Where is the largest geostrophic deflection force on Earth?

Updated on science 2024-06-13
2 answers
  1. Anonymous users2024-02-11

    is the pole, the equator is the smallest and the two levels are the largest. The geostrophic deflection force is actually formed by inertia - for example, for an object moving in the north-south direction, because the angular velocity of the earth's rotation is constant, but the perimeter of the latitude line is changing, so the linear velocity is inconsistent, for example, the object moving south in the northern hemisphere deviates eastward due to entering the lower latitude with greater linear velocity (the deflection force of the east-west moving object is more complicated, so it is not considered for the time being). )

    So the magnitude of the geostrophic deflection force depends on the degree to which the circumference of the weft coil changes when the object passes at the same angle (i.e., distance) on the meridian line. What is clear is that the higher the latitude, the more parallel the ground is to the equator, the more obvious the change in the circumference of the latitude coil caused by the same north-south distance on the meridian, and the greater the geostrophic deflection force.

    The following is the first experiment to prove the geostrophic deflection force - Introduction to Foucault's pendulum (excerpt from Encyclopedia) The pendulum is a very interesting device. Give the pendulum a proper starting role, and it will always move in a certain direction, or a certain plane. If the pendulum angle is less than 5 degrees, the pendulum can even be regarded as a harmonic oscillator that moves in one dimension.

    Now, consider a simple scenario: what would happen if Foucault was placed at the North Pole? It is clear that the Earth is rotating – relative to distant stars. Similarly, due to inertia, the pendulum of the Foucault pendulum is invariant in the direction of motion (plane) with respect to distant stars.

    As you can imagine, there are three distant stars that have determined a plane and the Foucault pendulum moves exactly within this plane. Due to inertia, the pendulum is still moving in that plane when the earth and the frame used to lift the pendulum rotates) So what happened? If you stand on the surface of the earth near the Foucault pendulum, you will obviously notice that the plane of the swing is slowly turning, and it is turning at about half the speed of the clock hand, that is, every hour the Foucault pendulum will turn 15 degrees clockwise.

    Swing in the same plane, which is determined by distant stars, what if you put Foucault's pendulum on the equator? In that case, we won't be able to observe any rotation. Considering the motion of the pendulum as one-dimensional resonance (single pendulum), since its direction of motion is parallel to the Earth's axis, which is stationary relative to distant stars, we cannot observe the rotation of the Foucault pendulum relative to the ground.

  2. Anonymous users2024-02-10

    All places on the earth have the deflection force of the lead picking. (Blind).

    a.Wrong. b.Right.

    Correct Answer: False.

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