Dissolve 18 6 g of Na2CO3 mixture with NaOH in water 30

n（hcl）=

It happens that after the reaction, only NaCl is left in the solution, so N(Na)=N(Cl)= Let AmolNa2CO3, and Bmol NaOH then 2A+B=

106a+40b=

The solution is a= b=

i.e. Na2CO3, NaOH

Na2CO3 produces CO2 gas.

I hope it helps you, if you have any questions, please ask o( o haha

n（hcl）=m/m=

na2co3：

naoh：co2：

High school freshman, if there is a mistake, don't mind. Thanks for pointing it out.

Solution: Let the amount of Na2CO3 in the original substance be x, and the amount of NaOH in Y

So there is 106x+40y=

Because it is a complete reaction, Na+ and Cl- are conserved, and because the solute in the solution after the reaction is only NaCl

So n(na+)=n(cl-)=n(hcl)=so there is 2x+y=

The two-formula solution gives x=

y=, so n(naco3)=

n（naoh）=

2) From the reaction equation, n(na2CO3) = n(CO2) = hope to be obtained, thank you!

1) Just react, indicating that the sodium carbonate has all turned into gas carbon dioxide, then m (sodium carbonate) = hole suffocation 44 * 106 = grams.

2) Then m (sodium hydroxide) = 8 grams The amount of sodium is equal to the amount of chlorine in hydrochloric acid, so hydrochloric acid is altogether, and the mass of hydrochloric acid is divided into blocks =

3) The solute is sodium chloride, and the mass is grams, and the total mass of the solution is grams, so the mass fraction is denier.

To produce gas, yes, then there is sodium carbonate involved in the reaction, and the mass of consumption is.

Then the mass of sodium hydroxide is 8g i.e., the reaction is consumed.

Since it is put well in the complete reaction, the HCl involved in the reaction is, then the mass fraction of hydrochloric acid is.

<> third question, why can't the mass of NaOH found in 2 questions be used to calculate the mass fraction of sulfuric acid?

Yes, who's to say no?

2naoh+h2so4=na2so4+2h2ox

x = solute mass fraction of the dilute sulfur band plex used as an acid is.

I'm glad to answer your questions and wish you progress in your studies!

If you don't understand, you can ask! If you approve of me, please choose the satisfactory answer, thank you stupid Heng!

After the precipitation is filtered out, the clarified lime water is obtained?

What does this sentence mean, this question does not seem to have anything to do with clarifying lime water.

The solution obtained after the precipitation is filtered out is salt water (sodium chloride solution).

And from the point of view of the topic, it is a whole hundred. Obviously, the author of the question deliberately made it up, and the NaO2 reaction with water in the question releases oxygen, and the masses cannot be directly added. I'm afraid that nao2 in the title should be na2o. Thereafter, the answer will be made in accordance with the above corrections.

for the quality of the final solution.

The precipitate is Fe(OH) Fe(OH)3, i.e. Fe(OH)3. From the title "just complete reaction", it is known that all the Fe elements in Fe(OH)3 come from FeCl3 solution, so FeCl3 solution contains FeCl3. After removing the precipitation, all the chloride ions in the sodium chloride solution obtained are from the gram FeCl3 solution, so there are Cl ions, so there is NaCl, that is, the solute mass fraction of the solution obtained after removing the precipitation is Nian Ling.

The Na element in NaCl (i.e., all from a mixture of Na2O and NaOH. Therefore, the mass of sodium in the original mixture is trapped and the number of destruction is high =

Finally, it should be calcium carbonate and sodium hydroxide.

1) Let the mass of calcium oxide reacted with sodium carbonate be a, and the mass of sodium carbonate is x.

CAO + H2O + Na2CO3 = = 2NaOH + CaCO3 (precipitate).

a x56/18=a/2 18/106=2/x

a=56/9= x=

CaCO3g is generated

2) Sodium bicarbonate mass:

NaHCO3+CAO==NAOH+CAC3 (precipitation)3 B 84 74= 3 B

The solution yields b = caco3 g

3) Na2CO3 g and NaHCO3 3 g in the initial mixture are added to the mixture CAO: A+B=and.

In the post-reaction mixture: caCO3

Exactly with the hydrochloric acid to form NaCl, then the amount of the substance of the sodium type beam = the amount of the substance of hydrochloric acid = 200g

When the mixture is heated, both the sodium carbonate crystals and the sodium bicarbonate decompose to form sodium carbonate, so the final solid is sodium carbonate.

According to the conservation of sodium: the amount of sodium carbonate = 1 2 = 1 mol of the amount of sodium element

So solid mass (sodium carbonate) = 106g mol 1mol = 106g

A. Sodium bicarbonate reacts with sodium hydroxide in the solution to form sodium carbonate, combined with the image, it can be seen that there is no carbon dioxide gas generation at the beginning, then the solute in the dilute solution made is sodium carbonate and sodium hydroxide, then the OA section 0 25ml first occurs acid-base neutralization, the ion reaction equation of the reaction is H++OH- H2O, and then the sodium carbonate reacts with hydrochloric acid to form sodium bicarbonate and sodium chloride, and the ion reaction equation is CO3

2-+H+ HCO3, so a is correct;

B. According to the analysis of A, the solute at point A is sodium chloride and sodium bicarbonate, so B is correct;

c. Let the amounts of sodium carbonate, sodium bicarbonate and sodium hydroxide be x, y, and z respectively.

According to the conservation of carbon atom: x+y=1mol l (

According to the amount of Na2CO3 and NaOH and the amount of HCl consumed, it can be obtained: X+Z=1mol L

According to the total mass, it can be obtained: 84g mol?x+106g/mol?y+40g/mol?z=

The simultaneous solution gives x=, y=, z=, so the mass of NaOH is, so c is correct;

d. Combined with the image, it can be seen that when 35ml of hydrochloric acid is added, 25 35ml of sodium bicarbonate reacts with hydrochloric acid to form carbon dioxide gas, and the amount of substances that generate carbon dioxide is n, and the amount of acid consumed when generating gas is (35-25) 10-3l 1mol?l-1=, then.

hco3+h+═co2↑+h2o

n then n = , the volume of carbon dioxide under the standard condition is 224ml, so d is wrong;

Therefore, choose D

Na2O and Na2

The mixture of O2 is just neutralized by hydrochloric acid after being dissolved in water, and the solute fiber in the solution is NaCl, which is conserved by chloride ions N(NaCl)=N(HCl)=100g

n（nacl）=2n（na2

o）+2n（na2

O2, hence Na2

O and Na2

The amount of the substance of O2 is arbitrarily proportional, so D is chosen