Xiaoguang s fellow student installed 3 60W incandescent lamps, 1 40W TV, and 1 50W tape recorder

This question tests the rated power, and the electric energy meter can withstand 220*3w=660w. The fuse can withstand 220*.

The total power of electrical appliances in the home: 3*60w+40w+50w+180w+90w=540w, less than 550w can be afforded.

If you buy another 1000W air conditioner, the total power of 1540W is greater than 550W. Can't afford it. And greater than 660w

The energy meter and fuse with a higher power rating need to be replaced at the same time.

The data of your question is too old, how can there be a 220V, 3A electric energy meter now, and you can't use anything at home. It reminds me of the fuse in our dormitory when we were in college, and the computer had to burn out, which was really terrible.

P=(3x60+40+50+180+90)w=540w,p=ui=, electrical appliances can work at the same time.

2.No, replace the energy meter and fuse.

1. Yes. 2. Generally, the air conditioner at home is pulled separately, and you can also buy a meter and fuse with a large current.

1. Yes. The total current 2 is approximately equal to less than no, and the energy meter with a rated current of at least 7A and a fuse with a rated current of at least 7A are used.

By the way, can you label the current of your household appliances to only 4A?

Unchained car: Set up a tape recorder to infiltrate early x yuan.

8 Bush finch 75 + 2x = 1560

600+2x=1560

2x=1560-600

2x=960

x=465

The total power of 100 lamps of 60W is 6000W, and the electricity consumption in 4 hours is 6 kW 4 hours = 24 kWh (kWh);

If you use 100 40W fluorescent lamps instead, the total power is 4000W, and the electricity consumption for 4 hours is 4 kW 4 hours = 16 kWh (kWh);

According to 4 hours a day, the incandescent lamp consumes 8760 kWh (kWh) per year (365 days), and the fluorescent lamp consumes 5840 kWh (kWh) per year (365 days), and the plant saves 8760-5840=2920 kWh (kWh) of fluorescent lamps compared with incandescent lamps in a year. Word by word, word by word, ask for adoption.

One lamp can save electricity all year round:

q = (60w - 40w) *4h/d * 365d= 20w * 1460h

2920 wh

kWh = degrees.

Therefore, 100 lights can save electricity throughout the year: = kWh * 100 = 292 kWh = 292 degrees.

Ordinary bulbs:

60w＝w＝p×t＝

One year (365 days).

24kw·h×365=8760kw·h

Fluorescent lamp: 40w=

w=p×t=

One year (365 days).

365×16kw·h=5840kw·h

8760kw·h 5840kw·h=2920kw·h A: The school can save 2920 kWh of electricity in a year (365 days).

The total power of 100 lamps of 60W is 6000W, and the electricity consumption in 4 hours is 6 kW 4 hours = 24 kWh (kWh);

If you use 100 40W fluorescent lamps instead, the total power is 4000W, and the electricity consumption for 4 hours is 4 kW 4 hours = 16 kWh (kWh);

According to 4 hours a day, the incandescent lamp consumes 8760 kWh (kWh) per year (365 days), and the fluorescent lamp consumes 5840 kWh (kWh) per year (365 days), and the plant saves 8760-5840=2920 kWh (kWh) of fluorescent lamps compared with incandescent lamps in a year. If you are satisfied, please adopt, and it is even better to agree with me.

Total power of 100 60W bulbs: 60W*100=6000W=6KW100 40W bulbs Total power: 40W*100=4000W=4kw60W bulbs Daily power consumption:

6kw * 4h = 24 kWh = 24 degrees 40w bulb daily electricity consumption: 4kw * 4h = 16kwh = 16 degrees daily power saving: 24 degrees - 16 degrees = 8 degrees.

Electricity saved in one year: 8 kWh * 365 = 2920 kWh.

The original electricity consumption is: 100 lamps per day 60W 4h 24000Wh = degree), 24 365 days per year = ?. Daily electricity consumption after switching to fluorescent lamps:

100 40w 4h 1000=, electricity consumption per year 16 365=? The two are then subtracted to get the answer.

24-16=8, saving 8 kWh of electricity per day, can save 365*8=2920 kWh of electricity a year.

60w=

40w = 2920 kWh of electricity can be saved in a year.

The power consumed p = (40w) * (10) * (1 minute) = 400 (watts * minutes) = watts * hours) = kilowatts * hours burner surplus) = degrees, this skin roll has nothing to do with voltage.

(1600-800)÷10

The total price of 80 (RMB) table lamp is 1600 minus 800 RMB.

Answer: 1600-800=800, that is, 800 yuan for ten table lamps, 800 divided by 10=80, that is, 80 yuan for each lamp.

The first space: w=pt=(3*40+3*60+90)*5*3600=

The second empty: w month = the end of the month transport sensitivity =

The third space: w month next to the hall branch with =

Because household circuits are connected in parallel in the circuit, the voltage applied to the electrical appliances during operation remains unchanged, that is, their working current remains unchanged, so the trunk current will become larger after adding electrical appliances

Therefore, choose B