Elementary Math Does there any change in volume after an empty milk cup is flattened?

A: The volume of the empty milk cup changes when it is flattened. An empty milk cup becomes smaller when it is flattened.

It shows that volume is the size of the space occupied by an object, and the space occupied by an empty milk cup that is flattened becomes smaller.

Tell us that after the milk cup is empty, try to flatten it and throw it in the trash to reduce the space it occupies.

Volume refers to the space occupied by an object.

Volume refers to the space held by an object.

The volume does not change, the volume changes.

Hello! When the milk cup is empty, reduce the space it occupies.

Tell us. It shows that the volume is the size of the space occupied by an object, try to give it to be flattened and thrown into the trash, the space occupied by the flattened empty milk cup becomes smaller, and the volume of an empty milk cup becomes smaller after being flattened.

Mine, are you still satisfied?

It becomes smaller, the teacher said, if the volume is solid and hollow, the volume will shrink if it is flattened.

There's no change in volume, there's no increase, there's no decrease.

Volume refers to the space occupied by an object.

Volume refers to the space held by an object.

The volume does not change. The volume has changed.

A: The volume of the empty milk cup changes when it is flattened.

Rectangle square: v length = abh square: v positive = a rectangle area = length width height square area = edge length edge length edge length general formula: v = sh

Square (rectangle) area = base area height.

Perimeter, area, and volume of the graph:

Circumference (length of outer perimeter).

c = the sum of the three lengths.

c Rectangle = (length + width) 2

c parallelogram = 2 times the sum of the length of the two adjacent sides.

cSquare = side length 4

c diamond = side length 4

c circle = 2 r (r is the radius) = d (d is the diameter) c trapezoidal = two base lengths + two waist lengths.

Area s = base height 2

s rectangle = length and width.

s parallelogram = base height.

s square = square of the side length.

s diamond = half of the product of the diagonal.

s circle = r2 (r is the radius).

s trapezoidal = (upper bottom + lower bottom) high 2

The formula for calculating a cylinder is as follows:

Cylinder side area formula: side area = bottom perimeter height s side c bottom h cylinder surface area formula: surface area = 2 r2 + bottom perimeter s s table s bottom + c bottom h

Volume formula of a cylinder: volume = base area height v cylinder s bottom h volume formula of a cuboid:

The volume of the box = length x width x height.

If a, b, and h are used to represent the length, width, and height of the cuboid, the formula is: v length = surface area of the abh cube formula:

Surface area Ridge length Ridge length 6 s positive a 2 6

Volume formula for a cube:

The volume of the cube Ridge length Ridge length Ridge length

If a is used to denote the edge length of the cube, then the volume formula of the cube is v positive a·a·a a 3

The volume of the cone = 1 3 Bottom area High v Cone 1 3 s bottom h

The 2 adjacent faces have a common edge.

If one side is 19, then the sum of the other two sides is 11

11 is an odd number, so one on both sides is an odd number, the other is an even number, and the prime number of an even number is only 2

Then 11 = 2 + 9, 9 is not a prime number, it is not true.

So one side is 11

So the three sides are 2, 11, 17

So volume = 2 11 17 = 374 cubic decimeters.

Correct the question first: "209 cubic decimeters" should be "209 square decimeters".

We can connect the front of this cuboid with the top to see, it is a large rectangle that has been bent, decompose 209: 209 11 19, this is a unique decomposition, for 11 and 19, we can deal with it, can not be decomposed into the sum of two prime numbers, that is, the length, width and high height of the original cuboid, can be decomposed, after decomposition can get the other two, 11 can not be decomposed into the sum of two prime numbers, 19 can only be divided into the sum of prime numbers 2 and 17, obviously is the length, width and height of the original cuboid, At this point, its volume can be calculated: 11 2 17 374 (cubic decimeters).

Let's take a look at the three-step equation again:

11 2 17 374 (cubic decimeter).

Do you understand? Wishing you happiness and progress! Good bye!

Yes, it should be square decimeters.

First, let's list a series of prime numbers...

Let the three sides of the cuboid be x y z, and without defining which one is long, which one is wide, and which one is high, then the sum of the areas of any two adjacent areas is xy+yz=209

i.e.: (x+z)y=209

Launch y = 19 or 11

If y=19, it is impossible to achieve x+z=11 so y=11,x+z=19, so the three sides of the cuboid are respectively

The solid can be calculated to have a volume of 374 cubic decimeters.

