Chickens and rabbits are in the same cage, chickens are twice as large as rabbits, there are a total

This is a typical dishChickens and rabbits in the same cageFor this kind of problem, we can directly list the equations, list the most formulas according to the existing conditions, and convert the formulas to each other, and we can get the answer. Since only the number of chickens and rabbits is unknown in this problem, we list them as the letter x and the letter y, respectively.

According to the method of binary equations, the final number of rabbits is 10. In order to ensure that the answer is correct, we can substitute the number 10 into the equation calculation, as long as the equation is true, it means that there is no problem with the answer. After the calculation, the number of rabbits was 10 and the number of chickens was 20.

1. There are two unknowns in the calculation process in this problem, which are the number of chickens and rabbits, and we list them as x and y. Since the chicken is twice as large as the rabbit, and the two add up to 80 legs, we can get the two formulas x=2y and 2x+4y=80. To arrive at the answer, we substitute the first formula into the second formula, which gives us 2(2y)+4y=80, and the result is y=10.

Substituting the result into any formula, such as x=2y, gives the result x=20. Then the number of chickens is 20 and the number of rabbits is 10. If you are worried that the answer is incorrect, put the two numbers back into the equation, and the answer is correct if there is no question.

2. The key to solving the problem is that chickens and rabbits are in the same cage in mathematics, which is a very classic problem, and what it ultimately seeks is basically the number of animals. As long as we master the steps to do the questions, we don't have to worry about facing this kind of questions.

First: find all the numerical relationships in the question and list them into a formula, take the chickens and rabbits in the same cage, the number relationship between chickens and rabbits, the total number can be listed;

Second, merge the two formulas so that there is only one unknown in the formula. This method is relatively simple, and it can be replaced directly;

Third: perform a simple conversion according to the mathematical method to arrive at the answer to the unknown. Here you need to pay attention to the conversion order, addition and subtraction, multiplication and division, parentheses, many people know how to do the question, but the calculation is unqualified.

3. Precautions for math problemsThere are only two precautions for math problems, one is the process of solving the problem, and the other is the answer. The problem-solving process is often a problem-solving problem, which requires people to list formulas, which is simply the reason for giving the answer. If there are only answers and no formulas, it is impossible for the teacher to give high marks.

Needless to say, everything we do is to find the final result. If the result is wrong, then the whole process will be in vain. Therefore, when doing the questions, you must check the calculations to ensure that the answers are correct.

You can set the number of rabbits to n, the number of chickens is 2n, 4 n + 4 n = 80 can be calculated as n = 10, and the number of rabbits is 10.

This problem is relatively simple, you can set the number of rabbits as x, then the number of chickens is 2x, and then do the calculation.

First of all, the rabbit is x, and the equation can be enumerated, 4x+4x=80, x=10, so there are 10 rabbits and 20 chickens.

There are 10 rabbits and 20 chickens, and in the end they have a total of 80 legs. Moreover, it satisfies the relationship between the number of chickens and rabbits.

This is a very typical math problem of chickens and rabbits in the same cage, which can be calculated by the method of column equations, and the final result is that there are 16 rabbits.

In this case, it is necessary to set the equation before it can be calculated, and according to the equation, the final result is calculated, and the number of rabbits is 16.

Solution: A chicken has 2 legs, and a rabbit has 4 legs.

Let the rabbits be x.

4x+4*2x=120

x+2x=30

x=104x=40

A: 40 chickens and 10 rabbits.

Answer: Let's have x rabbits.

By the stem, chickens are 4 times larger than rabbits.

Yes, there are 4*x chickens.

By the question stem, there are a total of 120 legs.

Yes, the rabbit leg has 4*x strips.

Chicken thighs have 2*4*x strips.

4*x+2*4*x=120

12*x=120

x = 10, i.e., 10 rabbits and 40 chickens.

Hope it works for you.

The chicken has 2 legs and the rabbit has 4 legs

Chicken = 4 rabbits. 2 chickens + 4 rabbits = 120

Solution, chicken = 40, rabbit = 10

So, there are 40 chickens and 10 rabbits.

The chicken is four times the number of rabbits, then the number of chicken legs is 2 4 4 = 2 times the number of rabbit legs, and the rabbit legs have 120 3 = 40, so the rabbits have 40 4 = 10 and the chickens have 40.

Chickens and rabbits in the same cage There are 4 times more chickens than rabbits.

A total of 120 legs.

