Steps. Answer, answer!! Hurry, hurry

Let's start with the discussion. Both balls are completely submerged in water.

Still is. Partially submerged in water.

Suppose both balls are floating in water (partially submerged), then their gravity and buoyancy are in equilibrium. Because the gravity of the two balls is equal, but the buoyancy of the two balls is not equal, at least one of the two balls is completely submerged in the water and will not float in the same hailstone.

Assuming that both balls are completely submerged in water, the ratio of their buoyancy should be equal to their volume. P A: P B 3:2, so.

v A: v B =

2：3。Whereas.

fA: fB.

2:3, so both balls are not submerged in water at the same time.

Of the two balls, one is completely submerged and the other is partially submerged.

Suppose B is completely submerged and A is partially submerged. Then since v A:v B = 2:3, the maximum value of the buoyancy force experienced by A should be.

Less than. B is buoyant.

2/3。And the reality has been reached.

4 5, therefore.

The assumption is not true.

To sum up, A is completely submerged in water, and B is partially submerged in water.

Let the volume of B submerged in water be.

v'Second. Rule.

vA: v'Second.

fA: fB.

v'Second. 5 4) V A.

Therefore. v'B v

B = (5 4)v A].

3 2) vA].

According to the buoyancy balance conditions.

v'B beam limb sail. p water. v

B * p B. So. p B.

p. water*v'B v

B = 5 6) p water.

g cm 3

1. Because A2 is the proportional middle term of A1 and A4, there is (A2) 2=A1*A4, that is, (A1+D) 2=A1(A1+3D).

Simplify to get d(d-a1)=0, because d≠0, so d=a1

A1, A3, AK1, AK2, ,..akn，..Proportional series, a3 a1=(a1+2d) a1=3a1 guess the plexus a1=3, so a1, a3, ak1, ak2 ,..

akn，..It is a proportional series with a1 as the first term and 3 as the common ratio.

So AKN=A1*3 (N-1).

and an is the same spike letter cherry difference series, so akn=a1+(kn-1)d=a1*kn, so a1*kn=a1*3 (n-1).

i.e. kn=3 (n-1).

2, because ob vector = A1 times OA vector + A200 times OC vector, and ABC is collinear.

So there is a1 + a200 = 1

s200=(a1+a200)+(a2+a199)+.a100+a101)

and an is an equal difference series, so a1 + a200 = a2 + a199 = .a100+a101

So s200 = 100 (a1 + a200) = 100

3. The quadratic function f(x)=ax 2*bx+c??? Is there a mistake in the question?

Make use of the distribution function continuum and its definition.

Solution: Because 3/4y plus 12 and 5/3y minus 7-2 are inverse numbers, 3/4y plus 12 plus 5/3 minus 7-2 = 0

3/4y plus 12 plus 5/3 y minus 7-2 = 0

9/12y plus 12 plus 20y-7-2 = 0

29 out of 12 = -3

y = -36/29

Substitute y into the formula 3/4 y, plus 12 minus 12/29.

3/4 plus 12 minus 12/29

3/4 multiplied by -36/29 + 12-12/29

27/29 - 12/29 + 12

11-10/29

Since 3 4y+12 and 5 3y-7-2 3 4y+12+5 3y-7-2=0 (since a pair of opposite numbers adds to 0, we need to find the y value first and then bring the y value into the later algebraic formula).

The column equation 3 4y+12+5 3y-7-2=0 (note that 3 4y is 3y/4).

9 12y+12+20 12y-7-2=0 (3 4y and 5 3y are divided together, and the denominator can be added and subtracted into the same number).

9/12y+20/12y+12-9=0

29/12y+3=0

29/12y=-3

y=-3*29 12 (* is a division sign).

y=-3×12/29

y=-36/29

Now we substitute y=-36 29 into an algebraic formula.

Get: 3 4 (-36 29) +12-12 29

Take ln f(x)=x(ln10-lnx).

Derivative=ln10-1-lnx, let him =0

Extremum point x = 10 e

Proxy shooting stupid which into, should be the maximum value e (10 e) function image long code file like this:

The process should be detailed enough. See image above.

Solution: Original =

Then bring in the data.

r such as caution to call the picture chain Qi steps wide.

<>I hope Jian Shen is helpful to stop you, please pick socks and lead.

Indicates that there is no jump, means skipped, - means that there is no attempt at the height, each height can be tried up to 3 times, and the result of each athlete is the highest height jumped, and the highest score is ranked first; Cracks.

If the height of the jump is the same, the height of the comparison is the first time to pass the jump, and the first to pass is ranked first;

If it is the same, the total number of failures is compared, and the one with the lesser is ranked higher.

According to the above principles, it can be obtained:

a 4th place.

b 1st place.

c 5th place.

d 3rd place.

e 6th place.

f 2nd place is excellent.