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1] Normally, the impedance of the horn is calibrated in the case of a 1k signal.
If the amplifier is powered by dual 15V, then the maximum peak voltage added to the speaker is 30V, divided by the approximate value) to obtain the root mean square value, which is approximately, if the horn is 4ohm, then, so that the maximum undistorted output power at 1k sinusoidal signal is approximately.
2] P v2 2r 15 15 2 4 3] Dual power supply. po=(ηv)2/2rl
is taken for the power factor.
4] Take 15V+15V, 4 ohm RL as an example):
1. Maximum sine wave continuous output power.
42=112(w)
2. The available power for actual listening to songs.
5] Undistorted power between single calculations:
1k sine wave signal input, load 4-8 ohms. Measure the maximum undistorted output voltage. (v):
v*v/(4/8)=w
Example: A power amplifier is input with a 1k sine wave signal. The power loop becomes dual 24VLoad 100w4ohThe output voltage was measured at 12V
144 4 = 36w) Note: All are counted with a single channel.
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This depends on what type it is, the general is a class A and B power amplifier (enthusiasts like to use a class A power amplifier or a gall machine, that is, a tube power amplifier, these powers are relatively large), the efficiency of class A and B power amplifiers is relatively high, and the power consumption is not large, generally tens of w, 1-200w on the top day
In addition,The power marked on the power amplifier is the peak power,It's not what you said"Power",The power of a few W in a general speaker is very large。 For example, the horn of an old-fashioned radio has a very loud power input.
The radiation of the power amplifier is not large, so don't worry.
PS has a simple method, with the plug strip with an ammeter, you can intuitively see the actual power.
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The power should be calculated using a valid value. Undistorted maximum power = output voltage squared 8 speaker impedance = (37+37) 2 64=. 37V is the maximum, not the RMS. 37 divided by the root number 2 is a valid value.
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1. The power amplifier and speaker are designed together, such as the power amplifier with 300 watt output, which has the best effect on the speaker with 300 watt carrying power;
2. The output power of the power amplifier is greater than the carrying power of the speaker, and the speaker will burn out, otherwise the thrust of the speaker is insufficient, and the effect is not good;
3. The nominal power is the normal working state of the machine, and it is usually for the system to spare force halfway, and the performance is the best, and the full power will not burn the machine;
4. The output power of the power amplifier is determined according to the use environment, and the bigger the better;
5. The power of the amplifier is twice as large as that of the speaker, and it is conducive to the performance of the speaker when the volume is not the maximum. If you don't turn on the maximum volume, you won't burn the horn.
Power Band Width: The vocal range is 20Hz 80kHz, and the frequency response of the speaker from bass to treble requires a response capability of 20Hz 20kHz. However, the frequency response of the power amplifier, which is the "bottleneck" of signal transmission, is required to be wider, such as: >>>More
There is a transformer in the amplifier, the larger it is, the heavier the whole amplifier, and the greater the power of the amplifier. >>>More
This kind of amplifier 276 should be equivalent to 220 watts of power, but I can't tell how much power you have.
BTL power amplifier, a channel to use 4 high-power transistors, because the even harmonic distortion of BTL power amplifier cancels, the sound is not good, so it is rarely used in the family. (In car audio, due to the low working voltage, all this). >>>More
I suggest you replace it with a low-power one, which is too wasteful of electricity, unless your power supply to the power amplifier is a switching power supply, and it is energy-saving. Because the power supply voltage of the 600W power amplifier will be relatively high, about 80 volts, because (the power is equal to the square of the voltage divided by the resistance), now the power is 600W, the load is 8 ohms, the voltage should be at least 70 volts, because there is a tube voltage drop, of course, it depends on its output resistance, the output resistance will be smaller, the power supply voltage will be smaller, the power consumed by the power amplifier itself will be smaller, that is, the efficiency will be higher, that is, for example, when your power amplifier is powered by 80V, The power you use to watch TV is 5W (the power is much greater than the power of the TV's own speaker, because you take the amplifier with the speaker, the speaker of the speaker is relatively large, that is, the speaker is heavier, we all know that the sound is generated by vibration, so drive such a big speaker to move, the required electrical energy can be imagined, and the sound is smaller, the sound is not clear, and the efficiency is very low), the power (sound energy) that produces the sound may not be enough, because the sound is already very large, 5W power consumption on the speaker,So what is the power consumed on the power amplifier,For example, the general speaker is 8 ohms,8 ohms when loaded,5W 8 ohms then the current is nearly a ampere,The voltage drop on the speaker is like this,The rest of the voltage is dropped on the control tube,80 minus 70 volts,70 times equal to 56W to be consumed on your power amplifier radiator,This power has the power of your TV。