Questions about high school, learning math. Overall problem.

Mentality, many things mentality is very important, first of all, put a good mentality, no one can be very powerful at once, but, the usual accumulation, and attitude, determines success or failure, those who seem to be your so-called effortless, do you know how much effort he spent behind it? And now he is standing on the basis of learning on the basis of a higher level, of course, in you feel that it is very effortless, learning is a process of accumulation, there is no shortcut, only hard work, but you don't see the efforts of others.

To do mathematics, first of all, you must have a clear concept, what definitions, theorems, etc., and secondly, you must do the problems carefully, study more, never let go of what you don't understand, and understand the relevant places by reading books, reading example problems, etc., and you will go further. High school is definitely more difficult than junior high school, so you should also work hard and think more comprehensively.

I believe that we will make progress through hard work.

How many points can you score now? 150 points?

It depends on whether you have a problem with the basic questions or the slightly more difficult questions, or if you have a problem with the extra difficult questions.

Decide what to do next according to your own situation.

Understanding is the most important thing, do more questions to cultivate problem-solving ideas.

Learn to lecture others, and you'll be successful.

This process... It's really hard to write, but if you write it on paper, it's probably easier...

By the way. Your two equal signs mean greater than or equal to it, not much greater than it.

To be further verbose, this drawing coordinate axis solution area is more intuitive and simple. The intersection of two straight lines is divided into four regions, and the upper part of the region is the region where the solution of the formula , , is located.

Forehead.. The resolution of the equation between the two straight lines is x+y=3 2x-y=0, and it can be seen that the straight line y=k(x+2) is below the above region.

As can be seen from the figure, the straight line y=k(x+2) crosses the point (-2,0), and k is the maximum value when the straight line passes through the point (1,2).

Get -1 k 2 3

The answer is not 2 3, I don't know if it's right.

Find the midpoint coordinates (midpoint coordinates formula) first

Then find the slope of the perpendicular bisector.

The straight point oblique equation is obtained.

Solution: Let the perpendicular bisector of line segment AB be m, and the coordinates of the midpoint of line segment AB be ([7+(-5)] 2, [(4)+6] 2).

i.e. (1, 1).

The slope of the straight line ab is [6-(-4)] 5)-7]=-5 6 and m is perpendicular ab, so the slope of m k=6 5

The equation of the oblique equation of the straight point is y-1=(6 5)(x-1) and the solution yields 6x-5y-1=0

Because it is the perpendicular bisector of the bright spot of ab, then the straight line perpendicular to ab must pass the midpoint of the straight line ab, because the midpoint of the straight line ab is (1,1) because the two lines are perpendicular to each other, the product of the slope is -1, and because the slope of the straight line ab is -5 6, the slope of another straight line perpendicular to ab is 6 5

Then the line segment ab perpendicular bisector equation is y-1=-5 6 (x-1), and you can reduce it to a general formula.

Find the trajectory equation to find which set which Let p coordinates (xp, yp) circle p: (x-xp) square + (y-yp) square = r squared, when r is greater than xp absolute value is, there is an intersection point with y axis, when x=0 find the distance between the two intersection points with the y axis is 2 (r squared - xp squared) = r, and r square = r square = r square = four-thirds xp squared, and the circle p passes (a, 0) so (xp-a) square + yp square = r square = four-thirds xp squared, Because the p coordinate satisfies the equation (xp-a) square + yp square = four-thirds xp squared, it can become (xp + 3a) square 12 a square - yp square 4 a square = 1, so it is hyperbolic and translated.

The answer upstairs is very complete, you have to be familiar with the general formula of the circular hyperbola, hope.