I also have a physics problem, what to do, how to solve this physics problem

I think that's how physics is learned:

1.The most important thing is to listen to the class! The efficiency of listening to lectures often determines the grade of a person's grades!

It is also an important process for laying the foundation of a person. First of all, you have to do a good job of previewing, so that when you listen to the class, you can know that ** is the focus of listening, where there is no book and you should take notes (if you can't do the preview, then you are busy, you must listen to all the content of the teacher as much as possible, and you must write down all the knowledge you think is important.) In addition, doing these things well does not mean that the class is efficient, you must develop the habit of thinking, mobilize your thinking, develop a good habit of listening and thinking while listening to the class, and if you think for yourself and do not produce results, you must ask the teacher on the day and figure it out.

2.Reading is important! If you have a poor foundation, then you should study how each concept, conclusion, and formula is arrived at or understand it with your own thinking (of course, there are individual formulas that can only be memorized) If you want to have a good foundation, it is not enough to just keep doing questions and not connecting the knowledge points together.

Reading books can make knowledge form a system in your brain, not fragments, and the knowledge of the system is your capital to "adapt to change"! Know that there is a limit to what you can do.

3.Don't do it blindly! In the past, I watched others always do questions, some people looked at the answers, and some of the slightly better ones didn't analyze the answers, which is not good, and it is better to do a question than to deal with ten questions!

And you have to memorize those typical questions (which are typical for you, everyone's knowledge and thinking weaknesses are different), and if you have nothing to do, you can open them and fix your own loopholes, so that this question can only make sense. And, when you do the question, think about what it tests and why it does it. Also, there are a limit to the questions you can do, but there are a lot of questions that may be asked, so you should also develop the habit of "drawing inferences from one another", and after completing a question, think about what the questions will be similar to this question but different, or whether you can still do it without a certain condition, so that your question will naturally become broader.

4.Self-confidence is also important! Whether it is physics or mathematics, when doing problems, whether you are confident or not has something directly affects whether you can make a question, you can't be afraid of physics, especially when you take the exam, you are afraid, you will retreat subconsciously when you encounter a problem, this is not good, as for how to overcome, you have to start small, gradually develop the confidence to do the problem, you can't be in a hurry, you must first build your own brick by brick and then go to the high place.

I didn't do much physics, but I was the best in the class because I did all four of the above.

To learn physics well, you should read more books and accumulate extracurricular knowledge in physics. The most important thing is to understand the origin of each law, such as the leverage theorem, why is it the way it is? Hands-on experimentation is good for understanding the origin of the law.

So that you can remember it and be able to be impressed. In class, I listened carefully to the teacher's lectures, watched carefully when the teacher demonstrated, and reviewed them after class. When the teacher speaks, he uses his brain to think, and the experimental scene comes to mind.

If the teacher is not able to do the corresponding experiments in class, you can do it yourself at home. This way you can better grasp it. If you don't understand it, ask your teachers and classmates to understand it.

If you have been studying physics for a few years and have not yet mastered the previous knowledge, you should also turn over the previous physics books in your free time and study them carefully, read them carefully, and make up for the previous loopholes, so that you can learn the next knowledge.

Categories: Education Science >> Admission >> High School Entrance Examination Question Description:

E-bike mass (40 kg, mechanical energy efficiency 75%, working voltage 32v, speed <=20, cycling crisp class? The average resistance at 0 kg is 20 N) If the rider has a weight of 80 kg and travels at a constant speed of 36 km in 2 hours (1) Ask the work done by the electric bicycle to overcome the resistance within 2 hours (2) Ask the working current of the electric bicycle when driving at a constant speed.

Analysis: (80+40)*20*36000=total work.

Let the current be II*32*75%=(80+40)*20*36000 7200

1/2m/s^2

1/3m/s^2

Assuming that the maximum velocity at the bottom of the inclined plane is v, because of the uniform acceleration, the average velocity is v 2 so (4+6) m=10s*v 2, and find v=2m s so a1=v 2 (2*4m)=1 2m s 2a2=v 2 (2*6m)=1 3m s 2

The coefficient of friction of the ice surface is a, the mass of the object is m, and g is the acceleration due to gravity, then the acceleration of the object on the slope is (mg-mga) m=g(1-a), and the acceleration on the horizontal plane is -mga m=-ga

The time taken on the ice is t1, then there is g(1-a)t 2 2 = 4t 2 = 8 g(1-a).

t1 = root number [8 g(1-a).]

