A corridor is 36 meters long and 2 meters wide, and is paved with 1,000 square floor tiles with an a

When k 0, f (x) = 3x2-2kx + 1, its opening is upward, the axis of symmetry x = k3, and passes (0, 1).

1.When =4k2-12=4(k+3)(k-3) 0, i.e., -3 k 0, f(x) 0,f(x) increases monotonically on [k,-k], so that when x=k, f(x) obtains the minimum value m=f(k)=k, and when x=-k, f(x) obtains the maximum value m=f(-k)=-k3-k3-k=-2k3-k

2.When =4k2-12=4(k+3)(k-3) 0, i.e., k -3, let f(x)=3x2-2kx+1=0

The solution is: x1=k+k2-33,x2=k-k2-33, and it is noted that the minimum value of k2 x1 0,m=min,m=max,f(x1)-f(k)=x31-kx21+x1-k=(x1-k)(x21+1) 0, f(x)=f(k)=k,f(x2)-f(-k)=x32-kx22+x2-(-k3-k??).k2-k)=(x2+k)[(x2-k)2+k2+1] 0, the maximum value of f(x) m=f(-k)=-2k3-k

To sum up, when k 0, the minimum value of f(x) is m=f(k)=k, and the maximum value is m=f(-k)=-2k3-k

Solution: The floor area of the corridor is:

8 2 = 16 (square meters) = 1600 (square decimeters);

Floor tiles required: 1600 8 = 200 (blocks).

A: 200 floor tiles are required

Convert the units to the unified units first.

60 meters 600 dm.

4 m 40 dm.

Then calculate the area of the corridor.

600 40 24000 square decimeters.

Finally, divide the area of the corridor by the area of the floor tiles.

24000 4 6000 blocks.

A: A corridor needs 6,000 such floor tiles.

6000 such floor tiles are needed. The area of the corridor is 60*4=240 square meters, and 240 bricks with an area of 4 square meters are required.

The length of this corridor is 60 meters, that is, 600 decimeters, and the width is 40 decimeters, so the area is 600 40 = 24000 decimeters, and the area of a small floor tile is 4 decimeters, so a total of 24000 4 = 6000 pieces.

The area of the corridor is 60x4 two 240 square meters, and the area of tiles is four square meters, so the number of tiles required is 240 4 60 pieces.

60 meters = 600 decimeters, 4 meters = 40 decimeters.

4 = 2 2, the side length of a square with an area of 4 square meters is 2 decimeters.

Long and other directions can be paved.

600 2 = 300 (block).

The wide direction can be tied.

40 2 = 20 (block).

The total number of such floor tiles is needed.

300 20 = 6000 (block).

A: 6,000 such floor tiles are needed.

A corridor is 60 meters long and four meters wide, and is paved with square floor tiles with an area of four square decimeters. It takes about 100 pieces or so.

60 meters 600 dm.

4 m 40 dm.

40x600 ÷4

6000 (blocks).

A: 6000 floor tiles are needed.

A corridor is 60 meters long, 4 meters wide, and uses square floor tiles with an area of square decimeters, how many floor tiles are needed for this corridor? Floor tiles are required to be 24 quick turns.

In this problem, we first need to calculate the area of the corridor, and then convert the units to square decimeters, and the column formula is as follows, 60 4 100 4 24000 4 60006000 floor tiles are required aqui te amo.

The corridor area is 60 4 240 square meters.

240 blocks.

6000 floor tiles are required!

6000 such floor tiles are needed. The area of the corridor is 60 * 4 = 240 square meters wide first mold, and the area is 4 square meters of 240 bricks.

First of all, it is necessary to unify the unit, 2 decimeters is equal to meters, and how many bricks are needed to divide the corridor area by the Songzhong Li bricks. Peiga.

Square metre. 38 6 228 sq. m.

228 blocks.

Summary. The perimeter is 8 dm long brick paved corridor, 45 blocks wide, 20 blocks wide, and the corridor area is 576 square meters.

The perimeter is 8 dm long brick paved corridor, and 45 blocks wide are commonly used, and the area of the corridor is 20 square meters.

The perimeter is 8 dm long brick paved corridor, 45 blocks wide, 20 blocks wide, and the corridor area is 576 square meters.

We can calculate the length and width separately.

45 meters. 20 meters.

36 16 576 sq. m.

38x6 = 228 square meters withered.

2 decimeters and two meters.

Two square meters is not quietly wide.

Brick = 228

5700 blocks.

5,700 bricks are needed.

2 dm = m.

Length: 38 pieces.

Width: 6 rows.

At least a few bricks are required: 190x30 = 5700 pieces.

2 dm punch base fiber meter.

Square metre. 228 square scattered imitation meters.

5700 blocks.

A: A minimum of 5700 bricks is required. Striker.

A corridor 20 meters long and 4 meters wide is paved with floor tiles, and if you use square floor tiles with a circumference of 16 decimeters, you need to lay them.

Hello, dear. 50,000 square tiles with a circumference of 16 decimeters need to be laid. First of all, you need to calculate the area of this corridor, that is, area = length and width = 20 meters 4 meters = 80 square meters, and then you need to calculate the area of each square floor tile, because the perimeter of the elimination resistance is 16 decimeters, so the side length is 4 decimeters, then the area of each floor tile is area = side length side length = 4 decimeters 4 decimeters = 16 square decimeters = flat socks spring square meters Finally, divide the area of the corridor by the area of each floor tile to get how many floor tiles need to be laid:

The number of tiles to be paved = area The area of each tile = 80 square meters Square meter = 50,000 tiles (rounded up, because the bricks cannot be laid in blocks).

Summary. The length is eight times the width, then 16 8 = 2 then the width is 2, 16 * 2 = 32 square meters. Convert 4 square decimeters to square meters. 32/

A promenade is 16 meters long, 8 times as long as it is wide, and it is paved with square bricks with an area of 4 square decimeters, and how many bricks are needed to pave it.

The long cave car is eight times the width, then 16 8 = 2 is 2 wide, 16 * 2 = 32 square meters. Converted to Nasdaq 4 square decimeters for square meters. 32/

800 floor tiles are required.

The second volume of the third grade.

I don't understand what you posted.

Meters and decimeters need to be converted.

The length is eight times the width, so the width is the length divided by 8 to get the width is 2, and the area is the length multiplied by the width, so it is 16 2 = 32

1 square decimeter = square meter, this can be directly remembered and used directly, so 4 square decimeter is square meter.

Divide the overall area by the area of a brick to calculate how many bricks are used, so 32 square meters divided by square meters equals 800

800 such bricks are needed.

The process is as follows:

800 (blocks).

A: 800 such bricks are needed.

The area of your library is 128 square meters, and the theoretical aspect is 128 divided by 160 pieces, but the real construction needs to calculate the loss, it is recommended that you buy 176 pieces, or go to the merchant to tell the actual area The merchant calculates the amount of consumables.

16 4 64 (sq.m.) 6400 sq.d.m.

6400 8 800 (blocks).