The isosceles triangle is known to have a top angle of 15 degrees and a waist length of 30 centimete

Known isosceles triangles.

The apex angle is 15 degrees. The waist length is 30 cm. Find out how many centimeters is the length of the bottom edge, this question is.

A line is drawn perpendicular from the vertex to the bottom edge, dividing the isosceles triangle into two parts. The apex angle is the degree. The other is 82 5 degrees.

Then make use of the triangle one. Tangent.

The sum tangent theorem gives us the two right-angled sides of a triangle. Finally, we can find out what is the base of this isosceles triangle?

What is the area of an isosceles triangle with a top angle of 30 degrees and a waist length of 6 cm Solution: It is known that the top angle of an isosceles triangle is 30 degrees and the waist length is 6 cm, and the height on the waist length = waist length sin30° = 6 1/2 = 3 cm The area of the isosceles triangle = waist length The height on the waist length 2=6 3 2=9 square centimeters Answer: The area of this isosceles triangle is 9 square centimeters.

sin15°= ((1-cos30°) 2) (180°-30°) 2=75° Bottom edge = 128sin30° sin75° (180°-30°) 2=75° From the sinusoidal theorem, we get: Bottom edge =128sin30° ....

The height on the base edge of an isosceles right triangle = half of the base edge. So the square of the height + (half of the base) square = the square of the waist So you can find the bottom edge.

From the apex angle we can calculate its base angle because the two base angles of an isosceles triangle are equal. So the sum of the two base angles is 180 degrees-15 degrees equals 165 degrees, and then each base angle is the degree, and we use the sine theorem to calculate it.

Summary. Isosceles triangle, the top angle is 36 degrees, the waist length is meters, and the length of the base edge is found.

Hello, can you understand such a solution?

If you're not satisfied, I'll answer it in a different way.

I don't understand. Are you in high school.

Is the top angle 36 degrees?

Be. Straightforward results will do.

If you are in high school, you can write the answer directly.

The answer is right.

Just give me the length.

This should be solved by the ** segmentation method, which is relatively simple.

7cos72°This is the length.

How many meters is the length?

It can also be expressed in such a form.

You see which one is better for you.

Just give the length directly. This one.

1) The circumference is 60cm, and the waist length cannot determine the specific value, but the range can be determined:

Dress up 15cm >> Waist < 30cm

2) The top angle is 50°, and the bottom of the hall is (90°-50°) 2=20°

Make a waist high from the apex of the bottom corner of the isosceles triangle, high on the outside of the triangle.

At this time, the outer angle of the top angle is the sum of the two bottom angles, which is 30 degrees.

The height of the waist, the extension of the waist and the other waist form a right-angled triangle containing a 30-degree angle.

The hypotenuse is the waist length of the original isosceles triangle 10, and the height is the right-angled side opposite the angle of 30 degrees, so the length is 5, so the area of the isosceles triangle is: 1 2 10 5 = 25 square centimeters.

Bottom angle = (180-120) 2 = 30 When the hole in the right triangle slips at an angle of 30 degrees, the straight and sensitive corner edge it faces is half of the hypotenuse so the waist length of the nanara = 2 * 3 = 6

The bottom angle is 70 degrees.

So the bottom edge is 2*20cos70 degrees =