A primary school application problem, an elementary school math application problem

-, although I am very dissatisfied with the attitude of the landlord, but let's solve this problem.

This problem can not be thought of very complicated, in fact, the step of exchanging money with the neighborhood can be directly omitted, just assume that the shoe store has 50 change, then the shoe store receives a 50 counterfeit banknote, so there is no income, and then look at the expenditure, the shoe store has to spend 29 yuan of change (this is a real banknote) and a pair of shoes, and the cost of shoes is 15 yuan, so 15 + 29 = 44, the answer is: Xiaomi Bu children's shoes store lost 44 yuan in this transaction.

This question is very simple, there must be a loss, you think about it from another angle, the neighborhood has no gain or loss, the young man got 15 yuan cost of shoes, and he also got 29 yuan, a total of 44 gains, then the shoe store lost 44

50 + 15 + 29 = 94 He gave 50 yuan to the neighbors, and he saved 50 yuan from his own loss, and then he gave a pair of shoes to others, and it was 15 yuan, and then he gave 29 yuan to others, adding up to 94 yuan.

And don't be so arrogant next time!!

Everything is wrong. You neglected to give him 50 for free when you changed the change.

I have two ways to do it:

1. Sequential method.

The whole process of financial entry and exit of the shoe store is as follows:

Dollar shoes (out).

2. Fifty fake money for young people, which is equivalent to 0 (in).

3. Give fifty to the neighbor in exchange for change, 0 (out).

4. The neighbor gave him 50 (in).

5. He made change 29 (out).

6. Return 50 (out) to the neighbor

In this way, the carry position is positive, and the output is negative, and it is calculated to be -44, so it loses 44 Second, the isolation method.

It can be seen as doing business twice.

1. Sold shoes and earned 6 yuan.

2. A person came to change the change, and he asked a neighbor to help him change it, but he lost 50 for the fake money, so 50-6=44, so he lost 44

It's no different from 100 yuan.

Isn't it the cost of 15 yuan + 29 yuan (for young people) = 44 yuan.

Neighbors ignore it for money. Disruptive audio-visual.

You must know that the neighborhood is just changing money. That is, the neighbors give 50 yuan to millet, and millet gives 50 yuan bills to the neighbors.

So this step can be completely ignored. It doesn't matter how much money you lose.

So the money lost is 15 + 29 = 44 yuan.

Excluding interference, the loss of the Xiaomi Bu children's shoe store has nothing to do with the neighborhood. It is equivalent to the young man buying a pair of his shoes for 15 yuan with a piece of waste paper, and he also gave this person 29 yuan, so he lost a total of 44 yuan.

Straight answer to the roll"

I think you're disgusting when you look at it, so I won't answer the question.

It's a bit of a big deal.

It's really unqualified.

If Lele gives Huahua 15 yuan, as much as Huahua, then Lele is more than Huahua: 15x2=30 yuan.

Lele turned out to be more than Huahua: 38 + 8 = 38 yuan.

If there are x roosters, then the hens have x+18 and the chicks have 78-(x+18+x)=60-2x

4x+3（x+18）+（60-2x）/2=138x=6

So there are 6 roosters, 24 hens, and 48 chicks.

Set x roosters, x + 18 hens, and 60-2x chicks. From the meaning of the question (60-2x) 2+3(x+18)+4x=138, 9 roosters, 27 hens, and 42 chicks were solved.

First of all, knowing that there are already 18 hens that have eaten 54 worms, 78-18 = 60 (only), 138-54 = 84 (only), then know that there are as many roosters as hens, let them be x, x+x+y=60 to get x=94x+3x+1 2y=84 y=42 hens: 78-9-42=27 (hens).

Answer: There are 9 roosters, 27 hens, and 42 chicks.

Let the number of roosters be x by the question 18 more hens than roosters Get hens (x+18) Let the number of chicks be y

Two equations are listed from the question.

2-1 yields 12x=108-x=9

x=9 into 1 to get y=42

Solution: male 9 female 27 small 42

Set: Rooster A, hen B, chick C.

a+b+c=78

4a+3b+c/2=138

a=b-18

b-18+b+c=78 2b+c=96 c=96-2b4(b-18)+3b+c/2=138 4b-72+3b+c/2=138 c=420-14b

96-2b=420-14b

b=27a=b-18

a=27-18=9

a+b+c=78

c=78-9-27=42

9 roosters, 27 hens, and 42 chicks.

If 1 11 of the number of male employees is elected, the number of male employees is divided into 11 shares, 1 share is elected, and 10 shares remain.

The remaining number of male employees is twice as large as the number of female employees, so that the remaining number of male employees accounts for 10 of the total number of employees, and the number of female employees accounts for 5 shares.

162+12) 6=29 (person).

29*5+12=157 (person).

A: There are 157 female employees in this factory.

（162+12）/[1/2x（1-1/11）]-162=174/[1/2x10/11]-162

157 people. A: There are 157 female employees in this factory.

Let the male worker be 1

Seeking male workers (162+12) [1-(1-1 11) 2]=319 Seeking female workers 319-162=157

Draw a line segment diagram for analysis.

1 (male worker) Female worker

X for male employees and y for female employees....x-y=162,x-(1/11)x=2（y-12）。。The solution is x=319 and y=157

(162+12) [1 2x(1-1 11)]-162=157 people.

A: There are 157 female employees in this factory

Landlord, take it For the sake of me being so patient in answering elementary school application questions, please

It can be solved this way.

Solution: Let's assume that B's deposit is twice as much as A's deposit after x months.

It can be seen from the title.

720+120x=2(500+50x)

720+120x=1000+100x

120x-100x=1000-720

20x=280

x=14A: After 14 months, B's deposit is twice as much as A's.