400 kilowatts distance 300 meters with how square lead cable

There are many types and specifications of wires and cables, and it is impossible to generalize. When choosing wires and cables, many factors should be considered, such as brand, category, specification, market, etc. Before choosing to buy, it is necessary to understand and compare in many aspects.

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Rated current: ip

If a voltage drop of 20V (rated voltage) is allowed between end wires and wires, the voltage drop is 10V per wire. Then:

Line resistance value of each wire:

r＝u/i＝10/759≈

The cross-section (resistivity) of each (copper core) wire (resistivity:

s＝ρ×l/r＝

Note: There is no 396 square cable, 400 square cable can be selected.

If we consider it in terms of the actual load (not the capacity of the device), and there is no capacitor reactive power compensation, the power factor cos = , and its current i = p 3ucos = 400 ( 3 1Cables are selected according to long-term continuous current (safe ampacity), PVC insulated PVC sheathed power cables can be selected, and the ambient temperature is +25°C, in the air.

According to the wire current comparison table, at least 240 square meters of copper core wire should be selected for 300kw load. The 240 square copper core wire is laid with a safe interception flow of about 570a.

300 kW power current calculation:

Three-phase: p=.

p: power; u: voltage; i: current; COS: Power factor, 1 for resistive load, and 1 for inductive (such as motor) load.

Root number 3=. i=p/(。

i=300/(

455a。<>

Cables include power cables, control cables, compensation cables, shielded cables, high-temperature cables, computer cables, signal cables, coaxial cables, fire-resistant cables, marine cables, mining cables, aluminum alloy cables, and so on. They are all composed of single or multiple strands of wire and insulation, which are used to connect electrical circuits, electrical appliances, etc.

The manufacturing of wires and cables is completely different from the way most electromechanical products are produced. Mechanical and electrical products are usually assembled into parts from another part, and multiple parts are then assembled into a single product, and the product is measured in units or pieces. Wires and cables are measured in terms of length.

All wires and cables are made from conductor processing, and insulation, shielding, cable-forming, and sheath are added layer by layer to the periphery of the conductor to make wire and cable products. The more complex the product structure, the more layers there are.

400 kilowatts require square millimeters.

of the dismantling and sale of cables. The calculation method is as follows: (take the electric motor as an example). According to the formula for calculating the power of three-phase alternating current.

p= 3uicosa (cosa is the power factor.

General value base sail; i=400000÷（；cable cross-sectional area s = 715 4 = square millimeters).

If it is three-phase 380V50Hz AC, the cable current density.

It is 4a mm, 400 kilowatts need a square millimeter cable. The calculation method is as follows: (take the electric motor as an example).

According to the formula for calculating the power of three-phase alternating current: p= 3uicosa (cosa is the power factor, which is generally taken.

i=400000÷（。

cable cross-sectional area s = 715 4 = square millimeters).

How many kilowatts can be loaded by 300 square cables, 300 square cables can be equipped with 570 thousand respectful watts of cable selection simple algorithm: including 10mm2) The wire below is multiplied by 5 by the cross-sectional area of the wire. 2.

The corresponding cross-sectional area of more than 100mm2 is multiplied by 2, 16mm mm2 multiplied by 4, 35mm mm2 multiplied by 3, 70mm mm2 multiplied by the coefficient if the wire passes through the pipe, multiplied by the coefficient used in high-temperature places, and the cross-sectional area of bare wire (such as overhead bare wire) is multiplied by the corresponding multiplier, and then multiplied by the cross-sectional area of the aluminum wire to calculate the copper wire upgrade calculation means that the current carrying capacity of the copper wire is equal to the current carrying capacity of the cracked aluminum wire, and so on. Conclusion: 300 square cable can carry 570 kilowatts, I hope it can help you.

Summary. Hello dear, according to the situation you described, in the three-phase five-wire distribution system with a total power of 300 kilowatts, it would be more appropriate to use 300 square copper wires and 800A switches. According to the power formula, p=have, i=p, equal to 300, equal to 537a.

It is calculated according to the three-phase power supply, the power number is, and then the corresponding cable is selected according to the current.

Hello dear, according to the historical situation you described, in the three-phase five-wire power distribution system with a total power of 300 kilowatts, it would be more appropriate to use 300 square copper wires and 800A switches. According to the power formula, p=have, i=p, equal to 300, equal to 537a. It is necessary to calculate according to the three-phase power supply or knowledge, and the power number is limb, and then the corresponding cable is selected according to the current.

How many kilowatts does 4*35+1*16 carry up to a maximum capacity.

Hello dear, according to the liquid condition you described, the copper core cable of 4*35+1*16 can carry 98 kilowatts. The current carrying capacity of aluminum-core cable is lower than that of copper-core cable, which is about 70% of that of copper cable. If the cable of 4*35+1*16 is an aluminum core cable, the rated load is about 42kw.

How much copper core wire does 300 kilowatts cost 4*?

Hello dear, according to the situation you described, the cable required for low-voltage three-phase four-wire power 300kw equipment: 1. The rated current should be more than 450A according to the data described in Gao Lachun, and the current carrying capacity of the cable should be 675A; 2. According to the ammeter, it can be known that the local flow rate of the 300 square millimeter cable of single Qi Naigen copper is about 670A, which can be selected; 3. According to the ammeter, it can be known that the current carrying capacity of a single aluminum 400 square millimeters is 630A, if the ambient temperature is more suitable, it can be selected; Otherwise, the square number of aluminum cables is increased by one grade, that is, 500 square millimeters.

Dear, hello, glad for your question, 400 kW with; The copper cable is 180 mm² and the aluminum cable is 240 mm². Calculation method: Calculated according to the three-phase alternating current power:

p= 3uicosa, and cosa is the power factor, which is the value. According to the cable ammeter, the copper cable is 180 square millimeters and the aluminum cable is 240 square millimeters. When selecting wires and cables, it is necessary to determine the safe current-carrying capacity according to the short-range heating situation, and the loss rate should also be considered according to its current-carrying capacity.

Then select within the appropriate operating voltage range. And it is necessary to select the appropriate wire or cable according to its maximum power, and consider the loss of electrical power and the subsequent construction environment. Dear, <>

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The 300 square cable can carry 570 kilowatts.

Simple algorithm for cable selection:

For wires below mm2 (including 10mm2), the current carrying capacity of the wire is multiplied by 5 by the cross-sectional area of the wire.

2. The corresponding cross-sectional area of more than 100mm2 is multiplied by 2,16mm mm2 multiplied by 4,35mm mm2 multiplied by 3,70mm mm2.

3. If the wire is multiplied by the coefficient and used in high-temperature places, the cross-sectional area of the bare wire (such as overhead bare wire) is multiplied by the corresponding multiplier and then multiplied by 2.

4. According to the calculation of the cross-sectional area of the aluminum wire, the upgrade calculation of the copper wire means that the current carrying capacity of the copper wire is equal to the current carrying capacity of the aluminum wire, and so on.