A middle school organizes a spring outing for junior high school students

1. The original plan was to rent 45 passenger cars N, according to the title of the column 45N+15=60 (N-1), the solution was n=5, and the number of students was 60 (N-1) = 240.

2. If you rent a 45-seater car, you need to rent 6 cars, and the total rent is 220 6 = 1320 (yuan) If you rent a 60-seater car, you only need to rent 4 cars, and the total rent is 300 4 = 1200 (yuan), and it can be seen that it is more cost-effective to rent a 60-seater car.

A middle school organized a spring outing for students, and originally planned to rent a number of 45-seater buses, but 15 people did not have seats; If you rent the same number of 60-seater buses, there is one more car, and the rest of the buses are just full, it is known that the daily rent of 45-seater passenger cars is 220 yuan, and the daily rental of 60-seater passenger cars is 300 yuan

1) There are a total of 240 students on the spring outing, and it was originally planned to rent 5 buses with 45 seats

2) If you rent the same kind of car, so that every student has a seat, renting a car is more cost-effective, your car rental plan is:

Solution: (1) A total of x students participated in the spring outing, and it was originally planned to rent 45-seater passenger cars

According to the meaning of the question, we get 45y+15=x60(y-1)=x, and solve this system of equations, we get x=240y=5

A: There are 240 students on the spring outing, and it was originally planned to rent 5 45-seater buses

2) Rent a 45-seater bus: 240 45 cars), so you need to rent 6 cars, and the rent is 220 6 = 1320 (yuan);

Rent a 60-seater bus: 240 60 = 4 (cars), so you need to rent 4 cars, the rent is 300 4 = 1200 (yuan).

A: It is more cost-effective to rent 4 60-seater coaches

Set up to rent 45-seater car x cars.

45x+15=60*(x-1)

Solution x = 5 cars.

Number of students in grade 7 = 45 * 5 + 15 = 240 students.

For example, renting a 60-seater car needs = (5-1) * 300 = 1200 yuan, and renting a 45-seater car needs = (5 + 1) * 2200 = 1320 yuan, so it is more cost-effective to rent 4 60-seater cars.

Set rent x 45x+15=60x-60x=5 There are 240 students Rent 4 cars with 45 seats plus 60 seats Cheaper A middle school in Dongpo, Huanggang City, organized a spring outing for seventh-grade students, and originally planned to rent a number of 45-seat buses, but there were 15 people.

Set rent x45x+15=60x-60

x=5 There are 240 students.

It's cheaper to rent 4 cars with 45 seats and a 60 seats.

Set rent x45x+15=60x-60

x=5 There are 240 students.

It's cheaper to rent 4 cars with 45 seats and a 60 seats.

A middle school organized a spring outing for students, and originally planned to rent a number of 45-seater buses, but 15 people did not have seats; If you rent the same number of 60-seater buses, there is one more car, and the rest of the buses are just full, it is known that the daily rent of 45-seater passenger cars is 220 yuan, and the daily rental of 60-seater passenger cars is 300 yuan

1) How many students are there in the spring outing, and how many 45-seater buses are originally planned to be rented?

2) If you rent the same kind of car, so that every student has a seat, how to rent a car more cost-effective Test point: Application of the binary linear equation prudential group Analysis: (1) The equivalence relationship in this question is:

45 Number of 45-seater passenger vehicles + 15 = total number of students, 60 (number of 45-seater passenger vehicles -1) = total number of students, according to which the first problem can be solved by a system of equations;

2) It is necessary to calculate the respective rentals of 45-seater buses and 60-seater buses respectively, and then choose after comparison Answer: Solution: (1) A total of x students participating in the spring outing were set up, and the original plan was to rent 45-seater buses y

According to the question, de, solve this system of equations, get

A: There are 240 students on the spring outing, and it was originally planned to rent 5 45-seater buses

2) Rent a 45-seater bus: 240 45 cars), so you need to rent 6 cars, the rent is 220 6 = 1320 (yuan), rent a 60-seat bus: 240 60 = 4 (cars), so you need to rent 4 cars, Heng Xiaoliang rent is 300 4 = 1200 (yuan).

Answer: It is more cost-effective to rent 4 60-seater buses Comments: When renting a car, it is most important to use one after the wider, no matter how many people have to use one, so when calculating the number of cars, use the "finishing method" instead of "rounding".

1) There are x number of students.

x-15)/45=(x/60)+1

x = 240 people.

The original plan was to rent the vehicles of Xun Shouxin as (240-15) 45 = 5 vehicles, 2) set up to rent 45 vehicles per mu x vehicles.

Fully rent a 45-seater car: 220 * (5 + 1) = 1320 yuan, full rent 60-seater car: 300 * (5-1) = 1200 yuan< 1320 yuan rent 4 45-seater cars, 1 60-seater car per mu wheel, just full, 220 * 4 + 300 * 1 = 1180

Therefore, it is appropriate to rent 4 45-seater cars and 1 60-seater car.

What to ask? Q: Which pants are suitable for rent?

