Chickens and rabbits are in the same cage, with a total of 13 heads. 38 Feet asks how many rabbits t

Analysis: Method 1.

The chicken has 1 head and 2 feet, and the number of feet is twice as many as the number of heads.

The rabbit has 1 head and 4 feet, and the feet are more than 2 times the size of the head2

In this problem, there are 13 heads and 38 feet, which are more than twice the size of the head.

38-13 2=12 (only).

The extra is the number of rabbits (each rabbit has 2 more legs than chickens), so the number of rabbits is.

12 2 = 6 (only).

Method 2: Find the equivalent relationship first.

Number of rabbits + number of chickens 13.

The number of rabbits 4 + the number of chickens 2 38.

Solution: If there are Y rabbits, then there are 13-Y chickens.

4y+2×（13-y）＝38

4y+26-2y＝38

2y＝12y＝6

There are 6 rabbits.

If they were all rabbits, then 13 4 = 52. There are 52-38 = 14 more, which is the number of chickens 14 2 = 7, rabbits 13-7 = 6.

There are x rabbits to dismantle.

4x+2*（13-x）=38

4x-2x=38-26

2x=12x=6

There are six rabbits.

Suppose it's all chickens and the feet have:

13 2 = 26 (only).

Feet less: 38-26 = 12 (only).

Rabbits have more feet than chickens.

4-2=2 (only).

Rabbit. 12 2 = 6 (only).

A: There are 6 rabbits.

Chickens and rabbits in the same cage, a total of 48 heads, 120 feet, assuming all rabbits, then there are = 48 4 192 feet, chickens have = (192 120) (4 2) 36, rabbits have = 48 36 12. A: There are 36 chickens and 12 rabbits.

Method 1: If there are x chickens, then rabbits (48-x) will be obtained according to the question.

2x+4(48-x)=132

2x+192-4x=132

2x=-60

x=30 rabbit 48-30=18

So there are 30 chickens and 18 rabbits.

Method 2: Set up x chickens and y rabbits, according to the title.

x+y=48

2x+4y=132

Solution x=30

y=18 so there are 30 chickens and 18 rabbits.

Solution: 48x2 two 96, 132 a 96 two 36

36 2 ii 18, 48 a 18 ii 30

A: There are 30 chickens and 18 rabbits.

Solution: If there are x chickens and y rabbits, then:

x+y=48

2x+4y=132

The solution yields x=30 and y=18

So there are 30 chickens and 18 rabbits.

Solution: Suppose that there are a chickens and a rabbit (b).

Then: a+b=48 (only).

2a+4b=132 (only).

Solve the equation to obtain: a=30 (only), b = 18 (only).

A: There are 30 chickens and 18 rabbits.

There were eighteen rabbits and seventy-two legs.

Thirty chickens, sixty feet.

There are x chickens and (48-x) rabbits.

2x+4（48-x）=132

2x+192-4x=132

2x=60x=30

48-x=18

A: There are 30 chickens and 18 rabbits.

Set: x chickens, 48-x rabbits.

2x+4(48-x)=132

Get x=30 so 48-30=18

A: There are 30 chickens and 18 rabbits.

48 2 = 96, 132 96 = 36, so rabbits have 36 2 = 18 and chickens have 48 18 = 30.

x chickens, y rabbits.

x+y=48

2x+4y=132

The solution yields x=30 and y=18

There are 30 chickens and 18 rabbits.

It can be solved by the equation, let's say, there are x chickens, there are y rabbits: x+y=48, 2x+4 y=132 solve this equation: x=30, y=18, there are 30 chickens, and there are 18 rabbits.

Chickens and rabbits have a total of 48 heads and 132 legs in the same cage, how many chickens and how many rabbits are there?

2 chickens + 4 rabbits = 132

Chicken + Rabbit = 48

2 (48-rabbit) + 4 rabbit = 132

96-2 rabbits + 4 rabbits = 132

2 rabbits = 132-96

2 rabbits = 36 rabbits = 18 rabbits.

Chickens = 48-18 = 30 pcs.

Chicken A, rabbit B, A+B=48, 2A+4B=132, solve the system of equations, B=18, A=30, 30 chickens, 18 rabbits.

Calculate the number of rabbits by lifting your feet: (132 48x2) 2 18 (rabbits).