The surface area is 486 square decimeters.

The increased surface area is exactly twice the base area of the cuboid (the two areas corresponding to the cross section), so the base area is 400 square meters, and the volume is 400*3=1200 square meters.

You only have to sawn 3 meters of wood into 2 sections, and you can see other methods to the known conditions.

800 2 3 = 1200 cubic meters.

The increased surface area is the sum of the areas of the two cross-sections, and the area of the cross-section of the cuboid is first found and then multiplied by its length.

Solution: (800 2) 3

1200 (cubic meters).

A: Its volume is 1200 cubic meters.

Method 1 is required.

4 2 5 10 (hours).

It also takes 10 4 6 (hours).

Method 2: Inject every hour.

It takes a total of 1 1 10 10 (hours).

It also takes 10 4 6 (hours).

Method 3: Inject every hour.

Injection is also required.

Also need 3 5 1 10 6 (hours).

Method 4 also requires injection.

Also need 3 5 2 5 4 6 (hours).

Method 5 was injected together.

600 2 5 240 (cubic meters).

Injected every hour.

240 4 60 (cubic meters).

A total of 600 60 10 (hours) is required

It also takes 10 4 6 (hours).

Method 6 was injected together.

600 2 5 240 (cubic meters).

Injected every hour.

240 4 60 (cubic meters).

Also to inject. 600 240 360 (cubic meters).

Also needed 360 60 6 (hours).

The known conditions are: length + width + height < = 150cm

By analogy with a rectangle, the closer the length and width are to the larger the area, and the same is true for the volume.

That is, when length = width = height, the volume is the largest.

Because the sum of length, width and height is 150cm.

So, the maximum volume is 50*50*50=125000cm3

The closer the length, width, and height, the larger the volume, and the maximum volume when the length, width, and height are equal.

150 3 = 50 cm.

50*50*50=125,000 cubic centimeters.

[and the same near large].

The sum is 150, and when the length, width and height are 50, the maximum volume is 125000cm 3

Length = width = height is the largest volume.

So 150 3 = 50

Volume = 50 50 50 = 125000 (cubic centimeters).

7*8*9=504cm, that is, the part with increased volume, the bottom area of the container is 12*7=84cm504 84 = 6, which is the height of the increase in the water in the container.

The volume of the iron block is 8*7*9=504 The rising volume is 504 and the base area is 12 so the rising height is.

8 times 7 times 9 divided by (7 times 12) equals 6, a rise of 6cm

Take the length as the axis.

Vulturex10x10x20=2000 vultures (cubic centimeters) with width as the axis.

This is a hypothetical question, suppose a cup of pure milk is 1, drink 30% of the left, fill up with water and add water, at this time milk accounts for the total cup, then the milk occupies 70% of the 50% of the 50%, that is, 1*50%*70%=, then the milk occupies the cup should be, that is, occupies 35% of the cup

35% of the first drink is gone, and 70% is left. Fill up the water and stir the milk to 70%, drink 50%, then drink half of the remaining 70% milk, that is, 35%. Then a total of 30% + 35% = 65% of the milk is drunk, so there is 35% milk left.

Suppose the capacity of the quilt is 100, drink 30, and leave 70 milk, add 30 water, and drink half of it, then drink 35 milk, and leave 35 milk, then the answer is 35%.

Milk is 1, drink more than once, drink more than once, and the answer is 35, which is 7 20.

Are you sure you just drank 50% of the last time without topping it up? That's 70%, you think a cup volume is 100 ml, then, the first time you drink 30, the remaining 70 ml, a total of 100 ml after filling, milk accounts for 70%, and drink 50% as long as it is not full again, the milk accounts for 70%, if it is full again, it is 35%, because, continuing from the description, there are 70 ml of milk left, and you drink half of it again and there is 35 ml left, and then fill up with water is naturally 35 percent!

1-30%=70%Regardless of whether it is full or not, drinking 50% accounts for half of the above 70%, that is, 70% 50%=35%, and the remaining milk in the cup is 35%.

If the last thing I say is milk, it's 50 percent

If you talk about pure milk, that's 35 percent.

Drink 30% and leave 70%.

Fill up with water and drink another 50%.

There are 35% left