Is the tonnage of the cylinder related to the plunger diameter of the plunger oil pump

Updated on Car 2024-06-05
14 answers
  1. Anonymous users2024-02-11

    Buy rotary lobe pumps and other products to find Jiangweilong Machinery Technology ****, 30 years of focus on pump manufacturing, 21 years of rotary lobe pump research and development. At present, the company mainly produces XHB rotary piston pumps and related extension products in the field of fluids, ZZB cam rotor pumps, grinding, homogenizing, emulsifying, mixing pumps, twin-screw rubber lining pumps, dry grinding resistant chemical pumps, etc. And provide OEM and ODM services for well-known manufacturers at home and abroad.

  2. Anonymous users2024-02-10

    Pressure p=60MPa=600kgf cm2 cylinder thrust f1=p*a

    Cylinder piston area a=

    So 15000kgf=(600kgf cm2)*d=

    Rounded to the national standard, 63mm is selected

    Return to calculate the actual required oil pressure p=48mpa

    However, if the installation space is sufficient, it is best to choose a larger diameter of the cylinder, because the oil pump will affect the performance of the oil pump if the oil pressure is rated again, such as the noise is very large, the life is very short, and there is the problem of the life of the cylinder seal, if you choose the 80mm cylinder, the working pressure can be controlled within 30MPa, and the V-type combination seal is selected, and the life and leakage problems can be solved.

  3. Anonymous users2024-02-09

    Force area pressure pressure.

    The pressure depends on how much MPA the pressure of your oil pump, the pressure is 15 tons, and you can calculate the force area, that is, the area of the cylinder piston.

  4. Anonymous users2024-02-08

    The cylinder thrust kg is equal to the cylinder piston area cm

    Multiply 10 oil pump pressures.

    It should be 56mm according to the calculation. However, according to the national standard, the cylinder diameter should be 63mm.

    You say: The oil pump pressure is 60MPa, what kind of pump is this? Mechanical pumps are generally not that big, right? The gear pump is generally 16MPa, and the piston pump is 32MPa. Hand pumps are still possible, but you've said they're electric, and I'm a little confused. Can you please advise?

  5. Anonymous users2024-02-07

    The main reasons for the lack of flow of the plunger pump are: 1. The inlet pipeline is blocked, check whether the inlet filter is blocked; 2. The inlet pipeline is not tightly sealed, which leads to air ingress and reduces the volumetric efficiency of the pump; 3. The inlet and outlet valves are not tightly sealed, resulting in internal leakage, remove the inlet and outlet valves, check the sealing performance of the valve seat and the valve core (check with kerosene) 4. Packing leakage, replace the packing that is, raise your fingers 5, if there is no problem of insufficient flow, the following reasons can not be considered. However, if the installation position of the pump is changed or the medium is changed or the inlet pressure is changed, the NPSH of the pump should be considered sufficient.

  6. Anonymous users2024-02-06

    Dear you with a good gear, I am happy to solve the old banquet for youAnswer: Piston pump flow rate with 80 tons of hydraulic oil stupid cylinder speed (24 30) m min (hydraulic cylinder area (cm2): a = d 2 4, d:

    Effective piston diameter of hydraulic cylinder (cm) Hydraulic cylinder speed (m min): v = q a, q: flow rate (l min) According to the principle of incompressibility of liquid, the oil inlet volume of the oil cylinder is equal to the oil output volume, if the oil with rod cavity is pumped into the rodless cavity, then the flow rate q in the above formula is the system flow rate + regeneration flow.

  7. Anonymous users2024-02-05

    Fig. a, let the liquid pressure be p, take the plunger as the research object, the area of the plunger mask is a= d 2 4, g-the weight of the plunger, ignore at this time, g=0. The force is p*a=f+g, and p=fa=f ( d 2 4) = 5000 (100*100*

    Fig. B, let the liquid pressure be P1, take the cylinder block as the research object, at this time, the code is dispersed and the weight of the cylinder is negligible, G=0, the area of the cylinder block A= D 2 4, A1= D 2 4- D 2 4 Its force is P1*A=F+P*A1+G1 to obtain P1=F ( D 2 4)=5000 (100*100* visible P=P1=

  8. Anonymous users2024-02-04

    Force divided by the area of the plunger, two identical, junior level questions.

  9. Anonymous users2024-02-03

    Theoretically, when the angle between the swash plate and the plunger, the oblique axis and the plunger in the oil pump becomes 90 degrees, the theoretical pressure difference between the oil inlet and the oil outlet of the oil distribution plate is zero, and the plunger neither absorbs nor presses oil at this time, so the output flow of the oil pump is zero.

    In the field of hydraulic industry, zero leakage cannot be achieved, so piston pumps, including hydraulic motors, must have a shell drain. And the oil inlet and outlet you said are actually the two working oil ports of the piston pump, don't understand it separately as the oil inlet and outlet, the working oil port is divided into two oil ports, a and b, the oil port A can both enter and exit oil, and the same is true for oil port B.

  10. Anonymous users2024-02-02

    Working pressure: 100mm=10cm=5cm+5cm5*5*cm²cm

    315* tons.

    The flow rate of the oil pump should be selected according to the action frequency of your cylinder, for example, 30 round-trips in 1 minute, and then multiplied by the flow rate of a single action, then the flow rate per minute is 30*liters, and the flow rate is marked on the oil pump.

    Flow rate per 1 action: stroke) = 2355 cubic centimeters = liters.

  11. Anonymous users2024-02-01

    First of all, you have to consider the maximum working pressure of your own hydraulic cylinder, the pressure of the piston pump is not low. The inner diameter of the hydraulic cylinder is 100mm, what is the outer diameter and inner diameter of the piston of the corresponding hydraulic cylinder? Whether your cylinder is pushing or pulling, the force area is different; f=p*s, which is a simple calculation using this formula, can roughly know the tensile force and thrust force of the work; When actually used, it needs to be controlled by speed control valves, etc.; The displacement can be calculated with reference to the recommended answer, that is, the frequency of action; When actually using, it is necessary to consider the safety factor.

  12. Anonymous users2024-01-31

    The pressure is related to the load, the displacement is related to the speed, as long as it is enough.

  13. Anonymous users2024-01-30

    The displacement should be according to the time requirements, working pressure: tons = cylinder area x working oil pressure.

  14. Anonymous users2024-01-29

    Hello, glad your question wishes to be.

    The answer to the Hengshui Brady meter.

    p= kg: p - punching force kg

    p-Material tensile strength kg cm2

    a - cross-sectional area of the stamped material, for a circle, a = 4d2xt t t - the thickness of the material is in cm for a rectangle a = axbxt the length and width of the b material. Other shapes are calculated in this way. The 2 in the formula is the square number, and it should be noted that the unit should not be mistaken.

    Finally, when choosing a machine tool, it is necessary to leave a safety factor to ensure the safety of the machine tool and its long life. Generally, you can multiply the calculation result by it.

    The effective area of the piston is calculated first, and then the pressure value corresponding to the pressure gauge reading is obtained according to the product of pressure = pressure (pressure gauge reading) and effective area.

    1MPa = 1000kpa = 10 bar = 10000mbar = 10kg (kg).

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