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1-3 5x=5 8 is solved so that x is equal to.
Analysis: 1-3 5x=5 8
Solution: 3 5x=1-5 8 - minus = subtracted - difference.
3/5x=3/8
x=3 8 3 5 – one factor = product of another factor.
x=5/8
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The shift sorting can be obtained, 1-5 8=3x 5, that is, 3x 5=3 8, and the solution is x=3 8 5 3=5 8.
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The process of solving the problem is as follows:
1-(3/5)x=5/8
3/5)x=3/8
x=5 8 solves x equals 5 8.
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After solving the original equation, the shifted term is:
3/5x=3/8
Both sides of the equation are multiplied by 40x at the same time, and the original equation is 15x=24x=24 15=8 5
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x-1 3x =3 5x+1 Solve the equation x-1 3x =3 5x+1 Solve the equation x-1 3x =3 5x+1 Solve the equation x-1 3x =3 5x+1 Solve the equation x-1 3x =3 5x+1x-1 3x-3 5x=1x 15=1x=15
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Solution: (5x-1) Attack trap = 3 (5x-1).
5x-1)²-3(5x-1)=0
5x-1)(5x-1-3)=0
5x-1)(5x-4)=0
5x-1=0 or 5x-4=0
x=1 5 or mindfulness x=4 meditation 5
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<> wanton hand is a crack and a crack is a thank you.
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Solution: The equation is 3(x -1) = 5x, and it is reduced to 3x -5x-3 = 0, and we get:
x=(5±√61)/6
Please refer to it. <>
Expressions of variables and constants through arithmetic, trigonometric operations, exponential operations, and logarithmic operations are known as analytic functions.
The combination of analytic functions and integrals, the concept of functions has been changed, so that the category of functions has been expanded from analytic functions to geometric functions. Curves in geometry are divided into 3 categories:
The first category can be defined in terms of a sentence indicating the nature of the curve or an equation indicating the nature of the curve; For example, the nature of a circle, the distance from any point on the curve to a certain point is constant;
The second type of curve, which cannot be expressed in a sentence or an equation;
The third type of curve is a curve consisting of two or more curves of the first type.
Of the three types of curves mentioned above, the first type can always be represented by an analytic expression y=f(x) or f(x,y)=0, while the rest of the curves cannot be represented by an analytic formula. Therefore, the analytic expression representing the first type of curve is considered to be a continuous or true function, and the rest of the functions are pseudofunctions.
In this context, there are some understandings of functions:
A function defined by a continuous curve is still a continuous function, and must be a true function;
By splitting a discontinuous curve or polyline into two or more curves or polylines, it is impossible to establish a set of multiple functions, which can never be expressed by an analytic formula. Therefore, "can it be represented by only one formula" is used to distinguish between true functions and pseudofunctions;
If the values of the two functions on the interval [a,b] are equal, then the values of the functions other than [a,b] are also equal;
Only periodic curves can be represented by periodic functions of the trigonometric class.
In fact, almost all of the above perceptions are wrong! Any curve can be represented by a periodic function; An equation can be used to represent discontinuous lines; Just because two functions are identant over an interval does not mean that they are also equal outside the interval.
It can be seen that the discontinuity can be represented by either one formula or multiple formulas.
Not only the periodic function, but also the arbitrary continuous function f(x), in the -
Mathematicians have found examples where the same line can be represented by one expression or by more than two expressions.
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Here's how, please refer to:
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Untie. 3(x^2-1)=5
Divide by 3 x 2-1 = 5 3 on both sides
+1x 2 = 8 3 on both sides
Square on both sides. x=√24/3 or -√24/3
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How to solve 1 4 -1 5 (48-x) = 3.
1 4x 48 5+1 5x 3
9/20x-48/5=3
9 20x 3+48 5 of repentance
9/20x=63/9=7
x=7*20/9
x=140/9
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To solve the equation, it is necessary to pay attention to the process and method of solving the problem, and to test it if necessary.
5x+2x6=47
Solution: 5x=35x=7
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lim(x→5)
x|x is around x=5, |x|is equal to x
limx→5x/x
lim(x→5)
x-5|X-5 depends on the left and right limits.
lim(x→5-)
x-5|/x-5
It means that from the side less than 5 to 5, you can see |x-5|=-x-5)=lim(x→5-)
x-5)/x-5
lim(x→5+)
x-5|/x-5
It means that 5 is approaching from a direction greater than 5, and you can see |x-5|=(x-5)=lim(x→5-)
x-5)/x-5
The left and right limits are not equal, then lim(x 5).
x-5|The X-5 limit does not exist.
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Vertical parsing steps.
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