Let the rabbit be x, 4x=120

x=30

Suppose there are x rabbits and 4x chickens.

4x+2x4x=120

4x+8x=120

12x=120

x=104x=4×10=40

There are 40 chickens and 10 rabbits.

There are chickens and rabbits in the cage, and the number of chickens is 2 times that of rabbits, indicating that the chickens and rabbit legs are equal, a total of 80 legs, rabbits 80 2 = 40, and chickens have 10*2=20? There are 40 rabbits 4 = 10 rabbits.

Set x chickens and y rabbits. According to the problem, the system of equations can be listed x=2y; 2x+4y=80

The solution yields x=20 and y=10

20 chickens, 10 rabbits.

This is a typical chicken-rabbit cage problem. Equations can be solved using set unknowns. If the number of rabbits is x, then the number of chickens is 2x. The equation is, 4x+4x=80, x=10, then the number of rabbits is 10 and the number of chickens is 20.

This is a mathematical problem in which there are several chickens and rabbits in the cage, and one chicken has two more than rabbits, and it has a total of 40 legs. How many chickens and rabbits are there? Let's just list one equation.

Let's say there are x chickens and y rabbits. x-y=22x+4y=40x=8, y=6 so there are 8 chickens and 6 rabbits.

Suppose the number of rabbits is x then the number of chickens is 2x, because rabbits have 4 legs and chickens have 2 legs, so we can know that 4x 4x 80, then x 10, the result is 20 chickens and 10 rabbits.

Suppose there are x rabbits and 2x chickens, so there are legs in total 4x+4x=80, so x=80 8=10, that is, there are 10 rabbits and 20 chickens.

Chickens and rabbits are in the same cage, the number of rabbits is twice that of chickens, a total of 140 legs, 14 chickens, and 28 rabbits.

Chickens and rabbits are in the same cage, the number of rabbits (heads) is twice that of chickens (2 1), rabbits have four legs, chickens have 2 legs (the ratio of the number of feet of each head is 4 2), because it is known that the number of rabbits (the number of heads) is twice that of chickens, then the number of rabbit's feet is 4 times the number of chicken's feet (4 1). So the equation is as follows

140 (4 1) = 28 is the number of rabbits

28 2 14 is the number of chickens.

According to the calculation results, the title is: chickens and rabbits in the same cage, forty-two heads on the top, one hundred and forty under the bottom, ask the chickens and rabbits each geometry.

China's ancient arithmetic book "Sun Tzu Jing Calculation" uses arithmetic method: half of the number of feet minus the number of heads, that is, 140 2 42 28 is the number of rabbits: the number of heads minus the number of rabbits, that is, 42 28 14 is the number of chickens.

It is proved that the number of rabbits is twice that of chickens, with a total of 140 legs, 14 chickens, and 28 rabbits.

Solve with the equation: let the chickens be x and the rabbits be 2x.

2x+4×2x=140

10x=140

x=14 (only);

Rabbit 2x 2 12 28 (only).

A: There are 14 chickens and 28 rabbits.

Chickens and rabbits in the same cage, the number of rabbits is 2 times that of chickens, the number of rabbit legs is 2 * 4 = 8 times the number of chickens, and the number of chicken legs is 2 times the number of chickens, that is, the total number of legs is 10 times the number of chickens. There are now 140 legs, indicating that there are 14 chickens and 28 rabbits.

Suppose the number of chickens is x, then the number of rabbits is 2x, chickens have 2 legs, rabbits have 4 legs, you can make a formula, x 2 2x 4 = 140, 2x + 8x = 140, 10x = 140, x = 14, so there are 14 chickens and 28 rabbits.

Solution: There are x chicks.

The number of rabbits is 2x

A chick has two legs, and a rabbit has four legs.

2×x+2x×4=140

2x+8x=140

10x=140

x=14 so there are 14 chicks.

There are 14 2 = 28 bunnies.

Set: chicken x, rabbit y.

2x＝y①2x＋4y＝140②

Substituting y 4y 140

y＝282x＝28

x 14 chickens and 28 rabbits.

140 (2+4 2) = 14 (chickens).

14 2 = 28 (rabbits).

A: There are 14 chickens and 28 rabbits in the cage.

Chickens and rabbits are in the same cage, the number of rabbits is twice that of chickens, a total of 140 legs, chickens. How many rabbits are there?

Rabbit = 2 chickens. 4 rabbits + 2 chickens = 140

5 rabbits = 140

Rabbits = 28 pcs.

