In the chemical equation in which potassium permengate is used to produce oxygen, which is the oxidi

Potassium permanganate produces oxygen, KMNO4 is both an oxidizing agent and a reducing agent, the oxidation product is oxygen, and the reduction products manganese dioxide and potassium manganate.

KMNO4 is both an oxidizing agent and a reducing agent, the oxidation products are oxygen, and the reducing products manganese dioxide and potassium manganate.

This is because the valency of MN is reduced, so potassium permanganate is an oxidant, a reduction product of potassium manganate and manganese dioxide.

The valency of oxygen increases, so the reducing agent of potassium permanganate, oxygen is an oxidation product.

Potassium permanganate is heated to obtain oxygen, manganese dioxide and potassium manganate. If the mn valency of potassium permanganate decreases and the valency of oxygen increases, potassium permanganate is a reducing agent even if it is an oxidant.

Potassium permanganate decomposes, it is both an oxidant and a reducing agent, and the manganese element is oxidized from positive heptavalent to positive hexavalent potassium manganate and positive tetravalent manganese dioxide, and the oxygen element is reduced from negative bivalent to zero valence in oxygen.

The decrease in the Mn valency in KMno4 is an oxidant, and the increase in the valency of O is a reducing agent. It can be understood that Mn is an oxidizing agent and O is a reducing agent, but they are both in the same molecule, so KMno4 is both an oxidizing agent and a reducing agent.

Potassium permanganate is both an oxidizing and reducing agent.

2kmno4==△==k2mno4+mno2+o2↑

In this reaction, the Mn valency in KMno4 decreases and the O valency increases.

Potassium permanganate undergoes a redox reaction on its own, which is both an oxidizing agent and a reducing agent.

Potassium permanganate itself is both an oxidant and a reducing agent, and only it is gaining and losing electrons in this reaction!!

Is it a heating reaction? Self-decompose that? He himself is both an oxidizing agent and a reducing agent

When potassium permanganate is used as an oxidant, its reduction products are different due to the acidity and alkalinity of the medium, and manganese ions are often generated in acidic environments, and manganese dioxide is generated under alkaline or neutral conditions. Tung kernel chain.

Potassium permanganate has strong oxidizing properties and is commonly used as an oxidizing agent in laboratories and industries. It is highly oxidizing in acidic media and usually generates divalent manganese ions. In alkaline or neutral solutions, it is not as oxidizing as in acidity, and usually produces manganese dioxide.

Take the reaction of potassium permanganate with hydrogen peroxide as an example:

Alkaline or neutral environment to generate manganese dioxide:

Manganese ions are generated in an acidic environment:

Potassium permanganate. When used as an oxidant, the acidity and alkalinity of its reduction products and system.

There is a certain relationship:

1. The reduction product of KMno4 in acidic argument solution is Mn2+ ions;

2. The reduction product of KMno4 in alkaline solution is dark green K2mnO4 like a stove beam;

3. The reduction product of KMno4 in a neutral environment is MNO2.

Hello, sorry for your question. 1. Manganese dioxide is used as a catalyst to produce oxygen from potassium chlorate, and potassium permanganate does not need a catalyst. 2. The potassium permanganate device is plugged with cotton at the mouth of the test tube to prevent potassium permanganate powder from entering the trachea.

3. Potassium permanganate begins to decompose at 240 °C, while potassium chlorate has a melting point of 356 and a decomposition temperature of 400, and the melting temperature of potassium chlorate is smaller than that of Jeollin. I hope to be able to help you with Ma Hongzheng, thank you

All of the changes in the valence state of an element are redox reactions.

It is the reducing agent that has an elevated valency.

It is oxidized. It is the oxidant that decreases in valency, which is reduced.

Potassium permanganate. It is both an oxidizing agent and a reducing agent, because the atomic valency in potassium permanganate is both high and reduced.

This anti-group move should be a self-redox reaction.

2kmNO4===K2mNO4+MNO2+O2 (conditional heating, and gas symbol).

Manganate mno42- (manganese positive 6-valent).

Permanganate MNO4- (manganese positive 7 valent).

Summary. The valency of the change is therefore a redox reaction Is the reaction of potassium chlorate to oxygen a redox reaction.

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Prepare the oxygen equation, heat potassium chlorate: 2kclo3 heat 2kcl + 3o2 (the principle of oxygen production in the laboratory.

The valency of the change is therefore a redox reaction

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In all acids, hydrogen ions have unbalanced oxidation, so only the acid radicals need to be considered to be reducible.

Oxidant leakage refers to a substance that gains electrons in a redox reaction.

Correspondingly, substances that lose electrons are called reducing agents. In a narrow sense, oxidizing agent can also refer to a substance that can make another substance obtain oxygen, and so on, fluorinating agent is a substance that can make a substance obtain fluorine, and the same is true for chlorinating agents, brominating agents, etc.

Note: There is a difference between the two definitions, with the former emphasizing the gain and loss of electrons, while the latter emphasizing the gain and loss of oxygen. According to the former definition, some substances such as xenon difluoride are strong oxidizing agents, while according to the latter definition, they are fluorinating agents. This entry mainly describes the former, which contains substances that are easy to obtain electronic elements, that is, substances with strong oxidizing properties are commonly used as oxidants.

The electron-gaining property of the oxidant is called oxidation, the determining factor of oxidation is the electron-gaining tendency of the ** state element in the substance, in the solution, according to the electric double-layer theory, the magnitude of oxidation is reflected as the standard hydrogen electrode potential of the oxidant, the higher the potential, the stronger the oxidation, the lower the potential, the weaker the oxidation, correspondingly, the stronger the reduction of the reduced state.

Answer] :(1) Raw teasing and dismantling into oxide mountain roll 4k+o2===2k2

o；2) Generate 2K+O2 of the Royal Digging Oxide

=k2o23) to form superoxide k+o2

=ko2

2kmNO4 heats K2mNO4 Mno2 O2

Only potassium permanganate is used to produce oxygen, and potassium permanganate does not react with oxygen, because both of them are oxidants and cannot be used to produce socks.

2kmNO4 heats K2mNO4 Mno2 O2

2kclo3 +mno2= 2kcl + 3o2

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2kmno4=k2mno4+mno2+o2;Heating symbol and gas rising symbol, the landlord added it himself, I can't enter it, I hope it works.

2kmNO4 = mNO2 + K2mNO4 +O2 (Condition: Heating).

2kClO3=2kCl+3O2 (Conditions: Heating, MnO2 catalyst).

2kmNO4==K2mNO4+O2+MNO2 (the condition is heating).

2kClO3 = 2kCl + 3O2 (conditions are heating and mNO2).