Three 6th grade math problems to solve Only one dimensional equations have been learned by solving e

6. Solution: There are x number of male employees.

1-1/11）x=(152-x)-5

Solution: x=77 then there are 152-77=75 girls.

7. Solution: There are x tons of cement in the warehouse.

1-1 5)x=(84-x+1 5x) (1+1 3)Solution:x=60 Then there are 84-60=24 (tons)8, solution: Set up a second team to transport x tons of goods.

1000·2 5+x+(1000 2 5+x)·1 3=1000 solution: x=350 Then the first pair you transported 1000 2 5=400 tons, the second team transported 350 tons, and the third team transported (400+350) 1 3=250 tons.

Addendum: Solution: Let the first one be x meters long.

1-1/5）x=（18-x）+

Solution: x= then the second long meter.

6. Male x person, female (152-x), (1-1 11) x = (152-x)-5Solution x = 70, female employees 82

7. A x, B 84-x, 4 5x = (1 + 1 3) x (1 5x + 84-x), solution x = 60, B 24

8. The first team is 1000x2 5=400, the second team is x, the third team is 600-x, 600-x=1 3x (x+400), the solution is x=350, and the third team is 250

Question added: one x, another 18-x, 4 5x=18-x+, solution x=, another.

According to A is B C and 3 7

Stating A is a total of 3 10

According to the ratio of the sum of the numbers B to A and C is 3:5, it means that B is 3 878 (1-3 10-3 8) = 72 of the total

Solution: Let the diameter of the great circle be x decimeters, then the diameter of the small circle is (x-6) decimeters.

x/(x-6)=5/3

5(x-6)=3x

2x=30x=15

So the diameter of the small circle = 15-6 = 9 (decimeters).

Circumference of a great circle: l=15

Circumference of a small circle: l=9.

There is no way to solve the unary equation, there should be other conditions, and I will reason that the length, width, and height of this cuboid are all regarded as natural travel state answers.

I guess it is: "The front area is 20 square decimeters, and the left side area is 12 square decimeters."

The area of the front of the dismantled tung = length * height = 20 = 5 * 4

Area on the left side = width * height = 12 = 3 * 4

Therefore, the length, width, and height of this cuboid are 5, 4, and 3 volumes = 5 * 4 * 3 = 60 (cubic decimeters).

Think of this topic like this:

Front. Length height = 20

Side. Width and height = 12

When the height is 1, the length is 20 and the width is 12The volume of the pure finch is 20 12 1 = 240 cubic decimeters.

When the height is 2, the length is 10 and the width is 6. The volume is to do a search early 10 6 2 = 120 cubic decimeters.

When the height is 4, the length is 5 and the width is 3

The volume is 5 3 4 = 60 cubic meters of leaky keys.

Do not use three yuan once, up to 2 yuan one time.

Set up 1 group to pack 1 copy of ** in a day.

Then, 3 teams loaded 180 copies in 60 days and completed it; 5 teams loaded 100 copies in 20 days and completed it;

The total number of the former is 180, the total number of the latter is 100, and the former is the original 600, plus the number of new applications in 60 days; The latter is the original 600, plus the number of new applications in 20 days;

180 100 80 (copies), 60-20 40 (days), indicating 80 new applications in 40 days, 80 40 new applications in 1 day = 2 copies.

That is, 2 teams are dedicated to installing new applications every day, and the rest of the teams are installing 600 already applied units.

From this, each installation team installs 600 60 (3-2) = 10 units or 600 20 (5-3) = 10 units per day.

There are 10 new applications per day** 2=20.

Equation: If there are x parts of new application for installation ** every day, each installation team will install Y part 600 + 60x = 3y 60 per day

600+20x=5y×20

The solution yields x=20 and y=10

Have fun.

