammonium acetate, acetate hydrolysis, provides oh-, which is equivalent to doing it against it, and does not provide h-, but also creates oh-

Therefore, 1>2>3 is easy to say, but the main difficulty is 4.

Is ammonia more ionized, or is ammonium ion hydrolysis worse? The first two brothers are always vague and vague in this place, avoiding the important and trivial. The landlord's doubts came out, right? I'm afraid that you will give those 2 answers first, I will send them out first, ask questions, and I will explain it to you clearly.

I won't explain the equation.

ai3+ +

AI3+ remaining, AI3+ +3AIO2-+6H2O=AI(OH)31:3

NAI3+=B-A3, NNH3=3(B-A3)=3B-AAIO2-remaining, 2AIO2-+CO2+3H2O=2AI(OH)3+CO32-

Naio2-=a-3b, NCO2=1 2(a-3b) = the last one is between the equation AI3+ +3OH-=AI(OH)3 and AI3+ +4OH-=AIO2-+2H2O.

So the ratio of C1 to C2 is between 1:3 and 1:4.

a. Because the reduction concentration of hydrochloric acid is weakened, concentrated hydrochloric acid can undergo redox reaction with manganese dioxide, and dilute hydrochloric acid does not undergo redox reaction with manganese dioxide, so concentrated hydrochloric acid cannot be completely consumed, a error;

B. What happens in the graduated cylinder is a substitution reaction, not an addition reaction, so B is wrong;

c. The reaction of copper and chlorine produces brown smoke, not blue smoke, and copper chloride is dissolved in a blue-green solution, which is concentrated green and dilute blue, so C is wrong;

d, the moist colored cloth strip can fade, indicating that there is chlorine gas generated, and the generated chlorine gas reacts with sodium hydroxide to form sodium chloride, sodium hypochlorite and water, adding sulfuric acid solution to the beaker is acidic, under acidic conditions, chloride ions and hypochlorite ions can undergo redox reaction to generate chlorine gas, the ion equation of the reaction is: 2h ++cl - clo - = h2o + cl2, so d is correct.

You take it for granted.

CuCl2 is blue, but ** is not blue smoke, but brown smoke.

Brownish-yellow smoke, so c wrong.

Conservation of gains and losses with electrons.

Fes obtained a total of 9a mol, Fe3O4 obtained a total of B mol, one mol of nitric acid lost 3mol

So option c.

This is a disproportionation reaction.

NO2 is both an oxidant and a reducing agent.

Oxidation reaction: NO2 loses electrons and generates HNO3

Reduction reaction: NO2 gets electrons and generates NO

It is to write the oxidation reaction and the decomposition reaction separately.