Why does the reaction between sodium thiosulfate and dilute sulfuric acid produce S element, shouldn

Sodium thiosulfate.

S in the substance is +2 valence, which is in the intermediate valence state, so it is valence.

That is, it can be increased or decreased, that is, it is easy to disproportionate under acidic conditions.

Disproportionation reaction. , if oxidation and reduction occur within the same molecule, they are in the same oxidation state.

so that part of the atoms (or ions) of that element is oxidized and the other part is reduced.

The reaction of sodium thiosulfate and dilute sulfuric acid is not a centering reaction. The centering reaction refers to the redox reaction of the same element in the ** state and the low-valence state to form an intermediate valence state, although sodium thiosulfate has strong reducing property but dilute sulfuric acid has no strong oxidation, so the two will not have a centering reaction. This reaction is actually the principle of making weak acids from strong acids to produce thiosulfuric acid, which is unstable and decomposes itself into sulfur, sulfur dioxide and water.

Valence state centering refers to the oxidation of the low valence state of the same element ** state in the redox reaction. However, this reaction cannot occur in the two adjacent valence states of the element.

Normalization means that these two elements end up in the same valence state in the product.

For example, the most noteworthy thing about this reaction is that the valence state of the reduction product cannot be lower than that of the oxidation product. That is, it cannot be crossed. This is also the reason why adjacent valence states cannot be reacted.

The reaction of sodium thiosulfate with sulfuric acid is: Na2S2O3 + H2SO4 = Na2SO4 + S + SO2 + H2O.

The chemical equation for the reaction of sodium thiosulfate and dilute sulfuric acid is: Na2S2O3 + H2SO4 Na2SO4 + H2O + 2SO2

Expand: Sodium thiosulfate is a chemical widely used in industrial fields such as photography, bleaching, and printing and dyeing, and its chemical formula is Na2S2O3, also known as baking soda or hypo. Dilute sulfuric acid (H2SO4) is a solution of 70% or less sulfuric acid and is a common chemical agent.

When sodium thiosulfate comes into contact with dilute sulfuric acid, a series of chemical reactions occur. First, the thiosulfate ions (S2O3 2-) in sodium thiosulfate combine with the hydrogen ions (H+) in dilute sulfuric acid to form sulfuric acid (H2SO3). As the ridge aging reaction progresses, the sulfuric acid further decomposes to form a mixture of sulfur dioxide (SO2) and water (H2O).

When the concentration in dilute sulfuric acid is higher, the faster the process becomes. In addition, some sodium sulfate (Na2SO4) is produced in this reaction.

Sodium carbonate and dilute sulfuric acid react to produce sodium sulfate, water, and carbon dioxide.

na co + h so = na front shot so + h o + co (gas).

This depends on the order of dropping, such as the dropwise addition of sulfuric acid to the sodium carbonate solution.

co32-+h+=hco3-

hco3-+h+=h2o+co2

If the anti-drip front is not added, then:

CO32-+2H+=H2O+CO2 (the symbol of the gas silver bond is added by itself).

Reaction equation of sodium sulfide and concentrated sulfuric acid: if it is dilute sulfuric acid, there is no oxidation, and the reaction of strong acid to weak acid occurs: Na2S + H2SO4 = Na2SO4 + H2S.

If it is concentrated sulfuric acid, strong oxidation, redox reaction occurs: Na2S + H2SO4 (concentrated) = S + Na2SO3 + H2OH2S, the gas cannot be dried with concentrated sulfuric acid for fear of being oxidized.

Reaction phenomenon of sodium sulfide and concentrated sulfuric acid:

Because concentrated sulfuric acid has strong oxidation and sodium sulfide has reducibility, the two undergo redox reaction: Na2S + H2SO4 (concentrated) = S + Na2SO3 + H2O At the beginning (before adding sulfuric acid), the HS- in the solution is completely generated by S2- hydrolysis, and the concentration is low.

After the addition of sulfuric acid, the H+ of sulfuric acid is combined with S2- to form HS-, and its concentration continues to increase. When the ratio of the amount of sulfuric acid to the sodium sulfide substance is 1:2, the HS- concentration reaches its maximum.

If sulfuric acid is added, the sulfuric acid begins to combine with Hs- to form H2S and escape the solution, and the Hs- concentration begins to decrease again.

The above content reference: Encyclopedia - sodium sulfide.

Summary. Why do sulfur ions react with concentrated nitric acid to form sulfur elements instead of sulfate ions, and the oxidizing property of concentrated nitric acid is not so strong here.

Why do sulfur ions react with concentrated nitric acid to form sulfur elements instead of sulfate ions, and the oxidizing property of concentrated nitric acid is not so strong here.

It is not enough to continue the oxidation of sulfur elements to sulfate ions.

So is the reaction between hydrogen sulfide and concentrated nitric acid to produce sulfur or sulfate ions? Sulfur element. There is also NO2H2O

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Due to the instability of Na S O in an acidic environment, the disproportionation reaction occurs: 2h 62616964757a686964616fe59b9ee7ad9431333431353963s o ===s so h o.

Chemical properties of sodium thiosulfate:

1. Sodium thiosulfate is stable under alkaline or neutral conditions, and it will immediately separate sulfur dioxide gas and produce sulfur precipitation when it is decomposed by acid.

s₂o₂⁻＋2h⁺＝s↓＋so₂↑＋h₂o

2. It is heated in air and oxidized and decomposed into sodium sulfate and sulfur dioxide. When burned in isolation from air, sodium sulfate, sulfide alkali and sulfur are generated.

2na₂s₂o₃+3o₂ →2na₂so₄+ 2so₂

3. Sodium thiosulfate has a strong complexing ability and can form a complex with silver bromide. Depending on this property, it can be used as a fixer.

4. Sodium thiosulfate has a certain reducing property, which can reduce chlorine and other substances

s₂o₂⁻＋4cl₂＋5h₂o＝2so₂⁻＋8cl⁻＋10h⁺

Because sodium sulfite and sodium sulfide are strong alkali and weak salts, they react under acidic conditions, and the products are sulfur elemental and sodium sulfate.

Sodium thiosulfate reacts with acid to form elemental S and sulfur dioxide.

Na2S2O3 + 2HCl ==== 2NaCl + S (precipitate) + SO2 (gas) + H2O

S2O3]2-, the valency of S is +2, and it is relatively stable in alkaline environment.

In an acidic environment, it undergoes a redox reaction to generate elemental S, +4 valence SO2.

s2o32- +2h+=s+so2+h2o

With the conservation of electrons, S2O32-li S is +2 valence, S is 0 valence, and So2 is +4 valence.

So an S2O32- generates an S and an SO2, and then balances the charges with H+ and H2O.

First, using the conservation of electrons of gain and loss, the ratio of S to SO2 is calculated to be 1:1. Then with the conservation of charge, two hydrogen ions are added to the left. Finally, the elements are conserved, and water is generated on the right.

S2O32- +2H+=S+SO2+H2O is a planned reaction of sulfur ions.

Isn't the sulfur in sodium thiosulfate +4 and 0 valence?