A and B go to buy watermelon, A is six yuan, B is four yuan, how many dollars is a watermelon?

Updated on society 2024-08-09
7 answers
  1. Anonymous users2024-02-15

    A and B went to buy watermelon, A was six yuan short of four yuan, B was four yuan, one yuan was missing, and watermelon was 9 yuan.

    According to the meaning of the title, you can list the sub:

    A + 6 = B + 4 = A + B + 1

    A = 3 yuan. B = 5 yuan.

    Watermelon amount: 3 + 5 + 1 = 9 yuan.

    So watermelon 9 yuan.

  2. Anonymous users2024-02-14

    A + 6 = B + 4 = A + B + 1

    A = 3 yuan. B = 5 yuan.

    3+5+1=9 yuan.

    Watermelon 9 yuan.

  3. Anonymous users2024-02-13

    6+4-1=9 yuan is a very simple column calculation.

  4. Anonymous users2024-02-12

    9 yuan. Let this watermelon** be x yuan with a title A has (x-6) yuan, B has (x-4) yuan (x-6) + (x-4) + 1=x 2x-9=x solution, x=9, this watermelon is 9 yuan.

    The key to solving the problem is to find out the quantity in the problem and the corresponding fraction. Ways to think about solving such problems:

    1. Analytical method: The analytical method is a thinking method that starts from the problem sought in the question and gradually finds out the known conditions necessary for the problem to be solved.

    2. Comprehensive method: The comprehensive method is a thinking method that starts from the known conditions in the topic and gradually deduces the problem to be solved.

    3. Decomposition method: Break down a complex application problem into several basic application problems, and find clues to solve the problem.

    A unary equation is one that contains only one unknown, the highest order of the unknown, and both sides are integers. Unary linear equations have only one root. The unary equation can solve most of the engineering problems, travel problems, distribution problems, profit and loss problems, integral table problems, billing problems, and number problems.

    In a univariate equation, the denominator step is usually multiplied by the least common multiple of each denominator, and if the denominator is a fraction, it can be multiplied by the reciprocal of the fraction on the denominator for the other parts of the term.

  5. Anonymous users2024-02-11

    Let this watermelon** be $x.

    There is a title to be obtained.

    A has (x-6) yuan, and B has (x-4) yuan.

    x-6)+(x-4)+1=x

    2x-9=x

    solution, x=9

    Answer: This watermelon costs 9 yuan.

  6. Anonymous users2024-02-10

    9 yuan. Let this watermelon** be x yuan with a title A has (x-6) yuan, B has (x-4) yuan (x-6) + (x-4) + 1=x 2x-9=x solution, x=9, this watermelon is 9 yuan.

  7. Anonymous users2024-02-09

    Let A have x yuan and B have y yuan, then.

    x+6=x+y+1

    y+4=x+y+1

    Solution. x=3 (yuan).

    y=5 (yuan).

    This watermelon

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