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Anonymous users2024-02-161. The truck catches up with the passenger car, which is exactly the tail of the car. then (250-180) (120-100) = seconds.
Walking in the opposite direction, it takes about 2 seconds to leave from the front to the rear of the car (250+180) (120+100).
2. It takes 8 seconds to get on a bridge, and 29 seconds to leave the bridge.
The front of the car actually walked on the bridge for 21 seconds. The train speed is 546 21 = 26 seconds meters.
The total length of the train is 26*8=208 meters.
546/(29-8)*8=208m。
3. A railway bridge is 1,000 meters long, and the time for the whole train to be completely on the bridge is 80 seconds.
Train speed: 1000 80 = m sec.
It was measured that the train took 120 seconds from the start of the bridge to the time it completely got off the bridge, and the time for the whole train to be completely on the bridge was 80 seconds.
Train length: meters.
4. 8=seconds.
124 Young Pioneers lined up in two columns, and there were 124 2-1 meters.
How long does it take for a team to get from the front of the line to the end of the line?
That is, the time from the time when the platoon is on the bridge to the time when the line is at the end of the line.
How much time does it take for the team to complete the length of the line plus the length of the bridge.
5. It takes seconds to miss all from the phase to the encounter, the length of train A is 300 meters, and the length of train B is 250 meters.
Then the sum of the speeds of the two cars is (300+250) m s.
Walk in the same direction, from catching up to missing all the seconds.
Then the speed difference between the two vehicles is (300+250) meters and seconds.
44-4 2=20 m-s 20+4=24m-s.
Inspection 24* meters.
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Anonymous users2024-02-15One. 1.A truck is 250 meters long and has a speed of 120 meters per second, and a passenger train is 180 meters long and has a speed of 100 meters per second.
If two trains are traveling in opposite directions, how long does it take to leave from the front of the train to the rear of the train?
120x-100x=250 gives x= (2) set x seconds.
120x+100x=250-180 gives x=43 22s2Let x m x 8 *29 = 546 + x get x = 192 m.
3.Let the length of the car be x meters and the speed will be y meters s
Equation 1000 + x = 120y
x=40y gives x=500m y=
4.The team length is 123*
The distance to be passed is 124+
Minute. 5.Let the velocities of A and B be x and y respectively
The system of equations gives x=27 y=23 (
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Anonymous users2024-02-141.(1) Set x seconds.
120x-100x=250 gives x=
2) Set x seconds.
120x+100x=250-180 gives x=43 22s2The length of the bridge is x meters.
x 8 * 29 = 546 + x gives x = 192 meters.
3.Let the length of the car be x meters and the speed will be y meters s
Equation 1000 + x = 120y
x=40y gives x=500m y=
4.The team length is 123*
The distance to be passed is 124+
Minute. 5.Let the velocities of A and B be x and y respectively
The system of equations gives x=27 y=23 (
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Anonymous users2024-02-131.(1) (250-180) (120-100) = seconds.
2) (250 + 180) (120 + 100) = 43 22 seconds.
26*8=208m
3.(120-80) 2+80=100 seconds.
1000/100=10m
10*（120-80）/2=200m
Name 62-1 = 61 61*
124+ points.
5.(300+250) msec).
(300+250) msec).
44+4) 2 24 (ms).
44-4) 2 20 (ms).
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Anonymous users2024-02-121) Because this is within 500 first (because no more than 500 yuan press 5 and then (3500-500) 15 (because more than 2000 yuan to 5000 yuan part of 15), so it is equal to 25 + 450 475 yuan.
2) 250-500 5 225 (this is within 500) 225 15 1500 (because this is 2000 to 5000 15), so 500 + 1500 2000
Hope it helps you o( o thank you.
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Anonymous users2024-02-11Suffice it to say that this is not an Olympiad question.
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Anonymous users2024-02-10And I would say that this is a super easy question, and it's definitely not an Olympiad.
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Anonymous users2024-02-09-2000=1500 yuan.
500 yuan in 1500 needs to be paid according to 1, the amount to be paid is 500 5% = 251500, and the remaining 1000 yuan needs to be paid according to 2, and the amount to be paid is 1000 10% = 100 yuan.
So he should pay $125.
Partially 500 5% = 25 yuan.
The 2nd part is 1500 10% = 150 yuan, so the 3 parts also need to pay 250-150-25 = 75 yuan.
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Anonymous users2024-02-08Divide by 5 and balance 1, buy 2 pieces for 3 yuan.
Divide by 5 and buy 4 pieces of 3 yuan.
Divide by 5 and 3, buy 1 piece for 3 yuan.
Divide by 5 and 4, buy 3 pieces for 3 yuan.
Divisible by 5, buy 0 sheets for 3 yuan.
15 to 64, 10 each of the above, so I bought 10 * (2 + 4 + 1 + 3) = 100 pieces of 3 yuan.
Bought 5 yuan: 1675 5 = 335 sheets.
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Anonymous users2024-02-07Starting from 15, try to go backwards, and you can get a certain pattern.
From this, it can be seen that the coefficient of 3 is a circular sequence of "0,2,4,1,3", that is, a total of (0+2+4+1+3)*10=100 pictures for 3 yuan were bought.
And the coefficient of 5 is "After that, it should be ......
It's also a group of five numbers, and there is.
335 sheets.
Is it a square of x or a square of x? Aren't there operators like parentheses?
1.Solution: Set up the original x people in the group, the time is t, and the total amount of the project is xtx+2) (t-2) = xt simplification: t-x-2 = 0 x-3) (t+6) = xt simplification: -t + 2x-6 = 0 + get: x=8 >>>More
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