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Anonymous users2024-02-114xπⅹ4^3)/3÷（4ⅹπx2^3）/3
4πⅹ4^3）/3x3/（4πx2^3）
Answer: A solid ball with a radius of 4cm is 8 times the volume of a solid ball with a radius of 2cm.
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Anonymous users2024-02-10The volume of the ball v (4 3) r, so the volume of a ball with a radius of 4 cm is 8 times that of a ball with a radius of 2 cm.
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Anonymous users2024-02-09Observe the volume formula of the sphere first, <>
It can be seen that it is related to the square of the radius, that is, r, so if the radius changes from 4 to 2, then the sphere will change from 3 4 4 to 3 4 2 The 3 4 in front of it is unchanged, just look at the relationship between 4 and 2, it can be seen that 4 = 2 4 Therefore, the radius is 4cm is the volume of the solid sphere is 4 times the volume of the solid sphere with radius of 2.
This question tells us that the comparison of spheres can directly observe the radius, but the actual comparison is the square of the radius, remember not to forget that it is the square of the radius.
Thank you.
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Anonymous users2024-02-08Surface area = 4 vulture macro bend r 2 = 4 vulture * (4) 2 = 64 vulture
Volume = 4 vulture liquid r 3 3 = 4 * vulture * 4 3 3 = 256 vulture section stuffy 3
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Anonymous users2024-02-07Because the surface of the ball is s=4 r = 4 square centimeters, and the volume is v=4 r 3=4 cubic centimeters.
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Anonymous users2024-02-06According to the meaning of the question, the volume of the ball v=(4 3) r, so, v=4 accompanies 3 1 2 2) =4 3 1 =4 3 family width cm), rounded, keep the two decimal places of the reed), Answer: The volume v of this ball is equal to, thank you!
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Anonymous users2024-02-05The diameter of a large sphere is 2 times that of a small sphere, so the volume is several times that of a small sphere.
v=(pi*d 3) 6 The diameter is twice that of the original stool, and the volume is 8 times that of the original, so the diameter of the large sphere is twice that of the small sphere of crude lead, and the volume of the large sphere is 8 times that of the small sphere.
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Anonymous users2024-02-04Summary. The formula for the volume of the ball is: $v = frac pi r 3$, where $r$ is the radius.
The volume of the ball is: $v = frac pi r 3$, where $r$ is the radius. When the radius is extended and rolled by 2mm, the new radius is $, that is, $ meters.
v_2 = frac\pi ( approx \text$。The increase in volume is: $ delta v = v 2 - v 1 approx text$.
Thus, the volume of the ball increases by about $ cubic meter.
Can you tell us more about that?
The volume of the ball is: $v = frac pi r 3$, where $r$ is the radius. When the radius is extended and rolled by 2mm, the new radius is $, that is, $ meters.
v_2 = frac\pi ( approx \text$。The increase in volume is: $ delta v = v 2 - v 1 approx text$.
Thus, the volume of the ball increases by about $ cubic meter.
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Anonymous users2024-02-03Surface Area:
s = 4 r = 4 9 = square meters.
Volume: v = 4 3 r = 4 3 27 = cubic meters.
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Anonymous users2024-02-02The area is 36 pies, and the body.
The product is also 36 factions.
Throwing a solid ball is not only by arm strength, but also by waist and abdominal strength, it is too important, there are four throwing events, javelin, shot put, discus, hammer throw, which do you imagine can go out dozens of meters only by arm strength? Put all your strength into it. In fact, it is very simple, you hold the solid ball high with both hands, stand in lunges before and after, the distance between the front and rear feet is half a meter, and the upper and lower backs are leaned to the limit position, that is, the waist is almost unbearable, this is called a reverse bow, and then suddenly tuck the abdomen, both hands only need to throw the ball forward, and the angle of the shot is about 50 degrees.
Concrete covering.
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