When the motorcycle is moving on a horizontal plane, when turning, when the body is tilting

The so-called support force is a kind of stress (that is, this force only occurs when other forces appear).

The best way to judge the direction of the ground support force is to assume that the ground suddenly disappears and see that the car will fly towards **: obviously, the car in the loop will fly out diagonally down the car body under the action of gravity and centrifugal force. So the direction of the support force must be in the opposite direction, i.e. along the diagonal direction of the car body.

You use this support force and gravity to make a resultant force, and the resultant force should be horizontal and pointing towards the center of the circle. I don't know if I understand?

When turning, the driver is subjected to centrifugal force, which is proportional to the square of the vehicle's speed and inversely proportional to the radius of the turn. Therefore, the motorcycle should reduce its speed appropriately when turning, tilt its center of gravity inward, and keep it consistent with the body. This kind of turning posture in which the human body and the car body are inclined at the same angle is the most natural, stable and easy-to-grasp driving method.

When turning, there are no strict requirements for the posture of the occupants, and they can lean outward or inward, because the vehicle mainly relies on the driver to master the balance of the vehicle when driving.

To do a force analysis, the gravity is downward, the friction is backward, and the support force, where the gravity and support force cancel out a part, and the support force is greater than the gravity, so the friction and support force determine the change of direction.

The moving surface refers to the moving surface of the object rather than the ground, which provides support in the direction perpendicular to the stressed object (motorcycle). At this time, according to the parallelogram rule.

The combined force of support and gravity on the motorcycle points to the center of the circle.

The wheels are round, and even if they are tilted, they will not fall off as long as the power is still there (when rolling)!

The road surface is generally not horizontal when turning.

The centrifugal force generated by the motorcycle when it turned, and this centrifugal force must require the motorcycle body to tilt slightly inward so that it is not easy to tipp. And the car is not needed when turning, this is because the car has 4 wheels, and the body support of 4 wheels is very stable, but the motorcycle has 2 wheels, if you don't tilt the body and turn the faucet directly, the support is not enough, and it will fall.

The motorcycle tilts the body to turn, in order to maintain the balance of the motorcycle when turning, not tilting the body, the motorcycle under the action of centrifugal force, plus the speed of forwarding, although the front wheel of the motorcycle can be directly turned under the power of the handlebar, but the rear wheel of the motorcycle directly turns at a right angle, the body will be directly thrown over under the action of the rear wheel, at this time the people on the car will also be directly thrown out, the result is that the car and people are falling.

The motorcycle turns on a level surface.

There is a tendency to centrifugal movement with the ground.

At this time, the centripetal force keeps the motorcycle and does not fly out in the direction of the tangent line of the trajectory.

This centripetal force is the direction opposite to the relative motion towards the center of the circle.

It is also the static friction between the motorcycle and the ground to keep the car from flying out.

You can understand it this way.

If there is no static friction, the car will fly out under the centrifugal force (in the tangential direction of the trajectory).

So this static friction is where the Yinchang force that keeps the car from flying out is the centripetal force.

The kinetic friction force is consistent with the direction of motion, and it may be towards the center of the circle.

Actually, this sentence is not entirely true.

That's right, because the tires have no lateral displacement relative to the ground, i.e. there is no side slip. So, the force is static friction.

What's not right: when the motorcycle turns, the body will generally be tilted, and the weight of the bike and the rider can be used to provide a large centripetal force in order to turn normally. Otherwise, it's easy to roll over.

Because it doesn't slip sideways.

The horizontal turn should be centrifugal force.

The motorcycle that turns on the horizontal plane is bright and does a circular motion, and the motorcycle that does a circular motion is equipped with a movement trend that deviates from the center of the circle, and the static friction force points to the center of the circle, providing the centripetal force of the motorcycle to do a circular motion. f=mv^2/r