Similarly, the time on the horizontal plane is t2 = root number [12 ga] t1 + t2 = 10

The root number [12 ga

Root number [8 g(1-a).]

The root number [3 ga

Root number [2 g(1-a)

5 can be solved a, g is the acceleration of gravity,

It doesn't have to be so complicated, and it's easiest to use V-T images.

According to the area, the displacement is x1:x2=t1:t2=4:6, and t1+t2=10s, t1=4s, t2=6s;

Then there is a1= by x1=1 2*a1*t1 2

x2 = 1 2 * (-a2) * t2 2 (a2 is negative, reverse thinking) has a2 = -1 3m s 2

Solution: Since there is an endpoint velocity of 0, the equation 8=a1t1*t1*t1 can be obtained according to the kinematic formula s=at*t2

1)12=a2t2*t2

2)t1+t2=10

3) And because v=a1t1=a2t2

So (1) (2) gets: t2 = substitute (3) gets: t1 = 4s, t2 = 6s

4) Substituting (4) into (1) and (2) respectively obtains: a1 = 2m s2 a2 = 3m s2

--The previous answer is not good, I believe you will adopt me. Looking forward to ---

There are three non-extensible insulated light wires with a length of 1m, one end of two of them is fixed at the O point on the ceiling, and the other end is tied to the charged balls A and B with a mass of m=<-2>kg, their electricity is +Q and -Q respectively, Q=<-7>C, there is a third wire connected between A and B, and there is a uniform electric field of size E=<6>N C in the space, and the direction of the field strength is horizontal to the right, and ABO is in a regular triangle when equilibrium, A is on the left, and B is on the right. Now the line between the ob is burned, due to the air resistance A, the ball B will finally reach a new equilibrium position, and when the ball finally reaches equilibrium, the rope will be subjected to tension?

The electrostatic force of interaction between two charged spheres is not counted).

Calculate the volume v=

Then find the mass m = density * v

Then you do the math yourself.

Believe you can do it.

From the fall of the basketball to the touch of the ground, it is the ball.

Gravitational potential energy. Converted into kinetic energy.

From the basketball touching the ground to the downward movement of the old spine without regret, it is the kinetic energy of the ball that is shouted into blue infiltration.

Elastic potential energy. From the beginning of the upward movement of the basketball to the time it has not yet left the ground, it is the elastic potential energy of the ball that is converted into kinetic energy.

Bouncing upwards from the basketball after it leaves the ground, it is the kinetic energy of the ball that is converted into potential energy.

1. The gravitational potential energy is converted into kinetic energy.

2. Kinetic energy is converted into elastic potential energy.

3. The residual potential of the bullet is converted into kinetic energy.

4. Kinetic energy is converted into gravitational potential energy!

The uniform intensity electric field is vertically upward, (your diagram is drawn vertically downward, so let's do it vertically upwards with the title).

In the gravitational field, electric field, and magnetic field, the two forces of gravity and electric field must be balanced, which is the Lorentz force.

Do a uniform circular motion under it. (If it is not balanced, the resultant force will do work, and it must not be able to do uniform circular motion).

mg=qe, the direction of gravity is vertically downward, and the direction of electric field force is vertically upward, indicating that the charged particle m is positively charged.

The direction of the Lorentz force is always directed towards the center of the circle, and according to the left-handed rule, the direction of the circumnavigation of the particle m is counterclockwise. A correct.

As can be seen from the figure, the kinetic energy of the electric particle m does not change, and the gravitational potential energy changes, so the mechanical energy is not conserved. b error.

The work of gravity is zero during the time that the particle rotates for one revolution. c must be correct.

A is correct and D is wrong, not clockwise.

Answer: AC