The sum of 4 consecutive even numbers is 316, where the largest is an even number, and what is the l

First, divide 316 by 4 to get 79, which means that the middle number of these 4 consecutive even numbers is 79, so these four numbers are the two consecutive even numbers in front of 79, namely: 78 and 76;

and two consecutive even numbers after 79, i.e., 80 and 82;

Check it, add 76, 78, 80, 82, these four consecutive even numbers, the result = 316, which is in line with the title.

Thus the four consecutive even numbers are 76, 78, 80, 82, and the largest even number is 82.

Let the 4 even numbers be n, n+2, n+4, n+6 (n is an even number), and add them to obtain:

4n+12=316

4n=316-12=304

n=76, and the maximum even number is 76+6=82

The maximum even number is 82.

4x+12=316

Solving the equation gives x=76, so the maximum even number is x+6=76+6=82

316-2-4-6 304,304 4 76, and the smallest even number is 76,76 2 102 2 82. The maximum even number is 82.

Solution: Let the largest even number be x

From the problem, we can see that x+x-2+x-4+x-6=316 solves the equation to get x=82

So the largest even number of them is 82

The problem uses the knowledge that the difference between adjacent even numbers is 2).

Inverse calculation according to the trapezoidal area formula (top bottom + bottom bottom) x height 2 = area:

316÷4x2=79x2=158

The maximum number is 82

This is the average.

The middle 2 of the 4 even numbers are 78 and 80. The largest is 82 and the smallest is 76

54 divided by 3 equals 18, 18 minus 2 equals 16, 18 plus 2 equals 20, these 3 numbers are 16, 18, 20

The three Min brothers, Ma Hui, are consecutive even numbers n-2, n, n+2

3n-26=n+2

2n=28n=14

The number of objects attacked by three consecutive even bridges is 12, 14, and 16

The three even numbers are: 12, 14, 16

Equation: Let the three even numbers be x-2, x, x+2

x-2)+x+(x+2)=42

3x=42x=14

x-2=12

x+2=16

The three even numbers are 12, 14, 16

solution, let the smallest even number be x, then the second even number is x+2 and the third is x+4.

x+（x+2）+（x+4）= 42

3x+6 = 42

3x = 42-6

3x = 36

x = 12

x+2=14 x+2+2=16

Answer: The three even numbers are 12, 14, and 16.

There is also an arithmetic method, 42 3 = 14 (This results in the middle number.) Then the smallest is 14-2=12 The largest is 14+2=16 Answer: The three even numbers are 12, 14 and 16.

The most important point: give it to me, do it very seriously...

Solution: Let the first number be x, the second number be x+2, and the third number be x+4

x+x+2+x+4=42

3x+6=42

3x=36x=12

x=12 x+2=14 x+4=16

Answer: The three numbers are: 12, 14, 16

Let the first even number be n, then the following even numbers are n+2, n+4, n+6, so n+n+2+n+4+n+6=324

Solve n=78

So, these four even numbers are .

324÷4=81，81-1=80，80-2=78，80+2=82，82+2=84

Answer: The four consecutive even numbers are 78, 80, 82, 84

The sum of three consecutive even numbers is 42 greater than the smallest of them

The largest even number is 42-2=40, the middle one is 40-2=38, and the smallest is 38-2=36

Let the maximum even number be 2n, then the four consecutive even numbers are .

2n-6), (2n-4), (2n-2) and 2n, from the title.

2n-6)+(2n-4)+(2n-2)+2n=2848n-12=284

8n=296

n=37 Then, 2*37=74, so, the maximum even number is 74.

The average of four consecutive even numbers is in between.

Between the second and third, it is 1 larger than the second, 1 smaller than the third, and the maximum is 3 larger than the average

Let the largest even number be the co-cleft x, then the first three reed return even numbers are x-2, x-4, and x-6 respectively. The state of the world.

x-2+x-4+x-6+x=1764

4x=1776

x=444