Then count the number of chickens: 48 18 30 (only).

x ten y two 48

2x dec. 4y-ii 132

2 (48 a y) ten 4 y two 132

96 x2y ii 132

2y two 36 y two 18

x 2 30 chickens and 18 rabbits.

soeasy

Assuming that they are all chickens, then there are 2*13=26 chickens. But there are actually 38 feet, so use 38-26 = 12. This is the total foot difference between chickens and rabbits, rabbits have 4 feet, chickens have 2 feet, and their foot difference is 4-2=2, then rabbits have 12 2=6 and chickens have 13-6=7.

Comprehensive formula: rabbits: (38-13*2) (4-2)=6.

Chickens: 13-6=7.

This kind of problem can be thought of like this in arithmetic:

Assuming all rabbits stand up, then each head corresponds to two feet when viewed from the feet. At the bottom of the cage there is a foot 2 13 = 26

And the original 38 feet, 38-26 = 12, where did these 12 feet go, held in the air, hehe. It's all rabbits. So how many rabbits are there?

12 2 = 6 chickens, 13-6 = 7 chickens

(Total number of feet - number of feet per chicken Total number of heads) (number of feet per rabbit - number of feet per chicken) = number of rabbits;

Total number of heads - number of rabbits = number of chickens.

or (number of feet per rabbit total number of heads - total number of feet) (number of feet per rabbit - number of feet per chicken) = number of chickens;

Total number of heads - number of chickens = number of rabbits.

Let's say it's all chickens.

then the rabbit has; (38-13 2) (4-2) = 6 chickens: 13-6 = 7 chickens

Assuming it's all rabbits, then the chickens have stove celery:

14 4-38) (4-2), 18 2, Sail Bench.

9 (only), then the rabbit state brigade has: 14-9 = 5 (only), A: There are 9 chickens and 5 rabbits

Suppose Quanchang Mill is a chicken, with legs 2*12 24 34 24 10 because rabbits are counted as chickens, each one is less than 4 2 2 feet, and rabbits have 10 2 5 chickens have 12 5 7

Or suppose that all of them are Changxiao rabbits, and there are 4*12 48 48 34 14 feet because chickens are counted as rabbits, and each one counts 4 2 2 feet, and chickens have 14 2 7 rabbits and 12 7 5

In a simple way.

Setup: The cage is full of chickens.

88 2 = 44 (only).

Rabbits: 44-30 = 14 (only).

Chickens: 30-14=16 (pcs).

Suppose the cage is full of chickens, then the chicken has two legs, then there are 2 30 = 60 (only) in the cage, then there are 88-60 = 28 (only) less than the original, the rabbit has 4 legs, 4-2 = 2 (only) more than the chicken, and then 28 2 = 14 (only) - rabbit, 30-14 = 16 (only) - chicken.

2 30 = 60 (only).

88-60=28 (only).

4-2=2 (only).

28 2 = 14 (only) - rabbit.

30-14 = 16 (chickens)

A: There are 16 chickens and 14 rabbits.

【Test Center】Chickens and rabbits in the same cage.

Analysis] Assuming that 30 are all chickens, then the legs are: 2x30 = 60 (only), 88-60 = 28 (only) less than the actual one, because each rabbit has 4-2 = 2 (only) feet than each chicken, so the rabbit has 28 2 = 14, and the number of rabbits subtracted by 30 is the number of chickens, and the answer can be accordingly.

Answer] Solution: Suppose 30 are all chickens, then rabbits have:

88-2x30) (4-2) = 14 (chickens) 30-14 = 16 chickens

A: There are 16 chickens and 14 rabbits.

Solution: There are x rabbits.

4x+（30-x）x2=88

4x-60-2x=88

x=14 then the chickens are: 30-14=16 (only).

It can be solved by a series of equations, or it can be solved using the hypothetical method.

Assuming it's all chickens, there should be feet:

13x2=26pcs.

Visible less: 36-26=10.

Each rabbit has 2 more legs than a chicken, so, rabbits have:

10 2 = 5.

Chickens have: 13-5=8.

Number of heads = number of birds: chicken + rabbit = 13 chicken 2 + rabbit 2 = 26

Number of legs: Chicken 2 + Rabbit 4=36

The number of feet - the number of heads is 2, and the rabbit is 2=36-26=10, and the rabbit = 5 (only), and then the chicken = 13-5=8 (only).

If there are x chickens, then 12-x rabbits.

2x+4（12-x）=38

5 chickens and 7 rabbits.

Set chicken x then rabbit 12-x

2x+4(12-x)=38

2x+4*12-4x=38

2x+48=38

48-38=2x

x = 5 chickens and 5 rabbits, rabbits 12-5 = 7