The inverse ratio of squares is related to the photon mass being zero 10

Updated on science 2024-08-07
10 answers
  1. Anonymous users2024-02-15

    Is there a deviation in the inverse square law? That is, whether the exponent of r must be equal to 2, this is the problem that scientists are concerned about, if there is a deviation in the inverse square ratio of Coulomb's law, it will theoretically lead to the stationary mass of the photon is not zero, so that the speed of light in the vacuum is variable (vacuum scattering), the blackbody radiation formula should be modified, and the charge is not conserved, so that it will shake the foundation of electromagnetism and even the entire edifice of physics, for hundreds of years, with the emergence of precision instruments and the improvement of experimental technology, and through the efforts of many scientists, the distance index has reached 2+3 10-16 accuracy. Although the accuracy is very high, whether it is strictly equal to 2 is still of general concern to physicists, and will be further tested, if the index of gravitation is biased, it will cause the Gaussian theorem of the force field to not be true, gravity is not a conservative force, can not introduce the concept of potential energy and a series of problems, is contrary to the knowledge we have learned, these basic physical laws are destroyed of course impossible to imagine.

    For example, if someone now declares that the exponent of r is slightly larger or smaller than 2, even slightly, physics may be revised.

  2. Anonymous users2024-02-14

    The intensity of light always squares with increasing distance, and there is no local termination. It is proved that there is no minimum unit of mass for light, i.e., the photon mass is 0

  3. Anonymous users2024-02-13

    Since a photon cannot be stationary, it does not have a rest mass, and the mass here is the relativistic mass of the photon.

    The rest mass of a photon is strictly zero, which is essentially equivalent to Coulomb's law, which is strictly inversely proportional to the square of the distance, and if the static mass of the photon is not zero, then Coulomb's law is not strictly inversely proportional to the square. All relevant classical theories, such as Maxwell's equations and the Lagrangian quantities of electromagnetic fields, rely on the assumption that the static mass of photons is strictly zero. From Einstein's mass-energy relationship and the equation of light quantum energy, the upper limit of the photon mass can be roughly obtained:

    m=hv/c^2

    The calculation method is as follows: First, since the energy of a photon with frequency v is e=hv, its mass can be obtained from the mass-energy formula: m=e c 2=hv c 2

    where c 2 is the square of the speed of light).

    The energy and momentum of a photon are only related to the frequency of the photon; Or rather, it's just about wavelength. Thus the magnitude of the momentum of the photon is p=h =hv c

  4. Anonymous users2024-02-12

    Photons do not have a rest mass but have a moving mass.

  5. Anonymous users2024-02-11

    It can only be said that the rules of the microcosm are different from the macro.

  6. Anonymous users2024-02-10

    Photons have a motion mass, which is generally not examined in the exam, and its momentum can be solved by the formula p=h. h is Planck's constant, which is the wavelength of light at that frequency.

  7. Anonymous users2024-02-09

    Photons have no mass, where mass refers to static mass. There is also a moving mass, which is commonly referred to as a type of energy. For example, when an electron is in the middle of the other, it produces photons.

    It's a manifestation of energy. It has kinetic mass, so it has momentum.

  8. Anonymous users2024-02-08

    First of all, this statement is not accurate, the photon does not have a resting mass but has a moving mass, and the moving mass can be expressed by energy (e=m*c 3), in fact, after you learn the wave-particle duality of light, you know that the energy of the photon is its frequency multiplied by Planck's constant, and the momentum is equal to Planck's constant divided by the wavelength.

  9. Anonymous users2024-02-07

    2 Any ray of light moves at a definite velocity c in a "stationary" coordinate system, regardless of whether the ray is emitted by a stationary or moving object. ”

  10. Anonymous users2024-02-06

    Life is endless, and movement is endless.

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