If it takes M days for Individual A to complete 1 project, then it takes Days for Person A B to comp

I think it is:

Everyone's productivity is 1 am (set the project to 1).

Working hours = engineering efficiency.

1/(a+b/am)

am/(a+b)

To demand the efficiency of each person per day, divide the unit 1 by the number of people and time. So it's 1 amIf nothing else, there is nothing wrong with this answer.

Everyone's productivity is 1 am (set the project to 1).

Working hours = engineering efficiency.

1/(a+b/am)

am/(a+b)

am is derived in fractional simplification.

Suppose (a+b) it will take X days for an individual to complete this project.

The number of people is inversely proportional to the number of days completed.

a*m=(a+b)*x

x=a*m/(a+b)

A It takes M days for an individual to complete 1 project.

then the efficiency of a person is m a

a+b) to complete the project individually.

(a+b)*m a is required

i.e. m+b am day !!

There are more b people, how can there be more b am days, it should be less than m days.

So I think there's something wrong with the topic.

am/a+b

Let everyone's productivity be x

The total productivity is ax

The total effort is equal to the productivity multiplied by the number of days worked.

Equal to AMX because everyone is equally productive.

So the person who adds b gets productivity, (a+b)x

So the work day is equal to the total amount of work divided by the work efficiency.

So the working date is equal to amx (a+b)x

Equal to am a+b

Let each person's productivity be x days, so the total amount of work is xab

Therefore, it will take y days for m individuals to complete.

Get xab=xym

So y=ab m

Answer: It takes AB M days for M individuals to complete this project.

Let the total amount of this project be n

You can find the average daily work efficiency of each person: n of a b = nn of ab (n * m of ab) = n of ab = mn of m = ab of m needs to be completed in ab days of m.

The original plan was to complete 1/1 a per day, but with the new method, 1 b+1 a per day can be completed, so it can be completed in 1 (1 b+1 a) days.

First seek the total amount of work to be ab, increase the number of x people as x+a, and then ask for time for filial piety, that is, ab a+x, so the answer is: ab a+x

According to the inscription, A completes 1 A per day, B completes 1 b per day, then A and B cooperate to complete 1 a+1 b, so the two cooperate and the number of days to complete is 1 (1 a+1 b).

Workload = a*m

Number of days completed = amount of work Number of people.

B individual am B day finished.

j solution: Let the total workload be 1

1 person works at 1 mA

1÷（b/ma）=ma/b

B individual ma b day completed.

If mg individuals need x days to complete, then according to the topic, get:

x=a*b/mg

That is, this project mg individual needs a*b mg days to complete.

If it takes (m+n) people m days to complete a project, then it takes (m+n) m days for one person to complete the project, then it takes (m+n) m n days for n people to complete it.

Number of days completed by one person (m+n)m

Number of days completed by n people (m+n) m n

Each person can complete: 1 (m+n)m, n people can complete :n (m+n)m per day, so the number of days required is: (m+n)m n