Come do yourself a favor ! 10 points!

Are all the books at home famous? It's very powerful, I think I was thirteen years old, and I haven't started reading **, I think, reading books is a step-by-step process, and it doesn't matter how many junk books you read, when you finish reading a type of book, you will turn to another type of book, so as to understand what a good book is, and it is not necessarily a famous book to read from the beginning, because you may not be able to understand it after reading it, but you will lose interest in famous books.

I suggest starting with "Campus**", if you have passed the stage of watching Campus**, you can try to look at "magic" and "fantasy" and the like, and then turn to "romance", and then you can read some books on "determination", as well as books with strong sorrow and joy in the book, I think it's okay. I'm 17 years old now, and I'm like this too, and I also like to watch ** when I was in junior high school, because of this, I also learned how to get along with good people, I rarely have a lot of things in my life, I don't quarrel with others, and I treat anyone very kindly, so I have the title of "good person".

It's a good idea to read some of the best books, such as Ostrovsky's How Steel is Made, Mark Twain's The Adventures of Tom Sawyer, and Gulliver's Travels, Robinson Crusoe.

These are all masterpieces, and the content is interesting, more attractive, and can increase knowledge and get closer to literature. You should love it

En Campus**, "Education of Love", "One Hundred Skirts", "23 Angel Street".

1) If a 0, then |a|=_a__,a|=_a__.If a 0, then |a|=_a_,|a|=a.

2) Fill in the conditions on the horizontal line to the right of the equation to make the equation true.

If |a|=a, then a 0 if|a|=-a, then a 0 2The following statement is correct: (a).

a.The absolute value of -a is a bIf |x|=-x, then x is negative.

c.The absolute value of a dIf x=-n , then |m|=|n|3.(1) The specified operation "circle addition" is: a circle plus b=a b+1, find the value of (-2) circle plus 3:

2) Circle plus 3=(-2)*3+1=-5

2) The specified operation "circle multiplication" is: a circle multiplied by b=a b+a+1, and the value of (-3) circle multiplied by 3 is found.

3) Circle multiplication 3 = (-3) * 3 + (-3) + 1 = -11

1.(1)a,a,0 according to when a=0, |a|=0

2)a>=0,a<

Note: In fact, the circle multiplication is customized, you just need to substitute the value.

Archetyping, +ing, archetypal, +s, difference, once, archetypal, archetypal, eating, skating

I don't understand the eighth question.

II, III

Solution: Set each ticket gate to pass 1 person per minute, then.

5*30 150 people.

6*20 120 people.

The number of new arrivals per minute is:

5*30-6*20) (30-20) 3 people.

The original number of people in line was: 5*30-3*30 60 people.

3 new arrivals per minute need 3 ticket gates to be free of strands;

The original queue required: 60 10 6 ticket gates.

So if you want to make 10 minutes disappear, then you need to open 3+6 9 ticket gates at the same time.

Equation solution: Before the ticket gate is opened, there are A passengers queuing, the number of passengers who come per minute during the ticket inspection is B, and C passengers can be checked per minute at each ticket gate, A+30B) 5C=30....a+30b=150c...1)

a+20b)/6c=20...a+20b=120c...2)

1)-(2), 10b=30c, b=3c

Substituting (1), we get a+90c=150c, a=60c

If you want to make the queue disappear for 10 minutes, you need to let (A+10B) passengers through the ticket gate within 10 minutes, and X ticket gates need to be opened at the same time.

a+10b)/xc=10...3)

a=60c, b=3c is substituted for (3), and it is obtained.

60c+3c)/xc=10

x=9 Analysis and solution: The number of passengers waiting for the ticket inspection is changing, "passenger" is equivalent to "grass", and "ticket gate" is equivalent to "cow", which can be solved by the solution of the cow grazing problem.

The total number of passengers is made up of two parts: one is the existing passengers who are already queuing before the start of the check-in process, and the other is the new arrivals after the check-in begins.

There is one ticket gate, and the number of people who can check in for one minute is 1. Because 4 ticket gates pass in 30 minutes (4 30) copies, and 5 ticket gates pass through 20 minutes (5 20), indicating that new arrivals (4 30-5 20) passes within (30-20) minutes, new arrivals are made every minute.

4 30-5 20) (30-20) = 2 (portions).

Suppose that the two ticket gates pass through the new passengers, and the two are offset, and the rest of the ticket gates pass through the original passengers, and the original passengers can be found.

4-2) 30 = 60 (servings) or (5-2) 20 = 60 (servings).

When opening 7 ticket gates at the same time, let 2 ticket gates pass exclusively through the new passengers, and the rest of the ticket gates pass through the original passengers, required.

60 (7-2) = 12 (points).

Time = 180 (16-12) = 45 minutes;

Helpful remember to praise, please re-post the question of the new question, thank you for this sleepy smile.