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Choose C.
After the upper and lower squares of option a, according to the law of Lopida.
Belonging to infinity than infinity, it is equal to the negative x square of option 2 which obviously tends to 1, so that option c tends to be infinitesimal and therefore c.
In a process of change, the amount of change is called a variable (in mathematics, the variable is x, and y changes with the value of x), and some values do not change with the variable, we call them constants.
Argument. Function): A variable associated with a quantity in which any value can find a fixed value.
Dependent variable. Function): Varies with the change of the independent variable, and when the independent variable takes a unique value, the dependent variable (function) has and only a unique value corresponding to it.
Function value: In a function where y is x, x determines a value, y determines a value, and when x takes a, y is determined as b, and b is called the function value of a.
Geometric Meaning:
Functions are related to inequalities and equations (elementary functions.
Let the value of the function be equal to zero, and from a geometric point of view, the value of the corresponding independent variable is the abscissa of the intersection point of the image and the x-axis; From an algebraic point of view, the corresponding independent variable is the solution of the equation.
Also, put the expression of the function.
except for functions without expressions) with "=" with "<" or ">", and "y" with other algebraic formulas.
The function becomes an inequality and the range of the independent variables can be found.
The above content refers to: Encyclopedia - Functions.
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I think that after the upper and lower squares of the option, according to Lopida's rule, it belongs to infinity than infinity, which is equal to the negative x square of option 2 and obviously tends to 1, so that option c tends to be infinitesimal ......So how to look at it is also c.
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At x 0, sin(1 x) is a bounded quantity and xsin(1 x) is an infinitesimal quantity.
lim(1-x)/(1-x^2) = lim1/(1+x) = 1/2。
x 1, 1-x is an infinitesimal of 1-x 2.
Nature
1. An infinitesimal quantity is not a number, it is a variable.
2. Zero can be the only constant for infinitesimal quantities.
3. The infinitesimal quantity is related to the trend of the independent variable.
4. The sum of finite infinitesimal quantities is still infinitesimal quantities.
5. The product of a finite infinitesimal quantity is still an infinitesimal quantity.
6. The product of the bounded function and the infinitesimal quantity is the infinitesimal quantity.
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Pick D
An infinitesimal quantity can be simply understood as a quantity in which the expression tends to 0 when the independent variable tends to a fixed point or infinity.
Finding the left and right limits of x=0 is actually to substitute 0 into the original formula to calculate and see if a specific value can be obtained, of course, to ensure that the original formula is meaningful.
When x>0, f(x)=xsinx(1 x), and then substituting it to get f(x) at x=0, the right limit is 0.
When x<0, f(x)=5+x, and the left limit of f(x) at x=0 is 5.
Since the left and right limits are not equal at x=0, the f(x) limit of the function does not exist when x 0.
Property 1, infinitesimal quantity is not a number, it is a variable.
2. Zero can be the only constant for infinitesimal quantities.
3. The infinitesimal quantity is related to the trend of the independent variable.
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Summary. Hello, please send a question** so that it can be better answered for you.
When x approaches 0, the following variables are not infinitesimal.
Hello, please send a question** so that it can be better answered for you.
Six questions. The first limit is 0
To the process. What about the second question.
The first one is the first question, and the second question is two.
What about the third one. The third one is that you just go up and down Lopida.
It's infinity up and down.
Ask for a guide and bring 2 in.
Derivative -sina
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I guess because of the wrong format, everyone misunderstood Pei Liang.
a.is e x(x->0)=1
b.is sin(x) x,(x->0)=1
c.is (x-3) (x 2-9), (x->3) = 1 6dis ln(x+1), (x 0)=0, for infinitesimal quantities, so choose d, 2, I don't understand.
B, C definitely do. A, C can't read. ,2,Several important poles are disliked to the power of x = x+1 (x 0) of the grace a e
b sinx(x's silver0)=x
c x-3 (x→3)= y (y→0)
d ln(x+1)=x(x→0)
Therefore, bcd,2,b,c,0, and the following functions are infinitesimal in the specified change process.
x a e (x→0) b sinx(x→0) c x-3 (x→3) dln(x+1)(x→0)
x x2-9
x is the square and x is the molecular fraction. x2 is squared.
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When x approaches positive infinity, ln(1+x) becomes larger and larger, and x 2 (x+1)=x-1+1 (x+1) also tends to infinity. e x squared tends to positive infinity, so its reciprocal e -x 2 tends to 0, i.e., infinitesimal.
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For any crypto chain, there is always x=x
such that x- >0.
fx can be expressed as fx=a+ (x), then is the poor and small without chaos, where a is the limit where x approaches fx.
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In what change is the function y (x 1) (x 2) infinitesimal? In what process is it infinitely large?
Hello, dear <>
According to the question you provided, in what nucleus is the function y (x 1) (x Yunshi grandson2) an infinitesimal? In what process is it infinitely large? The following is found for you:
When x approaches -2, y approaches infinitesimal amount; When x approaches 1, y approaches an infinite mass.
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Summary. The function y (x 1) (x 2) is infinitesimal in the process of x approaching 1 and infinitesimal in the process of x approaching -2.
In what change is the function y (x 1) (x 2) infinitesimal? In what process is it infinitely large?
The function y (x 1) (x 2) is infinitesimal in the process of x approaching 1 and infinitesimal in the process of x approaching -2.
Because when x 1, y 0, when x -2, y.
Examine the concept of limits.
"Limit" is a fundamental concept of calculus, a branch of mathematics, and "limit" in a broad sense means "infinitely close and never reachable". The "limit" in mathematics refers to a certain variable in a function, which gradually approaches a certain definite value a in the process of eternal change of cavity impulse (or decreases) and "can never coincide to a" ("can never be equal to a, but taking equal to a" is enough to obtain high-precision calculation results), and the change of this variable is artificially defined as "always approaching without stopping", and it has a "tendency to constantly get extremely close to point a".
Limit is a description of a "state of change". The value a that this variable is always approaching is called the "limit value" of the trapped round silver (of course, it can also be represented by other symbols Wang Yan).
Shouldn't there be an approximation value for the limit?
Directly find the derivative, the first derivative is y=5 3x (2 3)-2 3x (-1 3), and then find the second derivative, we can see that at x=2 5, the first derivative is zero, and the second derivative is not zero, so x=2 5 is the extreme point. (Extremum second sufficient condition). >>>More
f(x)=y=sin(3x/4+3π/2)sin(3x/4+3π/2-2π)
sin(3x/4-π/2) >>>More
Solution: Defined domain of y=2x+1.
is r, and the range is r >>>More
Solution: (1) Because f(x)=xf(x), f(-x)=-xf(-x), so f(x) is not equal to f(-x), so the function is not an even function; f(-x)=-xf(-x), and -f(-x)=xf(-x), so f(-x) is not equal to -f(-x), so the function is not odd either. In summary, this function is not odd or even. >>>More