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A and B meet 80 away from place A, when they meet again, A walks 80*2=160, and place B is 80-60=100 away from the first meeting point: 160-60=100
So ab is far apart: 100 + 80 = 180
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A and B are 80 kilometers away from B when they meet, and when they meet again, A walks another 160 kilometers, and B is 160-60 = 100 from the first meeting point, so AB is 100 + 80 = 180It should be right, hehe!
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If they go in the opposite direction, after x hours, the two of them are 20 kilometers apart.
40+20)x+20=140
Solution x = 2 hours.
If you go in the same direction, after x hours, the two people will be bridged and the Wang will be 20 kilometers apart, 40-20) x + 20 = 140
The solution is x = 6 hours, 4, A and B are 140 kilometers apart, and A and B are starting at the same time.
A and B set off at the same time from AB, which are 140 kilometers apart, and A's speed is 40 kilometers per hour, and B's speed is 20 kilometers per hour.
1) If you go in the opposite direction, how many hours will it take, and how many hours will the two people be 20 kilometers apart, and if you go in the same direction, how many hours will the two people be 20 kilometers apart, and solve the problem with a one-dimensional equation).
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A speed of 70 meters per minute.
B's speed is 80 meters per minute.
Then, when A and B meet, after 600 (70+80)=4 minutes, the dog's speed is 400 meters per minute.
So the dog ran a total of 400*4=1600 meters.
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1. Set up a hidden to do B to set off x hours after meeting and teasing, 6 (solution, x=17 Shan Zheng 14 hours.
2. Set X hours after B catches up with A, solve with relative velocity, 8x-6x=20x=10 hours.
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Let the velocity of the scattered car A be x (kilometers of hours) and the speed of B be y (kilometers of hours), and the equation is as follows:
90/x)*y=75
90/x)+(2/3)=(90/y)
Solve the equation to obtain: x=27, y=
That is, A travels 27 kilometers per hour.
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Let the two meet after q hours, and the two meet after Q=m (x+y)m (x+y) hours according to the title.
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Solution: If the speed of Pei B is x kilometers, then the speed of A is 3x kilometers.
10/x-10/3x=20
30-10=60x
60x=20
x=1 3Then, A's velocity is: 3 1 3=1 km Split and sell to get points.
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Solution: After setting x hours, the two people are 40 kilometers apart.
40x+30x=60-40
70x=20
x = 2/7
The two are 40 kilometers apart in two-sevenths of an hour.
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1 did not meet 60-40=20
20 (40+30) = 2 7 hours.
2 After the encounter 60+40=100
100 70=10 7 hours.
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