Physics application questions. Pressure, physical pressure application problems

A ladder container is filled with water, the bottom area is 500dm2, the height is 15cm, and the mass of water is 20kg

1) The bottom of the container is subjected to pressure and pressure.

The pressure on the bottom of the container p=pgh=1000kg m 3*10n kg * pressure on the bottom of the container f=ps=1500pa*5m 2=7500n2) The pressure and pressure of the container on the tabletop.

The pressure of the container on the desktop p1 = g s = f s = 7500n 5m 2 = 1500pa

The pressure of the container on the desktop f1 = p1s = 1500 pa * 5 m 2 = 7500 n

1) Pressure = density * 10n kg * h = 1000kg cubic meter * 10n kg *

Pressure = pressure * force area = 1500pa 5 cubic meters = 300g2) pressure f = g = 300g

p=f/s=300g/5cm^2=60n

Pressure f=g=300g

That's how it should be

The formula was also forgotten

You're in junior high school, right?

I'm also in junior high school

Categories: Education, Science, >> Learning Aid.

Problem description: Li Ming and Wang Jun wanted to measure the length of a section of railroad at the same time, but they did not have a suitable ruler, they knew that the speed of sound in the air was 340 m s, and the speed in the steel iron was 5000 m s. So Li Ming stood at one end of the railway, Wang Jun stood at the other end, Li Ming knocked the railroad track with a hammer shaft, Wang Jun heard two sounds, the time interval between the two sounds was 2 seconds, find the length of this railway?

Miscellaneous calculations, the process is the most important, thank you! ~~

Analysis: Solution Known: V Fe 5000m s V Empty 340m SS=VT , T=S T

t'=t1-t2

t'=s v null s v iron.

i.e.: 2s s 340m s s 5000m ss=

Under the condition of ensuring safety, the maximum gravitational force that the ice surface can withstand is f=p*s=4*10 4*

Total mass: m=f g=

Cargo mass: m = 1600-200 = 1400kg

p=f s pressure = pressure area under force.

4x10⁴pa=(200+m)xg/

Suppose g = 10 n kg

So m = 1400kg

Note: I did the math by mouth, you can calculate it with your own calculator, hehe.

The weight is 50 kg, and because it is standing horizontally, gravity equals the pressure.

F pressure = g = mg = 50kg 10n kg = 500n

p=f/s=500n/400cm²=500n/

The student's pressure on the underside is equal to his gravitational force, f=g=mg=50, then the pressure on the ground with his feet on the underside is p=f s=490 (.

Pressure: The pressure of each foot is: 1500kg

Pressure: square centimeters.

Analysis: Knowing the speed of the car and the time it has been traveling, the car overtakes another bus, estimates the length of the bus, finds the relative speed according to the formula v=s t, and further finds the speed of the bus

Problem solving process: Solution: The length of the bus is close to 10m, taking the bus as a reference, the distance of the car is about 10m, the speed of the car relative to the bus v=s t=10m 5s=2m s=, and the speed of the bus is about 100km

If you don't have a suitable answer to this question, there must be something wrong with your question!

The particle moves in a straight line with uniform deceleration.

Each period is the same time, and the ratio of the 3 displacements is 5:3:1.

So the distance of the first segment is (36 9) 5=20

The bus is about 10m-15m long, so the relative speed is , so the speed is.

The mass of aluminum is equal to the density times the volume, ten cubic decimeters are equal to ten times ten negative cubic cubic meters, ten negative three cubic meters of cubic meters multiplied by density is equal to mass, the mass is calculated to be 27 kilograms, the gravity is 27 times the gravitational acceleration 10, which is equal to 270 Newtons, and 270 is greater than 240, so it cannot be pulled up.

There is no solution to this question.

b c d>100

If a then bus length = (28-10) x 5 = 90m is not possible.

a.Because all other speeds are greater than cars, cars can't overtake.