C master, help! 5, C master, help!

If you're just thinking about using the least number of secondary storage units, it's not difficult, but I'll give you an example here

main()

int a[5]=;

int *p=a,m;

int i,j;

for(i=0;i<5;i++)

printf("%5d",a[i]);

printf("");

for(i=4,j=0;i>=5/2;i--,j++)m=p[i];p[i]=p[j];p[j]=m;}for(i=0;i<5;i++)

printf("%5d",a[i]);

Hope it helps.

d=a==b?++b:++c

Depending on the priority, this is an assignment statement.

i.e. d=? a==b?++b: ++c is a trinocular operation.

According to the change a, the value of b a==b is false, then execute ++c, that is, c=8;

Finally, d=8;

d=a==b?++b:++c

It's an assignment expression that I can't read.

First, ++b=4

b?++b:++c=4

It becomes d=a==4

I don't understand the back.

++, which takes precedence over +=, *=

y=18，z--=8，++y-z--=10；

x*=10, so x=x*10=1*10=10;

Then x+=10, x=x+10=10+10=20;

So the last value in parentheses is 20

x=20, and assign x to 20, so x=20

20 first calculate ++y-z--, to figure it out, ++y is to increase 1 first, and then calculate; z--is to participate in the operation first, and then subtract 1; ++y is 18 and z is 8; 18-8=10

Assignment operators *=, +=, -=, etc., the binding direction is from right to left, so first calculate x*=10 (just calculated 18), 10*1=10.

Then calculate x+=10 to get 20

x-square-3x+2>0, i.e. (x-1)(x-2)>0

ax square -3ax is greater than or equal to 0, that is, ax (x-3) is greater than or equal to 0

0=10+at

10=10t+(1/2）at²

Synopid 10 = 10t + (1 2) t * (-10) to get t = 2

Substituting yields a=-5

That is, the acceleration is -5 m s.

Set the time of 8 meters to be x

8=10x+（1/2）*（5）x²

That is, 5x -20x + 16 = 0

The solution is x=(10 2 5) 5

and t is up to 2

So x=(10-2 5) 5

Answer: The time it takes to glide 8 meters is (10-2 5) 5