Chickens = 14.

The number of legs of a chicken is twice that of a rabbit, so the number of chickens is 4 times that of a rabbit.

If there are 60 more chickens than rabbits, then rabbits have.

60 (4-1)=20 (only).

The chicken void bridge has.

20 4 = 80 (only).

There are 80 kipinai chickens and 20 rabbits.

The chicken has 2 legs, the rabbit has 4 legs, the stool cryptotogen assumes that the rabbit has x, then the Zaochamo chicken has (x+60), the number of chicken legs is 2x+120, the number of rabbits with beard legs is 4x, and the question is 2x+120=2 4x

If you get x=20, there are 20 rabbits and 80 chickens, a total of 20+80=100.

Suppose there is x only sentenced Li chicken, the number of legs of the chicken in the Ming Bureau is 2x, and the number of rabbit legs is x, then the rabbit has x 4, x-x 4=60 3x 4=60

3x=240 x=80

Suppose there are x chickens and rabbits have y, so the number of legs of the chicken is 2x, and the number of legs of the rabbit is 4y, and it can be seen from the title that 4y=2 2x

x+y=50, solution, x=25

y=25 chickens have 25 chickens and rabbits have 25.

Originally, a rabbit's feet were twice as many as a chicken's feet, and now the rabbit's total feet are twice as many as the feet of the machine, so the rabbit and the chicken should be the same, and the rabbit and the chicken have a total of 50, and they have the same number, so they are 25 respectively.

This problem is a typical chicken-rabbit cage problem, and when encountering such a problem, you can set up x chickens and rabbits (50-x). So 2 2x = (50-x) 4

Solution x=25

So there are 25 chickens and 25 rabbits.

Chickens and rabbits in the same cage, there are 50 chickens and rabbits, the number of rabbit legs is 2 times the number of chickens' legs, according to common sense, the number of legs of a rabbit is also 2 times the number of chickens' legs, the number of chickens and rabbits should be equal, chickens and rabbits have 50 2 25 each, the number of rabbit legs is 25 4 100, and the number of chicken legs is 25 2 50.

The rabbit has 4 legs and the chicken has 2 legs, which is 2 times in itself, and the condition in the question is also 2 times, indicating that the number of rabbits and chickens is the same, so 50 2 = 25, and both chickens and rabbits are 25.

There are 25 chickens and 25 rabbits.

Chicken + Rabbit = 50, 4 Rabbit = 2 2 Chicken = 4 Chicken, so Chicken = 25, Rabbit = 25, so 25 chickens and 25 rabbits.

Chickens and rabbits in the same cage, chickens and rabbits have a total of 50, that is to say, chickens + rabbits = 50, the number of rabbit legs is 2 times the number of chickens' legs, that is to say, 4 rabbits = 2 * 2 chickens are simplified, that is, chickens = rabbits, so there are 25 chickens and rabbits respectively.

The number of legs of a rabbit is twice that of a chicken, indicating that the number of rabbits and chickens is the same, so there are 25 rabbits and 25 chickens. It's a very simple question, and it basically doesn't need to be calculated.

According to the inscription, the legs of rabbits are twice that of chickens, and originally rabbits have four legs and chickens have two legs, which is exactly twice that of chickens, so the number of chickens and rabbits is equal, that is, there are 25 chickens and rabbits each.

Because a rabbit's leg is twice as large as a chicken's leg, the question states that the rabbit's leg is twice as large as a chicken's leg, indicating that the number of chickens and rabbits is equal, so it should be 50 2, which is equal to 25, so there are 25 chickens and rabbits each.

There are 50 chickens and rabbits, and the number of legs of the rabbit is twice that of the chicken, indicating that the chickens and rabbits are the same number, so the number of chickens is 25 and the rabbit is also 25.

According to the "number of legs of a rabbit is twice the number of legs of a chicken", it can be seen that there are as many chickens as rabbits.

50 2 = 25 (only).

A: There are 25 chickens and 25 rabbits.

The number of legs of a rabbit is twice as many as the number of legs of a chicken, because a rabbit has four legs, a chicken has two legs, and a rabbit has twice the number of legs, so there are as many chickens and rabbits, so 50 2=25, A, there are 25 chickens and 25 rabbits.

The answer to this question is: 4 rabbit legs and 2 chicken legs. Rabbit legs are twice as large as chicken legs, so there are as many rabbits and chickens. 50÷2=25。There are 25 chickens and rabbits each. Hope it helps.