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3.Surface area (3*4+4*6+3*6)*2=108cm2 volume 3*4*6=72cm3
4.Height 240 48 = 5 5 * 6 * 2 + 6 * 8 + 5 * 8 * 2 = 188mm2 In the fourth question, the box has no lid, so one side (length times width) cannot be counted as surface area. Those with an answer of 236 made this mistake, and those with an answer of 136 do not know what went wrong.
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Question 1: m=300-300*6%=282 (g) Question 2: 270*(1-80%)=54
Question 3: s=2*(3*4+4*6+3*6)=108v=3*4*6=72
Question 4: The base area is 6*8=48, then the height is 240 48=5, so the surface area is 2*(6*8+5*6+5*8)-6*8=188 Question 5: (y*90%-1530) y=15%.
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Let's give it to the first one, the fastest
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3.Surface area = (3 * 4 + 3 * 6 + 4 * 6) * 2 = 108 volume = 3 * 4 * 6 = 72
4.Height = 240 6 8 = 5 Surface area = 6 * 8 + 6 * 5 * 2 + 8 * 5 * 2 = 188
5.(90%y-1530) 1530=15% List price y=1955
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1. Xiaohua is 140 cm tall and Cortana is 160 cm tall. How many percent is Cortana more than Floret? To solve this problem, we have two ideas:
a. You can first find out that Cortana is higher than the floret (20) cm, and then find the percentage of (20) cm (140 cm). The list is ( 20 140 ) and the result is ( ).
b. You can also regard the height of the floret as 100%, find out that the height of the floret is equivalent to the height of the floret ( ) and then find out how many percent of the height of the floret is higher than the floret. Listed as ( ) The result of the calculation is (. Is the percentage of Flore shorter than Cortana ( ) equal to the percentage obtained earlier?
Not equal), think about why. The reference object is different.
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a, 20, 20, 140, (160-140) 140, b, 114, [(160 140)*100%-100%], not equal.
Reason: The reference is different.
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Focal length f=60-50=10cm
At this time, the object distance (the distance from the candle to the convex lens) U=50-20=30cm, 30 is greater than 10x2, that is, the object distance is greater than 2 focal lengths, U>2F, and the image is inverted, (reduced) real image.
camera).
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Travel 100m to the north
The size is equal and the direction is the same.
1 0 in any direction.
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1.and other large virtual images.
Plane mirror Chong Xinwu vertical frank.
3.The dispersion or direction of light propagation.
Presents a clear image.
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It's better to think of multiple solutions.
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