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It depends on what kind of data your atkj is.
If it's a row of data: it won't be 0 if you run it by your **
atkj=:1
atkj =
daynum=length(atkj);
portreturn=mean(atkj(1:daynum));
portrisk=std(atkj(1:daynum));
riskthreshold=[,portvalue=1;
valueatrisk=portvrisk(portreturn,portrisk,riskthreshold,portvalue)% The last semicolon is removed, so that the result can be displayed in the command window, if the semicolon is not removed, you can see the value % of vauleatrisk in the workspace in the upper left corner
valueatrisk =
0 %% run result.
If your data is not a row, but a two-dimensional matrix.
atkj = rand(10)%10*10 size.
atkj =
portreturn=mean2(atkj);% to calculate the mean of ATKJ, you can't use mean, if you use mean, you can average it by column, and the dimension of the final portreturn is 1*10%%.
portrisk=std2(atkj);In the same way as %std, std2 should be used to calculate the variance.
riskthreshold=[,portvalue=1;
valueatrisk=portvrisk(portreturn,portrisk,riskthreshold,portvalue)
valueatrisk =
0 %% run result.
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I don't really understand you either, but there is one thing: does your atkj have an assignment? Is there a program in front of you that you have missed?
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In MATLAB, a(i) =0 means:
Determine if the ith element of array a is not equal to 0, if it is not equal to 0, the result is true, otherwise it is false.
Analysis: a(i) represents the ith element in array a, and in MATLAB it means not, and = means not equal to (≠).
The following is an example: 1. Open MATLAB and enter the sample array in the command window.
a = -1:3
2. Determine whether the first element of a is not equal to 0: >a(1) = 0
Because the 1st element of a is equal to -1 and satisfies the condition that it is not equal to 0, the result is true and the result is displayed as 1
3. Determine whether the second element of a is not equal to 0: >a(2) = 0
Because the second element of a is equal to 0 and the condition that it is not equal to 0 is not satisfied, the result is false, and the result is displayed as 0
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