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Solution: Defined domain of y=2x+1.
is r, and the range is r
From y=2x+1, we get x=(y-1).
Swap x and y, then the inverse of y=2x+1 is obtained.
Be. y=(x-1)/2
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What was said upstairs seemed to be good.
My understanding: the function y=2x+1
is represented by x y; (y is equal to how much x).
The inverse function is.
x is represented by y. (solve, x is equal to how much y) at the end. Use.
x and. Replace each other with y.
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The inverse of the function y=2x+1 is y=(x-1) 2.
by y=2x+1
Get x=(y-1) 2
So the inverse of the original function is y=(x-1) 2.
Knowledge points: In general, let the range of the function y=f(x)(x a) be c, if you find a function g(y) where g(y) is equal to x, then the function x=
g(y)(y c) is called the inverse of the function y=f(x)(x a) and is denoted as y=f (-1)(x).
The inverse function y=f
x) and the domain are the domain and domain of the function y=f(x), respectively.
In general, if x corresponds to y with respect to some correspondence f(x), y=f(x), then the inverse function of y=f(x) is x=f
1(y)。The condition for the existence of an inverse function (a single-valued function by default) is that the original function must be one-to-one (not necessarily within the entire number field). Note: Superscript"−1"It doesn't mean power.
In calculus, f
n)(x) is used to refer to the nth differential of f.
If a function has an inverse function, the function is called invertible.
To put it simply, it is to swap y and x, for example, the inverse function of y=x+2 first uses y to represent x, that is, x=y-2, just change the positions of x and y, then y=x+2 inverse function is y=x-2.
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It reads as follows:y=2x-1。
2x=y+1。
x=(y+1)/2。
So it's the inverse function.
is y=(x+1) 2=x 2+1 2.
Definition: Nakai nucleus.
In general, let the function y=f(x)(x a) be in the range of values.
is c, according to the relationship between x and y in this function, x is represented by y, and x= g(y)If for any value of y in the inverse function of c, by x= g(y), x has a unique value in a that corresponds to it, then, x= g(y) means that y is the independent variable and x is the function of the dependent variable y, and such a function x= g(y)(y c) is called the inverse function of the function y=f(x)(x a), which is denoted as the domain of y=f (-1) (x) inverse function y=f (-1) (x).
The value range is the hole value range and the definition domain of the function y=f(x).
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The inverse of the function y=2x+1 is y=1 2x-1 2y=2x+1
2x=y-1
x=1/2y-1/2
So y=1 2x-1 2
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y=2x-1
y+1=2x
x=y/2+1/2
y=x/2+1/2
is the inverse function of y=2x-1.
y = 1/x
x is not equal to 0
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Solution: y=2x+1
x+1=log2y
i.e. x=log2y-1
Therefore, the inverse function of y=2x+1 is y=log2x-1, so the answer is: y=log2x-1(x 0).
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y-1=2x rock beat(1+2x)-1=-1 (1+2x)1+2x=-1 (y-1).
2x=-1/(y-1)-1=-y/(y-1)x=-y/(2y-2)
The inverse function of the Xun Zao Bridge is y=-x (2x-2), and x is not equal to 1
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Problem solving idea: from y 1 2 x 1+ 2 x, take y as a constant, find the imitation of x log 2 1 y 1+y, and then x,y are swapped, and the inverse function of the function y 1 2 x 1+ 2 x is y sell volt log 2 1 x 1+x ,x (-1,1).
y=1-2x
1+2x,y+y 2x=1-2x,y+1) 2x=1-y,2x=1-y1+y,x=log2
1-y1+y,x,y are swapped to get the function y=
The inverse function of 1-2x1+2x is y=log2
1-x1+x,x∈(-1,1).
So the answer is: y=log2
1-x1+x,x∈(-1,1).10,
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y=x^2+2x-1
y=(x+1)^2-2
x+1)^2=y+2
x+1=√(y+2)
x=√(y+2)-1
The counter-letter knows that Zheng Shu is y= (x+2)-1 before the nuclear Song
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y=x-2 x+1, the answer is as high as (x+1)y=x-2 at this time, x≠-1 gives xy+y=x-2
i.e. y+2=(1-y)x
i.e. x=(y+2) (1-y).
In other words, the inverse function of this group lifting with collapsed reed function is.
y=(x+2) (1-x) where x≠1
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Untie. y=2^x-1
The value range is: y> lift bend 1
y+1=2^x
x=log2(y+1)
Inverse functions. Answer for the noise: y=log2(x+1)(x>1).
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