-
We know that the formula for the area of a circle is the radius multiplied by the radius multiplied by the pi, and the area is required to know the radius first, which can be found by the relationship between the perimeter and the diameter. The circumference of the circle is a multiple of the diameter, and the semicircle is 1 2 times, but the semicircle has an extra bottom edge equal to the diameter, so the circumference of the semicircle is equal to (1 2) + 1 = times the diameter.
The circumference of this semicircle is, the diameter is meters) The radius is 8 2 = 4 meters.
The area of the semicircle is half of the area of the circle, which goes without explanation, the area of the circle with a radius of 4 meters is 4 4 square meters) The area of the semicircle with the same radius is square meters.
I think I've made it clear, I don't know if you understand, you can ask if you don't know.
-
The circumference of the semicircle) + 2r (two radii).
r=4 (when =).
of squares = so the area of the semicircle should be.
-
Circumference = semicircular length + diameter = diameter * diameter.
Diameter = meters. Area = 4 * 4 * square meters.
-
Assuming the flowerbed radius is r, there is.
2r+r=4, then the area is Tong Xiaosen s=
square meters) Answer: The area is square meters column calculation.
square meters of bureau acres of cautious rent).
-
The circumference of the semicircular parterre = radius + 2 radius =
Radius = Radius =
The face of the semicircle is curved like a product =
-
Radius = meters.
Area = square meters.
-
The area of this semicircular parterre is square meters.
The calculation process is as follows:
According to the circumference of the semicircle = half of the circumference of the circle + diameter, the column equation is used to find the diameter, and then the area of the circle is calculated by using the area formula of the circle s= r2, and then the area of the semicircle is found.
The diameter of the circular flower bed is d meters.
d = 12 area is:
square meters) so the area of this semicircular parterre is square meters.
-
First find the radius by the perimeter, and then you can find the area.
Oh dear, wait a minute. When semi-circular flower beds.
In this way, the radius is calculated, and the area can be calculated.
-
Circumference of a semicircle = diameter + arc of a semicircle.
2r + 1/2)×2πr=2r + r=(2+π)r=
then r=6 meters.
s=(1/2)×πr²=(1/2)×
Square metre.
-
The circumference of the semicircle c vultures 2r
r c (v. 2).
6 (m) s 1 2 vl r 2
Square metre.
-
Let the radius of the semicircular parterre be r
The circumference of the semicircle c=2r+l (the length of the arc of the semicircle).
l semicircular arc = c circle 2 = 2 r 2 = r
Therefore: the circumference of the semicircle c=2r+ r= m.
Substitution. Then the radius of the semicircular flower bed: r=2
The area of the semicircular parterre s = the area of the circle 2= r*r 2 The area of the semicircular parterre s = square meters.
-
Radius = meters.
Area = square meters.
-
Because half c = r 2r
+2)r, so m (radius).
s=πr÷2
Square metre.
-
Let the radius be r, then the circumference of the semicircular flower bed is 2r + r=, so r = meters, so the area is.
r 2 2 = square meters).
-
Solution: Let the radius of this semicircular flower bed be x meters, then the area is square meters, then:
2x+x=6 means that the area is square meters.
-
The circumference of a semicircle is half of the diameter + circumference.
Let the radius x give 2x+ x=
This yields x = 6 area = r 2 = 18
-
Answer: Semi-circular area.
Unbend the song of the hail: r = 36
So: the radius of the circle r=6
So: parterre circumference = semi-circle circumference + diameter.
Rice. The circumference of the flower buried Hui Zheng altar is meters.
-
The area of the semicircle is s=1 2 r
r=6, so the radius of the flower bed r is 6 meters.
So the diameter of the flower bed d is 12 meters.
The circumference of the semicircular car cavity is 1 and the circumference of the closed car is 2 d+d=m.
A: The circumference of this flower bed is meters.
Square area = side length x side length.
Because 36 = 6x6 >>>More
According to your conditions, the length and width of a standard basketball court are 28 meters and 15 meters wider, respectively.
The circumference of a rectangle is 208 cm, and the ratio of its length to width is 4 5 1 2. Find its area? >>>More
10 4 = decimeter The circumference of a square is known, and the perimeter of the square is divided by 4 >>>More
Inner Diameter:
Inner radius 10 2 = 5cm >>>More