What is the wire diameter of 35 squares?

The diameter of the line of 35 square (mm) is: mm.

The calculation is as follows:

Cross-sectional area s = r = cross-sectional area, r radius, pi.

ddiameter) d= (4s) = (4 35 mm) <>

The diameter of the line can be calculated based on the cross-sectional area.

35 square is the diameter of the line, but the unit is: square millimeter, that is, 35mm 1Commonly used units of area:

1) Area unit refers to the unit of measuring the size of the surface of an object. The main ones are cm (square centimeter), dm (square decimeter), m (square meter) and so on.

2) 1cm (square centimeter) is about the size of the nail surface of a thumb;

3) 1dm (square decimeter) is about the face of the socket head, the size of the palm of the hand;

4) 1m (square meter) is about the size of the table top of a heating table or mahjong table.

2.Conversion between area units:

1) Area unit abbreviation (symbol) advance rate.

2) square millimeter m 100m = 1c

3) square centimeter c 100c = 1d

4) square decimeter d 100d = 1

5) Square meter 1000000 = 1k

6) square kilometers k 1k

7) Hectare H or HA 100H = 1500 mu = 1K 8) 1H = 10000

9) 1 acre = 100

10) 1 mu =

The cross-sectional area of 1 square wire is 1mm, and the diameter is about . The way to distinguish is to look at the cross-sectional area or cross-sectional diameter of the wire.

The square of the wire refers to the square millimeter, because the area radius , so the radius area . Namely:

Radius 1

Radius So diameter radius 2

Usually, the diameter of the wire is kept to two decimal places, so the diameter of the wire of 1 square mm is.

Chinese National StandardsWire load current value (partial) as specified in GBT

The allowable long-term load current of the square copper core wire is: 8A--12A2, the allowable long-term load current of the square copper core wire is: 12A--15A3, and the allowable long-term load current of the square copper core wire is:

The allowable long-term load current of 16A--25A square copper core wire is: 25A--32A square copper core wire allows long-term load current to be 32A--40ANote

The "squared" mentioned above refers to the "square millimeter".

What is the size of the line in 3*4mm square.

Dear, I'm glad to answer for you: the diameter of a wire of 3*4 square is millimeters. The cross-section of the wire is basically a circle, and the surface of the circle is the product of the field s= r =, r is the radius of the old trembling, d is the diameter) 4=, d = (4 mm) The general national standard is 4 square conductor diameter.

The cross-sectional area of the wire is measured by measuring its diameter with a vernier caliper or a spike ruler with a micrometer hole, calculated using the formula s=d 4. If the calculated value is within 5% of the nominal value, it should be considered acceptable.

The 35 square cable can withstand about 150A current.

The maximum current that the wire can withstand, depends on:

First, the wire is changed to the material of the gods, that is, its resistivity.

Second, the heat dissipation conditions of the wire itself, that is: bare wire or insulating layer of wire, whether it is a single strand of wrapping wire or multi-strand of wrapping wire (multi-core cable), the thickness of the insulation layer and the thermal conductivity of the nuclear loss.

3. The heat dissipation of the working environment of the wire, that is, whether it is ventilated, or buried, buried, or piped.

Fourth, the temperature of the environment.

5. The heat resistance level of the wire insulation layer.

Squared, 4 squared, 6 squared.

Conversion method: Know the square of the wire, calculate the radius of the wire to find the area of the circle.

The formula is calculated: the number of wires squared.

square millimeters) Pi.

The square of the wire radius in mm.

Knowing the square of the wire, calculate the wire diameter as well, for example: The wire diameter of the square wire is: =, and then square to get the millimeter, so the wire diameter of the square wire is: 2 mm mm.

Knowing the diameter of the wire, calculating the square of the wire is also calculated using the formula for finding the area of a circle: Square of the wire Pi (4 square of the diameter of the wire.

Summary. <>

Dear, hello, I'm glad to have your question about how thick is the outer diameter of a 35 square 5-core cable, and help you find the following answer: The outer diameter of a 35 square five-core cable is.

The outer diameter of the 35 square 5-core cable is thick.

Hello, I am glad that your question is how thick is the outer diameter of the 35 square 5-core cable, and the rotten help you find the following answer: The outer diameter of the 35 square five-core cable is.

Pro, 35 square five-core cable outer diameter.

Wire and cable products used to transmit electrical (magnetic) energy, information and realize electromagnetic energy conversion. The wire and electric limb cable in the broad sense is also referred to as the cable, and the cable in the narrow sense refers to the insulated cable, which can be defined as: a collection composed of the following parts; One or more insulated cores, as well as their respective cladding, total and outer sheath shields, and cables may also have additional uninsulated conductors.

The 35 square line is about a millimeter thick.

The diameter of a 35-square-meter wire is about millimeters, but this data is not fixed. The wires on the market are divided into many different types, and the size of different types of wires is different, and there will be some deviations.

The diameter of the line of 35 square (mm) is: mm, and the calculation method is as follows: cross-sectional area s= r = cross-sectional area, r radius, pi, d diameter, mm) The diameter of the line can be calculated according to the cross-sectional area.

35 square wires withstand current:

If it is a 35 square copper core cable, it can carry between 130 A and 150 A current.

If it is household electricity, the general voltage is 220 volts, so according to the power calculation formula, the power that 35 square copper wire can withstand is 33 kilowatts. If the voltage in a three-phase circuit is 380 volts, then the maximum power it can withstand is 57 kilowatts.

If it is a 35 square aluminum wire book, it can load between 90 amperes and 110 amps. If it is a single-phase circuit, the power that can be withstood is about kilowatts, and if it is a three-phase circuit, the power that can be withstood is about kilowatts. Posture <>

mm diameter = square root of area x2 = mm.

Square of the wire = pi (square of the diameter of the wire Square means that the size of the wire is 35 square millimeters, which is its cross-sectional area.

The calculation formula is: cross-sectional area (s) = square of radius (r) pie ( ) For example, a wire with a wire diameter of ( squared, so the diameter of a square wire is millimeters.