6th grade learning problems, 6th grade prone problems

Looking down is "looking down", Focused is "staring", Looking around is "looking around", Sneaking is "peeping" The greatest common divisor of 36 and 48 is 12, and the least common multiple is 144

The greatest common divisor of 13 and 5 is 1, the least common multiple is 65, the greatest common divisor of 15, 30, and 90 is 15, and the least common multiple is 90

The greatest common divisor should be 1Because 13 is a prime number. Only divisible by 1 and 13.

The common multiple may be that you multiplied it yourself.

There is no common divisor (except 1).

The least common multiple is their product, both 4548960000

The greatest common divisor is 1

The least common multiple is 9360

Greatest common divisor: The common divisor of several numbers is called the common divisor of these numbers, and the largest one is called the greatest common divisor of these numbers.

Least common multiple: The common multiple of several numbers is called the common multiple of these numbers, and the smallest one is called the least common multiple of these numbers.

The original words on pages 66 and 72 of the tenth volume of the mathematics book of the six-year primary school of the People's Education Edition) 36 48 Greatest common divisor: 12 Least common multiple: 12*12=14413 5 Greatest common divisor:

1 Least common multiple: 13*5=6515 30 90 Greatest common divisor: 15 Least common multiple: 90

What I heard: Problems that children in the sixth grade tend to have and how to deal with them.

The sixth grade is the highest grade of primary school, and the children's psychology, physiology, range of activities, communication style, and learning requirements have changed greatly. The learning state is relatively impetuous, the subjective consciousness is significantly enhanced, the self-restraint ability is relaxed, and the sense of respect for teachers of individual children is weak.

Common questions for 6th graders are:

1. High incidence of school boredom.

2 Unstable psychological development during adolescence.

3.Obsessed with electronics.

Countermeasures: 1. Pay attention to the learning process and help children learn efficiently.

1. Pay attention to your child's learning process and understand the dynamics of learning. The process is more important than the result. Keep an eye on your child's learning process.

2. Create a good family atmosphere. Parents should create a good learning atmosphere and do not chat loudly, watch TV, etc. In addition, parents should reasonably arrange some activities that their children are interested in to relax and decompress.

2. Pay attention to children's physiological and psychological changes, and pay attention to adolescent education.

Parents should move from the role of mentor in the past to companion and guide.

1. Pay attention to your child's physiological changes.

2 The gender consciousness of the children in the sixth grade began to awaken, and the children had a hazy good feeling for the opposite sex, but this was not called love at all, it was just a hazy good feeling. At this time, their gender consciousness begins to awaken. The child begins to have a curiosity about the opposite sex, so he begins to desire to understand and approach the opposite sex.

Be sure to tell your child the boundaries of interaction between male and female classmates, so that children can establish a healthy concept of making friends from an early age.

3. Pay attention to children's mental health education. Parents should not only pay attention to their children's physical health, but also pay attention to their children's mental health. Parents should lead by example, teach by example, guide their children to learn to be tolerant and kind, and educate their children to never say mean things and not talk about others; Efforts should be made to cultivate children's sense of autonomy, ability to live independently and deal with things independently; It is necessary to guide children to turn "crisis" into "opportunity", so that children can face difficulties and setbacks, make them opportunities for growth, improve children's courage quotient, and improve frustration tolerance; It is necessary to pay attention to life education, cultivate children's health quotient, let children establish a correct view of life and death, and cultivate children's survival intelligence.

3. Parents should guide them scientifically to make their children surf the Internet healthily.

1 Parents should lead by example.

2 Satisfy your child's inner desires.

3. Make your child fall in love with reading. For children, the atmosphere of the family is very important. Parents should create a learning family and a reading family for their children. Parents should not only let their children have books to read, but also let their children read books.

4. Arrange abundant entertainment activities.

5. Guide your child to follow the rules.

What comes to mind: the importance of positive guidance and companionship from parents. Sixth grade is a crucial year for parents to accompany and encourage their children.

1 hour = 3600 seconds. The diameter of the water pipe is 2 dm = m, radius = m.

Calculate how many cubic meters in 1 hour - 500 meters of water in the water pipe = how many cubic meters of water is pumped to the water tower.

Calculation of total pumped volume: cubic meters;

Calculate the water in the pipe for 500 meters: cubic meters;

Calculate the amount of water actually pumped into the tower: cubic meters.

Set: The speed of the fast train is x, and the speed of the slow train is y

x +y=960/6

10x=960

Solution x gets 96, and y gets 64

Knowing the speed of the slow train, after that, the trouble LZ is forgotten. Mathematics is do-it-yourself.

Question 1: The cross-sectional area of the water pipe is = (square meters, 1 hour = 3600s, the length of the water flow = 3600s * 2m s = 7200m total volume = s * length = 7200 * cubic meters = cubic meters.

Question 2: The speed of the fast train s1=960 (12-5+3)=96km h, so there is a slow train speed s2= (11-5)=64km h, so the total time of the slow train = 960 s2=15h

Therefore, the slow train arrives at Station A at 8 p.m., that is, 8 p.m.

1 hour = 3600 seconds. The diameter of the water pipe is 2 dm = m, radius = m. Cubic metre; Cubic metre; Cubic metre;

Set: The speed of the fast train is x, and the speed of the slow train is y

x +y=960/6

10x=960

Solution x gets 96, and y gets 64

1 That's not all.

2-5 hours.

The express train traveled from A to B for a total of 10 hours and traveled 960 meters, so the speed of the express train is 960 10 = 96km h The two cars depart at 5 o'clock and meet at 11 o'clock, a total of 6 hours. The fast train went 96 6 = 576 km, so the slow train went 960-576 = 384 km. And because the slow train traveled for 6 hours, its speed was 384 6 = 64km s.

After 10 hours of travel, the slow train is 10 64 = 640 km, and there are 960-640 = 320 km left, so it will take 320 64 = 5 hours to reach station A.

Teach you a way to solve the problem: first look at the unit "1" known is unknown, known to use multiplication and not known to use division, look at the unit 1 after the more or less use 1 + more percentage, less use 1 - less percentage.