Ask for a simple biology problem Thank you

Updated on educate 2024-06-02
10 answers
  1. Anonymous users2024-02-11

    Bacteria, it seems that there are autotrophic and heterotrophic types, for example, cyanobacteria are autotrophic bacteria, and pathogenic bacteria are mostly heterotrophic types

    Lactose is a carbon base that is required for the growth of bacteria.

  2. Anonymous users2024-02-10

    There are heterotrophic and autotrophic types, most of which are heterotrophic and a few are autotrophic such as nitrifying bacteria.

    Can be used as a nutrient.

  3. Anonymous users2024-02-09

    Assimilation is divided into autotrophic and heterotrophic type, that is, the energy ** is different.

    Yes for microorganisms that can use lactic acid as a carbon source.

  4. Anonymous users2024-02-08

    Most of the bacteria are.

    Heterotrophic However, a small number of them are autotrophic.

    The autotrophic type is further divided into 1: photoautotrophic (such as cyanobacteria).

    2. Chemoautotrophic (e.g. nitrifying bacteria, denitrifying bacteria).

    The lactose in the medium provides energy and carbon for the metabolism of bacteria.

  5. Anonymous users2024-02-07

    Types of assimilation in bacterial metabolism: heterotrophic and autotrophic.

    Lactose added to the medium acts as a carbon source for bacteria to grow and reproduce.

    It seems to be the 2006 Beijing college entrance examination questions. It's also a simple biology problem. Sweat.

  6. Anonymous users2024-02-06

    Bacteria can be divided into heterotrophic and autotrophic types, and autotrophic types can be divided into chemoautotrophic and photoautotrophic types, such as nitrifying bacteria and sulfide bacteria belong to the chemoautotrophic type and cyanobacteria belong to the latter.

    The addition of lactose to the medium can not only provide the carbon source needed for bacterial growth but also provide energy, but the use of lactose requires bacteria to synthesize galactosidyltransferase, which belongs to the enzyme synthesis regulation in the regulation of bacterial metabolism, and lactose is an inducer.

  7. Anonymous users2024-02-05

    The template strand is g-c-a-g-t-a-c-c-g-c-g-t-c-c-t-c-a-t, so the sequence on the transcribed mRNA is: c-g-u-c-a-u-g-g-c-g-c-g-c-a-g-u-a-c-g-a-g-u-a

    An amino acid is determined by 3 codons, so the amino acid chain is: arginine-histidine-glycine-alanine-valine.

    If the DNA molecule is replicated, the type, number, and order of the bases in the newly synthesized daughter DNA molecule are the same as those of the parent DNA molecule, because (DNA replication follows the principle of complementary pairing of bases); And in the progeny DNA molecule, A = T, G = C, this fact illustrates (A is paired with T, C is paired with G).

  8. Anonymous users2024-02-04

    The template strand is g-c-a-g-t-a-c-c-g-c-g-t-c-a-t-c-a-t-g-c-g-c-g-g-c

    The protein is arginine-histidine-glycine-alanine-valine.

    DNA replication follows the principle of base complementary pairing: A is paired with T and C is paired with G.

  9. Anonymous users2024-02-03

    These two pairs of alleles are located on two pairs of homologous chromosomes" tells you that these two pairs of genes are completely independent and passed on without gene linkage.

    The genotype of F1 is VVSS

    Individuals in F2 who are different from the parental phenotype are heterozygous, and there are only two genotypes, vvss and vvss, which are 1 2 x 1 4 + 1 4x1 2 = 1 4.

    How to calculate the specifics, you look at the ** of the chessboard method on the textbook, I've been learning for almost 10 years, and I don't remember it very clearly.

  10. Anonymous users2024-02-02

    Two pairs of alleles are located on two pairs of homologous chromosomes, which tells you that the two pairs of genes are freely combined, and there is no chain effect.

    Individuals with different phenotypes of F1 gene VVSS and F2 are dominant and recessive (the parents here refer to the homozygous parents, and the limbs do not refer to F1), and the probability is 3 4 * 3 4 = 9 16, then the different probabilities are 1-9 16 = 7 16

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