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If two circles intersect at the points a(1,3) and b(m,-1), and the centers of the two circles are on the line x-y+c=0, what is the value of m+c? To write out the detailed process!!

Solution: From the meaning of the question, it can be seen that the straight line ab is perpendicular to the straight line x-y+c=0, and the solution can be m=5, then the perpendicular line of the line segment ab is x-y+c=0

The solution yields c = -2

then m+c=3

Therefore, the value of m+c is 3

Recommended to you "Mathematical World".

I recommend you a book.

From surprise to thought--- Wonders of Mathematical Paradoxes" is where you can definitely find the answer.

Let a = 2 to the power of -1 + 2 to the power of -2 + 2 to the power of -3 + 2 to the power of -4 + .2 to the power of -100.

Let b = 2 to the power of -1 a

2 to the power of -2 + 2 to the power of -3 + 2 to the power of -4 +...2 to the power of -101.

a-b = (1 - 2 to the power of -1) a = a 2 = 2 to the power of -1 - 2 to the power of -101 = (2 to the power of 100 - 1) 2 to the power of 101.

i.e.: a 2 = (2 to the 100th power - 1) 2 to the 101st power so a = 1-1 2 to the 100th power.

Imagine a piece of paper and tear it in half (i.e., tear off 2 to the -1st power).

Then tear off half of the remaining half of the paper (that is, tear off 2 to the power of -2).

When the number of tears increases.

The torn part will get closer and closer to a piece of paper (i.e., 1).

Proportional series. This will not be asked?

sn=a1(1-q^n)/(1-q)

2^(-1)(1-2^(-n))/(1-2^(-1))=1-2^(-n)

When n tends to infinity, sn=1

Approach 1 process: according to the equation of the proportional sequence of summation sn=a1(1-q n) (1-q)a1=1 2 q=1 2

So sn=1-q n

When n increases infinitely, q n infinity approaches 0

So the SN is getting closer and closer to 1

<> work backwards based on the answers.

The original formula can be factored into the form of (p 2 + ap + b) (p 2 + cp + d), where a = x1 + x2, c = x3 + x4, it can be clearly seen that these two are not rational numbers, especially difficult to solve (I guess that the specific values of these four roots may have the possibility of a root number in the root number).

x^2+y^2-x-3=0

x-1/2)^2+y^2=13/4

Yuanxin Tong Sleepy Zen (1 2, 0).

Substituting is to find the distance from the point to the line compared to the radius.

Your straight-line ruler equation should be wrong.

5 times any number of single digits that is non-zero, i.e. 5

From the result ten digits 0 to know which of the 6 is 4, then the first three digits can only be 9, and the result hundred digit 9 knows that the one above it is 3 (because the following digit is also carried 1), so the first two digits are 45

And because the result is that the number of 10,000 digits is only 1, the first three digits and hundreds can only be 3, so it is 309 times 45 = 13905