Each installation team is set to install an average of x units per day, and there are new applications for installation ** per day, with a number of y units**3x 60=600+60y 3x=10+y......（1）5x×20=600+20y 5x=30+y……（2）（2）-（1）

2x=20 x=10

30=10+y y=20

Each installation team installs an average of 10 units per day, and 20 new installations are applied for every day.

There are x new installations per day, and each installation team installs Y per day. The system of equations 600 + x * 60 = y * 60 * 3 (1) is obtained

600+x*20=5*20*y (2)

1)-(2) De.

40x=80y x=2y

Substituting (1) results in: x=20, y=10

This should be a binary (two unknowns) one-time (highest power is 1) equation.

This kind of question generally asks what to set up, and then finds two equations with unknowns from the question, and solves it correctly.

Solution: Set up a new application for installation every day.

Then (60x+600) (3*60)=(20x+600) (5*20), the solution is x=20, so (60*20+600) (3*60)=10 (parts) Answer: 20 new installations are applied for every day, and 10 installations are installed per day**.

There are X parts of the new application, and each installation team arranges Y part every day.

Then 3*y*60=60*x+600 5*20*y=20*x+600 x=20 y=10

3x+5y=m+2 1 formula.

2x+3y=m 2.

1 type *2-2 type *3 get:

6x+10y-6x-9y=2m+4-3m

y=4-m is substituted into 1 to obtain:

3x+20-5m=m+2

3x=6m-18

x=2m-6

x+y=22m-6+4-m=2

m=4x=2m-6=2

y=4-m=0

2x+3y=m（1）

3x+5y=m+2(2)

2)-(1) gives x+2y=2(3).

Because the sum of x and y is 2, i.e., x+y=2(4).

3)-(4) y=0

2x=m3x=m+2

The solution is m=4x=2

According to the meaning of the proposition, the sum of x and y is 2, and then a two-dimensional one-dimensional equation about xy x+y=2 can be listed, and then it is connected with the meta-equation system to form a ternary one-dimensional equation system about xym, and then the ternary one-dimensional equation system is solved, and the final result is x=2, y=0, m=4

1 due to 2x+y=-7

Therefore 2x=-y-7

Because x<0

Hence -y-7<0

Solution y>-7

According to parity.

Knowing y is an odd number.

Therefore y=-1, x=-3

y=-3,x=-2

y=-5,x=-1

24x-3y=15 y= (3x+x -15)/3= x-5+ 1/3 x

x=3 y=-1

x=-3 y=-9

x=6 y=3

1.Set up rainy days x days.

12x+(12-x)*18=204 x=22.Set a volleyball x yuan.

4*(3x)+5x=850 x=50 yuan Volleyball 3x=150 yuan Football.

3.The unit price of the table is 10x+4*(x+5)=540 x=260 7 table 260 7+5 chairs.

4.x (1000-x)* x=6 were damaged during handling

*18 = 216 (days) 216-204 = 12 (km) 12 divided by (18-12) = 2 (days).

4=12 (pcs) 12+5=17 (pcs) 850 17=50 (yuan) volleyball 50*3=150 (yuan) football.

5 = 20 (yuan) 540-20 = 520 (yuan) 520 (10 + 4) = 37 and 1/7 (table) 37 and 1/7 + 5 = 42 and 1/7 (chair) Personally, I think this question is wrong, and it may be 440 yuan.

Yuan) 1000*8+449=8449 8449 (8+) 1000-994=6 (pieces).

1.If there are x days of rain, then there are (12-x) days of sunny days.

12x+18(12-x)=204

2.Set a volleyball x yuan.

4*3+5）x=850

3.If the table is $x, the chair (x+5) is $.

10x+4(x+5)=540

4.Set broken x only.

1. (204-12 12) (18-12) = 10 days (sunny days) 12-10 = 2 days (rainy days).

(4 3 + 5) = 50 yuan (volleyball) 50 3 = 150 yuan (football) 3, (540-4 5) (10 + 4) = 26 7 yuan (is the price of the table) chair = 26 7 + 5

4. (1000 pcs.)