If there are a number of cars, there is x.

45x+15=60(x-1)

x=5, then renting a 45-seater car Yeji Chonghua needs 6 cars Rent Song J = 6 * 220 = 1320 yuan.

If you rent 60 seats, you need 4 cars Rent = 300 * 4 = 1200 yuan.

Got it.

1) If there are 45 ground cars x cars, then 60 seats will be obtained from the question and there will be (x-2) cars 45x+30=60*(x-2).

Get x = 10 so there are 480 people on the first day of junior high school, and the original plan is to use 10 cars with 45 seats 2) Set up 45 seats with ground rent x cars and 60 seats y cars, and the total rent w yuan is required 45x + 60y = 480

w=220x+300y

When x=8 y=2, w has a minimum value of =2360

（1.Set 45 seats for x cars.

45x-30=（x-2）*60

x=6 for 45x-30=240 people

2）.Three methods:

1.All 60 seats: 240 60 300 = 4 300 = 1200 (yuan) 2

All 45 seats: 240 45 = 5 (cars)...15 (persons), 6 cars:

5+1) 220=1320 (yuan).

3 Mixed: 1 car 45 seats 4 x 60 seats (not possible) becomes: all 60 seats (as above) 2 x 45 seats 3 x 60 seats:

2 220 + 3 300 = 13403 45 seats 2 60 seats: 3 * 220 + 2 * 300 = 12604 cars 45 seats One 60 seats: 4 220 + 300 = 11205 cars 45 seats 1 car 60 seats:

5 * 220 + 300 = 1400 A: 4 cars with 45 seats and one car with 60 seats are the most cost-effective.

1) If there are 45 ground cars x cars, then 60 seats will be obtained from the question and there will be (x-2) cars 45x+30=60*(x-2).

Get x = 6 (cars).

6-2) 60=240 (person).

2) All 60 seats: 240 60 300 = 4 300 = 1200 (yuan) All 45 seats: 240 45 = 5 (vehicles).15 (person) (5+1) 220=1320 (yuan).

Mixed: 4 cars with 45 seats, one 60 seats, 4 220 + 300 = 1120 (yuan) Answer: 4 cars with 45 seats, one 60 seats The most cost-effective.

(1) Set up to rent x vehicles.

45x-30=60x-120

90=15x

x = 6 six cars.

6 45-30 = 240 (person).

2) All 60 seats: 240 60 300 = 4 300 = 1200 (yuan) All 45 seats: 240 45 = 5 (vehicles).15 (person) (5+1) 220=1320 (yuan).

Mixed: 4 cars with 45 seats, one 60 seats, 4 220 + 300 = 1120 (yuan) Answer: 4 cars with 45 seats, one 60 seats The most cost-effective.

1...Let the 45-seater car be x, and the title will give 45x-30=(x-2)*60 x=6, and the number of people will be 45x-30=240

2...45 passenger cars 6 60 passenger cars 4 The price of 45 by the question is 1320 yuan 60 The price is 1200 yuan So 45 passenger cars should be rented.

1.The number of students is 480,, 10 cars.

2.The first option rents 10 45-seater buses at a cost of 2,200

The second type rents 8 60-seater coaches and costs 2400Obviously, the first option is more cost-effective.

There were a total of 240 people, and they originally planned to rent 6 taels. Rent 4 taels of 45 seats, a 60 seats is the most cost-effective.

(1) The total number of people exceeds 100, and the total number of people is 120.

2) 45 students in 7th grade and 75 students in 8th grade.

The process is as follows. There are x people in the seventh grade and y people in the eighth grade.

First of all, because when purchasing tickets separately, the ticket price paid by the seventh grade is 15 yuan for the person and the ticket price paid by the eighth grade is 12 yuan.

15 * x + = 1575, that is, x + = 105x + y > x + 105, so the total number of people is more than 100 people Since the total number of people is more than 100 people, the ticket ** is 9 yuan, and you need to pay 1080 yuan to buy tickets together, there are x + y = 1080 9 = 120, that is, the total number of people is 120 people.

From above, = 15, i.e. y = 75, x = 120 - 75 = 45

Hope that helps.

The process is as follows.

There are x people in the seventh grade and y people in the eighth grade.

First of all, because when purchasing tickets separately, the ticket price paid by the seventh grade is 15 yuan for the person and the ticket price paid by the eighth grade is 12 yuan.

15 * x + = 1575, that is, x + = 105x + y > x + 105, so the total number of people is more than 100 people Since the total number of people is more than 100 people, the ticket ** is 9 yuan, and you need to pay 1080 yuan to buy tickets together, there are x + y = 1080 9 = 120, that is, the total number of people is 120 people.

From above, = 15, i.e. y = 75, x = 120 - 75 = 45

Hope that helps.

If the number of seventh-grade spring outings is x, and the original plan was to rent a 45-seater passenger car y, then 45y=x-10

60(y-1)=x+5

Solution: x=235, y=5

That is, the number of seventh-grade spring outings is 235, and it was originally planned to rent 5 45-seater buses.