What is the algorithm of the amplifier power? How to choose the power of the amplifier

Updated on number 2024-08-08
4 answers
  1. Anonymous users2024-02-15

    1] Normally, the impedance of the horn is calibrated in the case of a 1k signal.

    If the amplifier is powered by dual 15V, then the maximum peak voltage added to the speaker is 30V, divided by the approximate value) to obtain the root mean square value, which is approximately, if the horn is 4ohm, then, so that the maximum undistorted output power at 1k sinusoidal signal is approximately.

    2] P v2 2r 15 15 2 4 3] Dual power supply. po=(ηv)2/2rl

    is taken for the power factor.

    4] Take 15V+15V, 4 ohm RL as an example):

    1. Maximum sine wave continuous output power.

    42=112(w)

    2. The available power for actual listening to songs.

    5] Undistorted power between single calculations:

    1k sine wave signal input, load 4-8 ohms. Measure the maximum undistorted output voltage. (v):

    v*v/(4/8)=w

    Example: A power amplifier is input with a 1k sine wave signal. The power loop becomes dual 24VLoad 100w4ohThe output voltage was measured at 12V

    144 4 = 36w) Note: All are counted with a single channel.

  2. Anonymous users2024-02-14

    This depends on what type it is, the general is a class A and B power amplifier (enthusiasts like to use a class A power amplifier or a gall machine, that is, a tube power amplifier, these powers are relatively large), the efficiency of class A and B power amplifiers is relatively high, and the power consumption is not large, generally tens of w, 1-200w on the top day

    In addition,The power marked on the power amplifier is the peak power,It's not what you said"Power",The power of a few W in a general speaker is very large。 For example, the horn of an old-fashioned radio has a very loud power input.

    The radiation of the power amplifier is not large, so don't worry.

    PS has a simple method, with the plug strip with an ammeter, you can intuitively see the actual power.

  3. Anonymous users2024-02-13

    The power should be calculated using a valid value. Undistorted maximum power = output voltage squared 8 speaker impedance = (37+37) 2 64=. 37V is the maximum, not the RMS. 37 divided by the root number 2 is a valid value.

  4. Anonymous users2024-02-12

    1. The power amplifier and speaker are designed together, such as the power amplifier with 300 watt output, which has the best effect on the speaker with 300 watt carrying power;

    2. The output power of the power amplifier is greater than the carrying power of the speaker, and the speaker will burn out, otherwise the thrust of the speaker is insufficient, and the effect is not good;

    3. The nominal power is the normal working state of the machine, and it is usually for the system to spare force halfway, and the performance is the best, and the full power will not burn the machine;

    4. The output power of the power amplifier is determined according to the use environment, and the bigger the better;

    5. The power of the amplifier is twice as large as that of the speaker, and it is conducive to the performance of the speaker when the volume is not the maximum. If you don't turn on the maximum volume, you won't burn the horn.

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