A few simple primary school questions, a few word questions elementary are simple

1.Two trains departing from two stations 465 kilometers apart at the same time, going in opposite directions, meeting 5 hours later, when one train travels 240 kilometers, find out how many kilometers per hour does the other train travel? (Column Equation Solution).

Solution: Let another train travel x kilometers per hour.

5x=465-240

5x=225

x=225÷5

x=45A: Another train travels 45 kilometers per hour.

2.Two baskets of apples weigh a total of 55 kilograms, if basket A is reduced by one-fifth, and basket B takes 1 kilogram, then the weight of the two baskets of apples is exactly the same, how many kilograms do the two baskets of apples A and B weigh respectively?

A: 54 9 5 = 30 (kg).

B: 55-30 = 25 (kg).

A: The apples in the first basket originally weighed 30 kilograms, and B weighed 25 kilograms.

3.If a snail climbs up from the bottom of a well, climbs 110 centimeters during the day and slides 40 centimeters at night, if it climbs exactly to the mouth of the well during the day on the fifth day, how deep is the well at least?

70 4 = 280 (cm).

280 + 110 = 390 (cm).

A: The well is at least 390 centimeters deep.

Another train travels in 5 hours: 465-240=225 km.

The distance traveled by the truck per hour is: 225 5 = 45 km.

Set frame A to be a kilogram, a-(1 5)a=55-a-1 substitution method to solve a=30, box B 25

From the title: the distance that a snail climbs up all day is 110-40 = 70 cm.

On the fifth day, it just arrived at the wellhead during the day, indicating that it took five days and four nights to reach the wellhead from the bottom of the well.

70*4+110=390 cm.

1.(465-240) 5=225 5=45 kmh.

2.If the apples in basket A weigh x kilograms, then basket B weighs (55-x) kilograms.

4/5x=55-x-1

9/5x=54

x = 30 B basket of apples weighs 55-24 = 31 kg.

3.(110-40) x 4 + 110 = 70 x 4 + 110 = 280 + 110 = 390 cm.

Solution: Let another train travel x kilometers per hour.

5x+240=465

x = 45 solution: Let the basket have x kilograms.

x=45 solution: (110-40) 5=350

1. x*5 + 240 = 465

The solution is x=45

2.The original weight of the basket was x kg (x- x 5) +1 + x = 55

The solution is x=30 30 kg for basket A and 25 kg for basket B.

3. 110 * 5 - 40 * 4 =390 cm

1.Let the other car travel x per hour

5x=465-240

x=452.Let A weigh x and B 55-x

4/5x=55-x-1

x=30 B: 55-30=25

3.The snail climbed for a total of 5 days and 4 nights Well depth: 5 110-40 4 = 390 to seek, give the best...

Question 1 v=(465-240) 5

Question 2 Let the basket have x kilograms and the equation x-(1 5)x=55-x-1 can be obtained

Question 3 h=(110-40)*4+110

1 question: 45 km/h.

Question 2: A 30 kg B 25 kg.

3 questions 390 cm.

1) 82) 10, 11, 12, 13, 14, 153) measure the thickness of 200 sheets of white paper, and divide by 200

,11,12,13,14

3. Measure the thickness of 200 sheets of white paper, and divide it by 200 (the number of sheets that are easy to count, and the thickness that is easy to cut).

The sum of five consecutive natural numbers is 60, what are the five natural numbers?

The original sum of the two numbers A and B is 52

Grandpa Li's family raised 284 sheep, of which the number of big sheep was 3 times the number of small sheep, and how many big sheep and small sheep each were

Using the backward method, the car at station B is twice that of station A, and if A is unit one, B is the share, a total of 1+ copies.

135 Explain that A is 54 and B is 135-54=81 Then, it says that 36 cars from station B to station A, and then 45 cars from the existing cars at station A to station B, which is equivalent to 45-36 cars from A to B = 9 cars.

54 + 9 = 63 cars.

If there are x cars at station A, then there are 135-x cars at station B, and 36 cars are driven from station B to station A, and then 45 cars are driven from the existing cars at station A to station B, then the vehicles at station A are x+36-45=x-9

At this time, the number of vehicles at station B is 135-x-36+45=144-x(144-x) (x-9)= x=63, then the number of vehicles at station B is 135-x=72

X cars were parked at station A (if there are 36 cars from station B to station A, and then 45 cars from the existing cars at station A to station B), that is, station B with 9 cars from station A, (135 x+9) (x 9) = x=63

If there are x cars at station A, then there are 135-x cars (136-x-36+45) at station B

145-x=

x=63,4 is rounded. x=63

In this question, the data design is not standard, but if you know how to do it, the key is to calculate the number of incoming and outgoing trains at each station, and you can't miss the calculation.

Solution: There were X cars parked at the first station. then the existing (x+36-45), station B existing (x+36-45).

x+36-45）+（x+36-45）×

x+36-45）×

x+36-45=135÷

x+36-45=54

x=54+45-36

x=63 station B originally had: 135-63=72 (vehicles).

Suppose station A has x and station B is 135-x, then: (135-x-36+45) (x+36-45) = x=63, and station B is 72

10 2 = 240 cubic centimeters.

A: The volume of this stone is 240 cubic centimeters.

2 = 300 square decimeters, then the bottom area is 300 square decimeters, 300 20 = 6000 cubic decimeters.

A: The volume is 6000 cubic decimeters.

1.There is a rectangular piece of paper, 56cm long and 24cm wide, cut it into small squares of the same size, what is the maximum possible side length of these small squares?

A: The greatest common factor of 56 and 24 is 8, so the maximum side length of these small squares is 8cm

2.The area of a rectangle is 72 square centimeters, and the length and width of the rectangle are known to be only a common factor of 1. What is its length and width? (length is not a multiple of width).

A: Its length is 9 cm and its width is 8 cm.

3.Bei Bei folded a rectangular piece of paper in half left and right, and then folded the folded paper up and down, and then folded left and right in half, a total of three times, what is the shape of the folded paper? What is a fraction of the area of the original rectangle? Thank you.

Answer: The folded paper is rectangular, and the area of the folded figure is one-eighth of the original rectangular area. （1/2×1/2×1/2=1/8）

If you have reached the length limit, you can still enter 9999 words.

1 56, 24 8 cm.

A: These small squares may have a maximum side length of 8 centimeters.

Because the length and width of a rectangle are only a common factor of 1, and length is not a multiple of width, the length and width of this rectangle can only be 9 cm and 8 cm.

3 The shape of the paper folded in half three times is rectangular, and the area is 1 8

1. The maximum side length is a small square of 24 cm.

1 72 = 2 36 = 3 24 = 4 18 = 6 12 = 8 9, of which only 8 and 9 are a pair, so the length is 9 cm and the width is 8 cm.

3. It's still a rectangle. Fold it in half once, and the area is half of the original, i.e., 1 2;Fold it in half again, then the area is the original 1 4, and after the third fold, the area is the original 1 8.

1. 8cm。 2.8 and 9 3.The small rectangle is one-eighth of the original.

Question 1: 8cm

Question 2: 8 and 9

Question 3: Rectangle or square; Eighth.

If the original length and width ratio is 2:1, it ends up square.

If the original aspect ratio is not 2:1, it will end up rectangular.

Not sure if that will help you.

1) 56 24=1344 (cm) 1344 4 = 336 (cm) I don't know if it's right.

3) It is rectangular. It's 1 out of 8

Don't blame me for being wrong.

1 24cm

3 or rectangular is the original 1 8